[ 3 / biz / cgl / ck / diy / fa / ic / jp / lit / sci / vr / vt ] [ index / top / reports ] [ become a patron ] [ status ]
2023-11: Warosu is now out of extended maintenance.

/sci/ - Science & Math


View post   

File: 7 KB, 565x185, matchstick.jpg [View same] [iqdb] [saucenao] [google]
2709711 No.2709711 [Reply] [Original]

Move one matchstick to make this a valid equation. Making the equal sign a not-equal sign isn't allowed.

>> No.2709745
File: 44 KB, 819x460, Xdiv1equ1.png [View same] [iqdb] [saucenao] [google]
2709745

>> No.2709759

>>2709745
Wait, what?

>> No.2709765
File: 12 KB, 565x185, Untitled.png [View same] [iqdb] [saucenao] [google]
2709765

square root of 1 equals 1

>> No.2709776
File: 28 KB, 448x500, proud.jpg [View same] [iqdb] [saucenao] [google]
2709776

>>2709765

>> No.2709780
File: 44 KB, 800x600, 1288959871489.png [View same] [iqdb] [saucenao] [google]
2709780

Take the middle one on the left, burn the leftmost then set it down parallel to the remaining one on the lefthand side.

>> No.2709789

>>2709765

plus or minus one

>> No.2709803

Move that stick to make an X, you have roman numeral XI=11

>> No.2709807 [DELETED] 
File: 32 KB, 565x185, v_ne_11.png [View same] [iqdb] [saucenao] [google]
2709807

Isn't this the obvious one?

>> No.2709835

2 ≡ 2

>> No.2709856

Push bothe ends of V together. 11=11

>> No.2709980

It's already a valid equation, given the right value of V.

>> No.2710002
File: 12 KB, 565x185, 1300210775338.jpg [View same] [iqdb] [saucenao] [google]
2710002

>> No.2710012
File: 7 KB, 548x184, 123.jpg [View same] [iqdb] [saucenao] [google]
2710012

11 = 11

>> No.2710013

XI=11 using greek numerals

>> No.2710017

>>2710012
>>2710002
If that is the solution then it pisses me off.

>> No.2710027

>>2709789
Nope. sqrt(1) = 1 by definition.

>> No.2710031

does not equal.

>> No.2710506

Burn first matchstick (left one)!!1

*Russian online*

>> No.2710596

V =/= II


yeah boi

>> No.2710619

VI > II

>> No.2710644

>>2710596
V >= II

>> No.2710654

>>2710644

I don't think breaking them counts.

>> No.2710702

Let N = 5

V = N

This is a valid solution regardless of whether
V is taken as a letter or a numeral

>> No.2710755

>>2710027
Wat.

>> No.2710769

<div class="math">v \equiv 11</div>

then v*1 = 11 (written as v1=11 in matches)
so the equation is valid

>> No.2710779

>>2710755
I think he meant that, that sign is the principal square root which is always taken to be positive.

>>2710654
You're just taking the I of VI and making a greater than or equal sign, doesn't actually look like >=.

>> No.2710795

1 x 1 = 1,
1 / 1 = 1

>> No.2711095

XI=11