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/sci/ - Science & Math


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2748712 No.2748712 [Reply] [Original]

Can you do it?

>> No.2748715

5/5+ d/dx (5) =1

derivative of a constant is 0

>> No.2748718

5^(5-5) = 1

>> No.2748724

(5/5)^5 = 1

>> No.2748736

sqrt(5*5)/5 = 1

>> No.2748756

im(5) + 5/5 = 1

>> No.2748776

5/5/5 = 1

>> No.2748779

5+5+5=/=1
Probably not proper operation
First thing i thought:
>(5/5)^5 = 1

>> No.2748784

5^(5 mod 5)

>> No.2748817

<div class="math">\pi(5) + \pi(5) - 5</div>
with pi(n) the amount of primes smaller or equal than n

>> No.2748825

Nice. I feel stupid after reading some responses :(

>> No.2748828

>>2748776
Either 5, 1/5, or 1/25 depending on where you wanted parentheses. :(

Also, (5th root)5/5

>> No.2748834

<div class="math">5^{5-5}</div>

>> No.2748836

(5/5)^5

>> No.2748842

<div class="math">\delta_{5,5}^5,</div>
whener <span class="math">\delta[/spoiler] is the kronecker-delta function.

>> No.2748847

>>2748842

Nice !

>> No.2748851

>>2748834
But 5-5=0 OH SHI!

>> No.2748859

(5-5)/5=1

money please.

>> No.2748860

f(5,5,5) where f(x,y,z) = 1

>> No.2748864

>>2748851
...and 5^0 = 1.

What's the problem

>> No.2748874

<div class="math">5^(\delta(5*5))</div>

where <div class="math">\delta</div> is the dirac delta function

although I like >>2748842 better

>> No.2748866

exp(i*Pi*5) - exp(i*Pi*5) - exp(i*Pi*5) = 1

>> No.2748872

5+5=5

>> No.2748873

log5(5)

>> No.2748876

>>2748859

Yeah... But really, no.

>> No.2748879

>>2748842
>In mathematics, the Kronecker delta or Kronecker's delta, named after Leopold Kronecker (1823-1891), is a function of two variables, usually integers, which is 1 if they are equal and 0 otherwise.
The fuck is this function useful for?

>> No.2748882

<div class="math">5^{\delta(5*5)}</div>

where <div class="math">\delta</div> is the Dirac delta function

>> No.2748886

>>2748879
to see if numbers are the same

>> No.2748889

>>2748879

writing stuff faster

>> No.2748888

>>2748882

It's better when it's correct, right ?

>> No.2748894

>>2748879
For instance for constructing matrix diagonal elements

>> No.2748897

>>2748879

Algebra, physics... It's everywhere ! (and very convenient)

>> No.2748899

>>2748882
lol wut, this makes no sense

>> No.2748902

>>2748879
It's actually useful in digital circuits stuff.

>> No.2748904

>>2748899

Makes perfect sense. 5^0 = 1.
You might wanna check Dirac delta in wikipedia.

>> No.2748906

>>2748888

Totally unrelated, but hey, my first quads !

>> No.2748908

>>2748904
I know the dirac delta function. You just seem to set it to zero..?

>> No.2748910

You have 5 apples and 5 pears. Someone gives you 5 pears. How many apples do you have?

>> No.2748914
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2748914

>>2748712
let's imagine an operation called "zblut".
Can I define "zblut" in this form:

5 zblut 5 zblut 5 = 1

???

>> No.2748916

>>2748908
oh, nm... you evaluate it at the point x=25...

>> No.2748917

>>2748908

Well, the dirac delta is worth infinity in 0, and 0 for any strictly positive numbre. So delta(25) = 0.

>> No.2748922

>>2748914

You might wanna use parenthesis though, it's a bit confuse which zblut applies to what...

>> No.2748932

(5/5)^5

>> No.2748934

5^(5-5)

>> No.2748937

555^0=1

>> No.2748942

>>2748736
>>2748776
>>2748817
>>2748859
>>2748860
>>2748866
>>2748872
wrong

>> No.2748948

>>2748914
Let's say zblut = 1/ (5(sqr-root(5))

>> No.2748952
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2748952

15 / 15

>> No.2748954

>>2748922
zblut is commutative and associative .

>> No.2748962

>>2748948
>>2748954
zblut cant be a constant.

>> No.2748970

>>2748952

winrar

>> No.2748985

>>2748948
you should go back to elementary school and learn what is an operation

>> No.2748998

5^ (d/dx 5)

>> No.2749005

>>2748952
You used six fives.

>> No.2749032

(sqrt(5*5))/5

>> No.2749072

>>2748914
you can either make zblut a ternary operation, or a binary operation
zblut(5, 5, 5) = 1
or:
zblut(zblut(5,5),5) = 1
or:
zblut(5<div class="math">\cdot</div> 5, 5) = 1
but then define <div class="math">\cdot</div>, which could be anything really

>> No.2749367

5^(d/dx(5^(d/dx(5)))) = 1