/sci/ - Science & Math

[Flame No.2705534]

Help /sci/ I need to solve this problem and I'm not sure what to do. heeeeelp. ;_;
4x+3 / 4x^3 - 29x^2 - 40x -12

[Anonymous No.2705562]

1 / ((x-8) x-4)

[Flame No.2705564]

basically, help me divide and simplify please.

[Flame No.2705574]

>>2705562
Thanks!

[Anonymous No.2705580]

>>2705564
Do you know how to divide polynomials?

I'm assuming you meant 4x+3 over the 4x^3

[Anonymous No.2705597]

<span class="math"> \frac{4x+3}{4x^3 - 29x^2 - 40x -12}=\left(\frac{4x^3 - 29x^2 - 40x -12}{4x+3}\right)^{-1} [/spoiler]

Do some algebraic long division, flip back over.

[Flame No.2705602]

>>2705580
I'm in calculis
How do I forget this. ;_;

Also apparently the answer given by >>2705562 was incorrect.
More questions on the way...

[Anonymous No.2705639]

>>2705602
Also, he's right. It simplifies to <span class="math"> \frac{1}{x(x-8)-4} [/spoiler]

[Anonymous No.2705647]

use you synthetic division ;)

[‫‬‭‮‪‫‬‭‮‫‬‭‮‪‫‬‭‮‫‬‭‮‪‫‬‭‮suomynonA‬‬‬‬‬‬‬‬‬‬‬‬ No.2705692]

http://www.wolframalpha.com/input/?i=%284x%2B3%29%2F%284x^3-29x^2-40x-12%29