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/sci/ - Science & Math

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2773796 No.2773796 [Reply] [Original]

I'm traying to solve this multiple integral... I know that you /sci/ can help me... All the day traying to solve this problem... I can get the solution... This is a integral from my bible... Piskunov.,,,

>> No.2773814

What is math?

>> No.2773830

>>2773814

op here: don't understand... Please help

>> No.2773844
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2773844

Op here: Bump!

>> No.2773855

>>2773796

sorry can't help you, but how good is that Piskunov book? is it worth it for someone who has going into Calc II or is it too advanced?

>> No.2773857

just do it?
<div class="math">\begin{align*}\int_{3}^{4}\int_{1}^{2} \frac{1}{(x+y)^2}\;dy\;dx &= \int_{3}^{4}\left(\frac{-1}{x+y}\big|_{y=1}^{y=2}\right)\;dx\end{align*}</div>

>> No.2773860

Nope. Your punctuation annoys me.

>> No.2773864

just do it?
<div class="math">\int_{3}^{4}\int_{1}^{2} \frac{1}{(x+y)^2}\;dy\;dx = \int_{3}^{4}\left(\frac{-1}{x+y}\big|_{y=1}^{y=2}\right)\;dx</div>

>> No.2773881

>>2773864

Is a very good book, from cal I to III, try to get it...

>>2773860
wut?

>>2773857
Sorry, but I'm little nervious. Cuz, I from chile and my english sux... I need your help.


>>2773855

How you get that? I need the develop of tha all problem.

thanks

>> No.2773920

bump

>> No.2774022

/sci/ please!

>> No.2774540

here's more, i think you know how to finish it.

<span class="math">\int_{3}^{4}\int_{1}^{2} \frac{1}{(x+y)^2}\;dy\;dx = \int_{3}^{4}\left(\frac{-1}{x+y}\big|_{y=1}^{y=2}\right)\;dx = \int_{3}^{4}\left(\frac{-1}{x+2} + \frac{1}{x+1}\right)\;dx = [/spoiler]

>> No.2774572

>>2774540
how are you typing those expressions?

>> No.2774612

does this use HTML?

\int_0^{\infty} e^x dx

>> No.2777463

>>2774540

I get that solution, but when i'm developing the solve, i cant get it... Please!!! help me...

The all solve. My brain is hurt.

>> No.2777501

op here: i can get the solve... Wut the fack.

>> No.2777540

>>2777463
>>2774612

see >>2774878

>> No.2777607
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2777607

I look forward to celebrating human achievement hour with /sci/

>> No.2777740

>celebrating human achievement

what is it good for?
whom does it help?

celebrity worship, my ass

>> No.2777768

op here: bump! help

>> No.2777918
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2777918

>>2774540

what i'm doing wrong?>>2774540

>> No.2778002

bump

>> No.2778099

op here: i'm fucking screw...

>> No.2778867

op bump!

>> No.2778897

here you go, die you fucking troll
<div class="math">\int_{3}^{4}\int_{1}^{2} \frac{1}{(x+y)^2}\;dy\;dx = \int_{3}^{4}\left(\frac{-1}{x+y}\big|_{y=1}^{y=2}\right)\;dx = \int_{3}^{4}\left(\frac{-1}{x+2} + \frac{1}{x+1}\right)\;dx =-\ln(x+2)+\ln(x+1)\big|_{x=3}^{x=4} = -\ln 6 + \ln 5 + \ln 5 - \ln 4 = \ln\left(\frac{25}{24}\right)</div>

>> No.2778917

>>2773796 >>2777918
you never changed your limits of integration when you substituted.

>> No.2779133

>>2778897

thanks

i'm gonna die... OK... But thanks for the solve... And all!>>2778917

>> No.2780954
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2780954

2779333