/sci/ - Science & Math

[Anonymous No.3164891]

Hey /sci/ can you help me find the reactants for this redox titration?

KMnO4 (aq) + Fe(NH4)2(SO4)2 (aq)

[Anonymous No.3164905]

have you tried reading the guide in the stickied post?

[Anonymous No.3164907]

>amazingly hot chick
>insta-erection
>never a miscommunication

You can't explain that!

[Anonymous No.3164923]

OP, what does permanganate do?

[Anonymous No.3164925]

>>3164905
I did, but I couldn't find a solution with any of the links.

I know there should be a transfer of charge between two of the ions, but they never gave us the products, just said to "research the reaction"

[Anonymous No.3164938]

Ps. What is the point of a titration?

[Anonymous No.3164940]

>>3164923
Not sure exactly. I managed to find this reaction:

KMnO4 (aq) + Fe(NH4)2(SO4)2 (aq) --> FeMnO4 (aq) + K(NH4)2(SO4)2 (aq)

But K(NH4)2(SO4)2 can't be as the charge on the K would have to be +2

In that case, either NH4 or SO4 would have to be reduced? Help me please I'm a total chemistry klutz..

[Anonymous No.3164954]

>>3164938
OP here,

Point of a titration is to find the concentration of an acid or a base. In this case it should be used to find the concentration of the salt solution ferrous ammonium sulfate

[Anonymous No.3164986]

From my point of view the the reaction would simply be this:

2KMnO4 + Fe(NH4)2(SO4)2 -> K2(NH4)2(SO4)2 + Fe(MnO4)2

neither Fe+2 or MnO4-1 change charge...

[Anonymous No.3164989]

OP here,

bump for help cause this lab is due tomorrow

[Anonymous No.3165008]

>>3164986

If no electrons are transferred, it won't be a redox reaction.

KMnO4 is an oxidizer. Fe is in the +2 state now, but can be oxidized to +3.

[Anonymous No.3165022]

>randomly rearrange things for fun, i can do this

2KMnO4 + Fe(NH4)2(SO4)2 = 2KSO4 + Fe(NH4)2(MnO4)2

[Anonymous No.3165051]

>>3165008
Interesting. I kinda know what you mean, but not sure what to say.