[ 3 / biz / cgl / ck / diy / fa / ic / jp / lit / sci / vr / vt ] [ index / top / reports ] [ become a patron ] [ status ]
2023-11: Warosu is now out of extended maintenance.

/sci/ - Science & Math

View post   
File: 42 KB, 990x742, ngpc-wp-wk-4-5_27678_990x742.jpg [View same] [iqdb] [saucenao] [google]
2885145 No.2885145 [Reply] [Original]

Maths shit.

3log(A) + (B)log9 - log162 = (C)

Given that log(c) = -1, find A and B.
Also, all the base is 2 for all log functions in the given equation.

Someone help? (C) is obviously easy shit.

Pic obviously unrelated.

>> No.2885184

<div class="math">3 log_{2} (A)+ (B)log_{2}9 - log_{2}162 = (C) ?</div>

>> No.2885189
File: 24 KB, 250x243, 1298721289659.jpg [View same] [iqdb] [saucenao] [google]
2885189

>base 2

>using anything but base e

>> No.2885192

>>2885184
That.
Sorry, I know not how to write proper script.

>> No.2885199

>>2885189
Yo, not my fault.
Just what it says in my assignment.

>> No.2885223

assuming log is base 10
log(c) = -1
10^-1 = c
c = .1 (no duh)
logA^2 + log9^B - log162 = .1
log(A^2 • 9^B)/162 = .1
10^.1 = (A^2 • 9^B)/162
you can take it from there

>> No.2885238
File: 547 KB, 4494x5000, lol.jpg [View same] [iqdb] [saucenao] [google]
2885238

>>2885223

>one equation
>two unknowns
>mfw you can take it from there

>> No.2885249

you get a range of results

http://www.wolframalpha.com/input/?i=3log2%28A%29+%2B+%28B%29log2%289%29+-+log2%28162%29+%3D+1%2F2

>> No.2885253

>>2885249

you sure it didn't say GRAPH A and B, op?

>> No.2885262

>>2885238
>some for one
>substitute into original equation
>thats middle school shit son

>> No.2885264

>>2885253
Certain.

>>2885238
That.
Also:
>Base of all log functions in equation is 2.
>log(A) is multiplied by 3.

But thanks anyway.

>>2885249
This is pretty handy. Thanks.

>> No.2885270
File: 14 KB, 300x300, bush.jpg [View same] [iqdb] [saucenao] [google]
2885270

>>2885262

>solving equation for one variable
>plugging it back into the exact same equation

good luck with that

>> No.2885273

>>2885262

no, you're incredibly fucking stupid

try doing that for A + B = 10

because that's essentially what you've given him

OP, the question is flawed

there are multiple answers

>> No.2885284

Of course, if you're looking only for interger soltions, reading off that graph ( >>2885249 ) it looks like when A = 0, B=5, and vice-versa

>> No.2885293

This thread makes me feel really stupid.

I dropped out of highschool.

>> No.2885296

>>2885284

actually A can't equal zero.

Here are my two solutions, OP

when B = 0, A = 3
when A = 1, B = 2

>> No.2885323

>>2885296

actually i think that's wrong

go with B = 0, A = 5

>> No.2885354

>>2885323
Tanks, stranger.

You wouldn't happen to have working with that, would you?
Or did you use that site as well?