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/sci/ - Science & Math


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File: 65 KB, 800x470, impossibru!.png [View same] [iqdb] [saucenao] [google]
2788997 No.2788997 [Reply] [Original]

I want someone to explain this to me in depth, I really could just look up the answers, but I really dont learn that much from doing that, so hopefully someone on /sci/ can help me with this

>> No.2789005

integrate mf

>> No.2789008

That's the god damn derivative? Jesus. Was it derived from a Taylor polynomial? I don't even know, I'm awful at math.

>> No.2789010

Just forget this then, Im going to just look up the answers

>> No.2789036
File: 63 KB, 827x723, Bild 1.png [View same] [iqdb] [saucenao] [google]
2789036

>> No.2789041
File: 43 KB, 749x660, Bild 4.png [View same] [iqdb] [saucenao] [google]
2789041

>> No.2789047

>>2789036
It's you!

>> No.2789048

>>2789047
what?
Who are you?

>> No.2789052
File: 52 KB, 570x377, reaction face.jpg [View same] [iqdb] [saucenao] [google]
2789052

>>2789036
Bro whatever that is, it makes me even more confused, sorry if I dont meet you eye to eye on this

>> No.2789056

I want to know the answer to this, also could someone annotate the answers a) b) c), I want to know what methods to use for each because Im shit

>> No.2789064
File: 86 KB, 917x1280, cutey_EmmaRed2.jpg [View same] [iqdb] [saucenao] [google]
2789064

>>2789052

You're function g'(x) is definied piecewise. Obviously, I mean when you look at the graph you know what function g'(x) is.
I called it Dg, the derivative of g.
Now that you know the funtion you can integrate it piece by piece. g(x)=int(g'(x))+c
you find out what c is if you consider g(0)=5 (it says so in your pic.)
I.e. g(0)=int(g'(0))+c

>> No.2789077

>>2789064
OP here
So you mean its this?
5∫(g'(x))+C
Where you would integrate from 0 to 3?

>> No.2789087

>>2789047
How are you gentlemen!
All your base are belong to us.
You are on the way to destruction.

>> No.2789099
File: 1.02 MB, 2240x3624, cutey_EmmaStone_high_res.jpg [View same] [iqdb] [saucenao] [google]
2789099

It's some function which starts at x=0, y=5.
you know that when you then take 2 steps to the right, you add to g(x) (the integral of g'(x)) the value of A=(r^2·pi)/4=pi, because that's the value under the curve of g'(x) from 0 to 2.
Then from 2 to 3 you know that g' is linear, so the value of g(x) goes up quadratically (because the integral of a linear function is a quadratic function) and you <see> that the value will rise +1,5 since that's the area under the curve. and so on.
you can reconstruct g(x).
And I have drawn you a pic (youout the condition g(0)=5, you you have to shift the function up in your mind.)
kthxbye.

>> No.2789180

>>2789099
OP here:
Thanks bro

>> No.2789248
File: 32 KB, 233x186, mollylips.jpg [View same] [iqdb] [saucenao] [google]
2789248

>>2789180
you're welcome.

>> No.2789290

>>2789248
OP here:
Quick question, why do you post pics of girls on a cal thread?

>> No.2789309
File: 68 KB, 640x480, mollyPhoto 65.jpg [View same] [iqdb] [saucenao] [google]
2789309

>>2789290
that's a silly question.
why would I not post pics of some cutie pies?
I posted two mathematica screenshots, so stop complaining :P
(also, I always post emma here when talking to an OP, so I don't have to take a tripcode. Except for I switched back to the one where I don't have mathematica running but also no more emma pics, so it's her)

>> No.2789319
File: 95 KB, 450x360, 1300590344901.jpg [View same] [iqdb] [saucenao] [google]
2789319

>>2789309
the one machine/computer

>> No.2789328

>>2789248
>>2789309
>>2789319
Wh- who is this?

>> No.2789333

>>2789309
Wait are you a girl?
I did not want to offend you

>> No.2789335

>>2789328
http://www.youtube.com/mememolly
http://www.youtube.com/RocketBoom
I think.

>> No.2789342
File: 96 KB, 450x360, d6939c58d1dff4ee34b1d1e1f7c926bd_1516277.jpg [View same] [iqdb] [saucenao] [google]
2789342

>>2789328
A guy with TWO computerz!

>> No.2789381

>>2789335
Thanks!