[ 3 / biz / cgl / ck / diy / fa / ic / jp / lit / sci / vr / vt ] [ index / top / reports ] [ become a patron ] [ status ]
2023-11: Warosu is now out of extended maintenance.

/sci/ - Science & Math

View post   
File: 183 KB, 684x359, 129580349491.jpg [View same] [iqdb] [saucenao] [google]
3114880 No.3114880[DELETED]  [Reply] [Original]

I'm quite sure my teacher gave the wrong answer regarding this and I'm asking you guys just to make sure (because I'm slightly confused now).

So, what's partial derivate for x from function
x (times) y - (1/2)x - (3/4)y?

I'll remove the thread as soon as I get a legitimate answer.

>> No.3114890

ans: y - 1/2

>> No.3114895
File: 132 KB, 686x686, Thisiscorrect.jpg [View same] [iqdb] [saucenao] [google]
3114895

>>3114890

>> No.3114901

>>3114890
OK thanks.
Can I ask you how you got that?
Please explain in retard terms so even I can understand.

>> No.3114917

>>3114901
diff: xy - x/2 - 3y/4

the xy goes to just y
the x/2 changes to 1/2
and seeing as the 3y/4 term doesn't have an x in it, you can just ignore it.
so it goes to y - 1/2

>> No.3114918

>>3114901
f'(x) = (x*y - x/2 - 3y/4)'

in this equation simply consider 'y' as a constant (as if it was any actual number, like - 69).

(3y/4)' = 0,
(x/2)' = { derivate of a power function or simply of linear } = 1/2,
and xy the same way.

sum it all up - tada

>> No.3114939
File: 24 KB, 555x325, 130386092093.jpg [View same] [iqdb] [saucenao] [google]
3114939

>>3114917
>>3114918
Okay I got this shit now.
Thanks.

>> No.3114941

>>3114880
>I'll remove the thread as soon as I get a legitimate answer.