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/sci/ - Science & Math


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2988924 No.2988924 [Reply] [Original]

I know you guys don't like to do homework but me and my roommate have been trying to work this one out for a good half hour and are stumped. here it is:

A 77 , 38--long rod hangs vertically on a frictionless, horizontal axle passing through its center. A 15 ball of clay traveling horizontally at 2.7 hits and sticks to the very bottom tip of the rod.

To what maximum angle, measured from vertical, does the rod (with the attached ball of clay) rotate?

So far we tried conversation of angular momentum. We did an elastic collision to find what the initial angular velocity was and found the end angular velocity, but we're left with an unknown time and acceleration when we plug into equations.

We then tried Ke = Pe but this was flawed because I think the Pe deals with the center of mass moving, not the end of the rod.

Can I have some help?

in return, a hot girl.

>> No.2988939

hot girl does not compute, must in return better image.

>> No.2988952
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2988952

>>2988939
this better? Need help quick :/

>> No.2988958

that chick sure is fucking hot. jesus

>> No.2988971
File: 278 KB, 576x864, ashley_ann_vickers-2.jpg [View same] [iqdb] [saucenao] [google]
2988971

>>2988958
running out of pics and time, will post rest when someone helps

>> No.2988993

>filename
I'll just google ashley ann vickers, thanks anyway.

>> No.2988994

physics master demands better input for demanded output. use google.

>> No.2989004
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2989004

>
A 77 , 38--long rod hangs vertically on a frictionless, horizontal axle passing through its center. A 15 ball of clay traveling horizontally at 2.7 hits and sticks to the very bottom tip of the rod.

Dem units

>> No.2989015

>>2989010
and m/s

>> No.2989017

1. Use agular momentum to find the initial rotational speed of the rod-clay system.
2. Use rotational kinetic energy = .5Iw^2 to determine the height

>> No.2989011

>A 77 , 38--long rod

not sure what this means

>> No.2989010

>>2989004
sorry, units are in cm and grams

and googled the question, no good

>> No.2989023

>>2989004
Dat greentext.

>> No.2989024

>>2988971
Holy Titsburgh, that young lady is highly attractive

>> No.2989032
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2989032

>>2989017
solve for what though? how do you get height out of the KE?

>> No.2989055
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2989055

3 minutes left haaeeelllppp

>> No.2989070

>>2989032
I'm imagining the rotational energy being dumped into a potential energy reservoir.

>> No.2989083

>>2989070
eh it's over, time ran up. The answer was 74 degrees. Yea we were looking at that but doesn't that PE have to do with the center of mass moving? It's fixed in this situation.

I had tried 7.4 as an answer and I was off by 10 somewhere, looking at it my answer there was off by 10 by coincidence and not a fault in calculation.

I'm still curious as to how to get it, any input is nice.

>> No.2989119

>>2989083
bump

>> No.2989507

>>2988924
>>2988952
>>2988971
>>2989032
>>2989055
Dayum!
Too bad she likes girls more.