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/sci/ - Science & Math

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File: 210 KB, 680x572, 226-two-plus-two-equals-5-troll-physics.png [View same] [iqdb] [saucenao] [google]
2719505 No.2719505 [Reply] [Original]

FFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFUUUUUUUUUUUUUUUUUUUUUUUU........................

>> No.2719552

>no one replies
I'm so proud of you /sci/

>> No.2719576

>>2719552
I'm trying to find a flaw in the logic. Give me a minute.

>> No.2719584

>>2719576
Protip: square roots are not single-valued

>> No.2719601

>>2719505
>>2719505

Nice try.

16-36 = -20

25-45 = -20
-20 + 20.25 = -20 + 20.25

0.25 = 0.25


You end up dividing by zero.

(4-9/2)= -0.5

0.5^2 = 1/4

(5-9/2)^2 = 0.5

so you're saying 0.5 = -0.5

and that is saying 1 = 0

meaning you divided by zero.

which is like saying

4/0=5/0

(4/0)*0=5
cancel 0's,

4=5

there is the error. learn maths

>> No.2719629

>>2719576
No, the point was that this is an old troll image and you shouldn't reply because the error has been pointed out a thousand times.

Here's one of many answers, he took the square root of both sides, so he should have +/-.

>> No.2719644

>>2719629
nope, when the values are known you don't need +-.

>> No.2719680

>>2719644
hahaha o wow!

>> No.2719682

>>2719644
mmm, yeah you do actually.

>> No.2719713

>>2719680
>>2719682

nope

>> No.2719725

>>2719713
quick question for you, what's the square root of 4?

>> No.2719728

(4-9/2)^2 = (-.25)^2 = (.25)^2 = (5-9/2)^2. You can't take off the square root like that without putting a +/- in front of the (4-9/2) and (5-9/2)

>> No.2719738

>>2719725

+-2

-2^2 = 4

+2^2 = 4

am winrar

wat about

sqrt -4??????????????

halp plz

>> No.2719748

>>2719738
no no let him answer it.

>> No.2719760

>>2719738
2i

>> No.2719773

>>2719760
You mean +-2i

>> No.2719794

>>2719725

http://www.wolframalpha.com/input/?i=-2+%3D+4^.5

ewps?

>> No.2719827

>>2719738
>mfw -2^2=-4

>> No.2719832

x^2= 4
x= +-2

4^.5= +2

its really that simple.

>> No.2719839

>>2719794
How did we ever do math before wolfram alpha?

>> No.2719898

>>2719760

2i^2 = -4?

2log(base -4) 2i = log (base-4) -4

2log 2i/log -4 = 1

-4^1 = 2i^2

((-1)(4))^1 = 2i^2

log -4 = 2 log 2i
log -4 = 2 (log 2)(log i)
log -4/ log i = 2log2

log (base i) -4 = log 4

i^(log 4) = -4

-4 = 2i^2

i^log 4 = 2i^2
i^log4/i^2 = 2

i^log4 = 2 times i^2 for the equation i^2log4/i^2 to be 2.


i^2= 2/i^log4
2log i = log (2/i^log4)

Log i = (log (2/i^log4))/2

10^(log (2/i^log4))/2 = i

need help wat do i =?

>> No.2719927
File: 162 KB, 700x493, 1296186941842.jpg [View same] [iqdb] [saucenao] [google]
2719927

>>2719839

with your imagination wooooooooshhhhhh!!!!

>> No.2719955

>>2719839

you could waste time writing and explaining the definition of absolute value or just plug that shit in wolfram and have it ominously state, "this shit is wrong" for you.

>> No.2719963

>>2719955
Because -2 is not one of the square roots of 4?

okay. whatever you say.

>> No.2719995

>>2719963

roots? There's only one, +2.

>> No.2720077

>>2719995
http://mathworld.wolfram.com/PrincipalSquareRoot.html

from the mouth of god.

>> No.2720192

http://www.wolframalpha.com/input/?i=%28%284-%289%2F2%29%29^2%29^%281%2F2%29+%3D+%28%285-%289%2F2%29
%29^2%29^%281%2F2%29

wolfram says shit is fine.