im confused

[Anonymous No.2704120]

why is the partial derivative with respect to x of:

f(x,y,z) = x^3 * e^(3y^2 + xz)

equal to:

(3x^2 + x^3*z) * e^(3y^2 + xz)

I dont get why the 3x^2 appears...

[Anonymous No.2704145]

Did you happen to get this at an exam today?

VU University Amsterdam?

Anyways, product rule.

[Anonymous No.2704150]

>>2704120
>>2704120

nvm i got it lol product rule

duhh

[Anonymous No.2704154]

product rule, then factoring out the exponential term

[Shiro !NuJBxbKoek No.2704165]

f(x,y,z) = x^3 * e^(3y^2 + xz)

k.

product rule:

x^3 * e^(3y^2 + xz)

f(x) = x^3
f'(x) = 3x^2
g(x) = e^(3y^2 + xz)
g'(x) = z e^(3y^2 + xz)

f(x)g'(x) + g(x)f'(x)
=>

x^3 *e(3y^2 + xz) *z + e^(3y^2 + xz)*3x^2.

=> 3x^2 e^(3y^2 + xz) + zx^3 e^(3y^2 + xz)
=> e^(3y^2 + xz) ( 3x^2 + zx^3).

[Anonymous No.2704166]

>>2704154
>>2704145

no just random econ homework

rape my face im dumb

[Anonymous No.2704178]

>>2704166
Okay, because I had this EXACT problem at an exam today.

[Anonymous No.2704189]

>>2704178

haha weird