/sci/ - Science & Math

[Anonymous No.3040014]

. An aeroplane is travelling at 750kmhr-1 at 3km height. It encounters some turbulence, and drops in free fall for 2.5s. This process causes it to slow down to 700kmhr-1. Find:The deceleration of the aeroplane.
and
The height of the plane after the turbulence.

[Anonymous No.3040022]

-1 near kmhr mean kmhr^-1 ^.^

[Anonymous No.3040028]

>The height of the plane after the turbulence.
Depends on the plane. Jumbo jets are 3 meters high, others can differ.

[EK !EKFQOBUFnQ No.3040064]

1. a = (v-u)/t
= 50/2.5
= 20 km/s^2 decelleration.

2. S = -0.5gt^2
S = -4.9X2.5^2 = - 30.625 meters.

3000-30.625 = 2969.375 meters.

[Anonymous No.3040072]

guys come on do my homework for me :3

[EK !EKFQOBUFnQ No.3040084]

>>3040064
sorry, decleleration is in km/h^2
i didnt convert units.

[Anonymous No.3040111]

>>3040084
dude thanks <3
ive got some more if you want to :3

[EK !EKFQOBUFnQ No.3040123]

>>3040111
alright, fine.
but only coz of he trips and the cute smileys.
:)

[Anonymous No.3040148]

>>3040123
thanks ;3


11. A cannon is shot into the air at an angle of 35o, at 24ms-1. Find the maximum height of the cannon ball.

[Anonymous No.3040168]

Who gives a shit, all this is controlled by electronics and meters in the real world.

[EK !EKFQOBUFnQ No.3040182]

>>3040148
...i'm going to repsume that the canon stays on the ground, and it is only the ball that is fired into the air:

i'll also presume that that angle (35) is being measured from the horizontal (so an angle of 90 would mean straight upwards)
24sin35 = 13.765...

v^2 = u^2 + 2aS
0 = 13.765^2 +2X(-9.8)XS
19.6S = 189.5...
S = 9.67 meters to 2 decimal places.

[EK !EKFQOBUFnQ No.3040191]

>>3040182
*presume

[Anonymous No.3040199]

>>3040182
you make it look so easy
EK, i love you forever <3

[EK !EKFQOBUFnQ No.3040265]

>>3040199
hah, nice to be appreciated
:D

[Anonymous No.3040276]

>>3040191
i actually read the original post twice and never noticed that typo. fucking dyslexia.