/sci/ - Science & Math

[Anonymous No.2637860]

x^2-y^2=339

How am I supposed to find an answer to this kind of equation? I know that I'm supposed to be able to solve this but I have no idea. Anybody out there able to help?

[Anonymous No.2637874]

y=+/-sqrt(x^2-339)

hurrrrdurrrr

[Anonymous No.2637880]

read your book

[Anonymous No.2637888]

That's the equation of a circle a radius of <span class="math"> \sqrt{339} [/spoiler]. It has an infinite number of solutions unless you define a point on the circle.

[Anonymous No.2637889]

do you have a similar pic for derivatives?

[Anonymous No.2637893]

oh and by the way x and y are both integers

[Anonymous No.2637897]

>> Anonymous 03/03/11(Thu)16:58 No.2637888
That's the equation of a circle with a radius of 339 . It has an infinite number of solutions unless you define a point on the circle.

[Anonymous No.2637906]

>>2637893
well thanks for fucking telling us.

[Anonymous No.2637907]

gonna dump all of these before someone asks

[Anonymous No.2637908]

"Solve it" in what way?

[Anonymous No.2637911]

[Anonymous No.2637909]

That's the equation of a circle with a radius of 339 . It has an infinite number of solutions unless you define a point on the circle.

[Anonymous No.2637915]

[Anonymous No.2637916]

>>2637897

of sqrt(339)

[Anonymous No.2637917]

x=+/-170 y=+/-169
x=+/-58 y=+/- 55
http://www.wolframalpha.com/input/?i=x^2-y^2%3D339

[Anonymous No.2637922]

[Anonymous No.2637918]

It's the equation of a hyperbola with focii at <span class="math">\pm 479.4[/spoiler], and asymptotes with a gradient of <span class="math">\pm 1<span class="math">. Any solution lies on the hyperbola.[/spoiler][/spoiler]

[Anonymous No.2637925]

>>2637907
>>2637911
>>2637915
many thanks

[Anonymous No.2637933]

[Anonymous No.2637935]

>>2637916
Sorry... I've tried getting this right like 5 times now...

That's the equation of a circle with a radius of <span class="math"> \sqrt{339} [/spoiler]. It has an infinite number of solutions unless you define a point on the circle.

[Anonymous No.2637950]

It's the equation of a hyperbola with focii at <span class="math">\pm 479.4[/spoiler], and asymptotes with a gradient of <span class="math">\pm 1[/spoiler]. Any solution lies on the hyperbola.

[Anonymous No.2637953]

>>2637935
x and y are integers
>>2637917
Knowing the solution wasn't that hard for me rather than being able to know how to solve it.

[Anonymous No.2637956]

>>2637935
look again, it's not a circle

x squared MINUS y squared

I'm still not understanding what exactly the OP is trying to solve for. An integral?

[Anonymous No.2637963]

>>2637956
Integer solutions for that equation

[Anonymous No.2637968]

>>2637956
Yeah... You're right. I guess I should've paid better attention during conics.. Shame on me :(

[Anonymous No.2637980]

>>2637950

Sorry, I mean focii of <span class="math">\pm 26[/spoiler]. I've attached the image of the graph.

[Anonymous No.2637994]

>>2637963
Wouldn't there be an infinite number of them?

[Anonymous No.2638004]

>>2637963

Pick a point that lies on the hyperbola. That's a solution. There are plenty to choose from.

[Anonymous No.2638008]

>>2637994
no, according to this link http://www.wolframalpha.com/input/?i=x^2-y^2%3D339
just wondering how these solutions could be achieved

[Anonymous No.2638066]

>>2638008

I'm not quite sure what the integer solutions given by Wolfram actually correspond to. They're probably just arbitrary solutions. You can find a solution using the equations:

<div class="math">y=\pm\sqrt{x^2-339}</div>
<div class="math">x=\pm\sqrt{y^2+339}</div>

Pick any y value you want. There will be a corresponding x value, and vice versa.