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/sci/ - Science & Math

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File: 132 KB, 725x275, Mathjoke.jpg [View same] [iqdb] [saucenao] [google]

Anonymous Wed Mar 9 22:07:19 2011 No.2673008 [Reply] [Original]

Help me evaluate the integral, thanks in advance

∫ 9r^2dr/√(1-r^3) u=1-r^3

Pic not realated

>>	Anonymous Wed Mar 9 22:10:19 2011 No.2673019 Wow, you're a lazy ass. You know that u=1-r^3 is a separate equation, probably suggesting a change of variables? Any, expand and follow the steps to understand. http://www.wolframalpha.com/input/?i=%E2%88%AB+9r^2dr%2F%E2%88%9A%281-r^3%29

>>	Anonymous Wed Mar 9 22:13:19 2011 No.2673034 >2673019 Thanks for the link :)