Hey /sci/. Having trouble, how does one expand and simplfy this 1-2(x+3)^2 I'm having issues, can anyone help me out

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Anonymous Fri Apr 22 08:46:13 2011 No.2929909 [Reply] [Original]

Hey /sci/.
Having trouble, how does one expand and simplfy this
1-2(x+3)^2
I'm having issues, can anyone help me out

>>	Anonymous Fri Apr 22 08:47:13 2011 No.2929912 multiply x+3 by x+3 then multiply your answer by -2 and add 1 to it

>>	Anonymous Fri Apr 22 08:48:13 2011 No.2929914 Learn to wolfram: http://www.wolframalpha.com/input/?i=1-2%28x%2B3%29^2

>>	Anonymous Fri Apr 22 08:51:13 2011 No.2929919 expanded and simplified: <span class="math">-2x^2-12x-17[/spoiler]

>>	Anonymous Fri Apr 22 08:54:13 2011 No.2929933 >>2929919 how'd you get -17

>>	Anonymous Fri Apr 22 09:00:13 2011 No.2929949 >>2929933 >>2929933 Learn first square rule: <span class="math">(a+b)^2 = a^2 + 2ab + b^2[/spoiler] Then use basic arithmetic.

>>	Anonymous Fri Apr 22 09:02:13 2011 No.2929957 Expansion of a square > (a+b)^2 = (a^2+2ab+b^2) 1 - [ 2 (x^2 + 6x + 9 ) ] = 0 -2x^ -12x - 18 + 1 = 0 -2x^2 -12x - 17 = 0 therefore 2x^2 + 12x +17 = 0

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