/sci/ - Science & Math

[Anonymous No.2599368]

Try it.

[Anonymous No.2599398]

that adds up to 120% dumbass

[EK !EKFQOBUFnQ No.2599402]

you wasted 2 minutes of my life and i want them back
hans-moleman.jpg

also, 7/10
nice troll

and i only fell for it because i'm high

fuck you, well played, and goodnight.

[Anonymous No.2599408]

>>2599402
>>2599398
>implying this problem is not solvable.
This is high level math, children. Wait a bit until some adults solve it.

[EK !EKFQOBUFnQ No.2599411]

>>2599408
haha
lmao
im not being trolled twice in one thread....

fool me once shame on me
fool me twice...erm...wait...thats not right...

...fuck

tl;dr, fck you!

[waffleswaffles !wAffLeNaE2 No.2599414]

I do not like Venn Diagrams but I forgot the other way to calculate it

[Naggarothian !!0S4L3hs2lkr No.2599417]

>>2599398
>>2599402
>>2599411
>MFW

[Anonymous No.2599413]

>>2599408
That's a lie. The solution is obviously -20%.

[Anonymous No.2599423]

>>2599398
no
the categories of people who watch 2 sports also count for each of the singular categories of the sports they watch

[Anonymous No.2599425]

>>2599411
Typical liberal.

[Anonymous No.2599426]

Statsfag here.

52% play neither sport.

[Anonymous No.2599428]

>baseball
>sport
7/10
Nice troll

[EK !EKFQOBUFnQ No.2599432]

>>2599426
its about watching sport, not playing sport, you fucking dyslexic jew!

[Naggarothian !!0S4L3hs2lkr No.2599436]

>>2599432

[Anonymous No.2599442]

>>2599432
Whatever, bro. Care to demonstrate my result if you will?

[Anonymous No.2599441]

>>2599426

This guy is right


Everyone is this thread is a troll or stupid

[Anonymous No.2599440]

Doesn't have to add up to 100%. If I watched gymnastics and baseball, I am part of the 14% that watched gymnastics and baseball. I am also part of the 28% that watched gymnastics, and the 29% that watched baseball.

[Anonymous No.2599450]

The answer is 24%.

[Anonymous No.2599452]

>>2599426
Correct!

[Anonymous No.2599455]

>>2599441
>28 + 29 + 19 = 76 - 10 - 12 - 14
>calls others stupid

[Anonymous No.2599456]

>>2599442

see

>>2599441

/thread

[waffleswaffles !wAffLeNaE2 No.2599457]

Only Gym = 12
Only Baseball = 11
Only Soccer = 5

Only Gym+Base = 6
Only Gym and Soc = 2
Only Base and Soc = 4

All three = 8

So the answer is 52.

[EK !EKFQOBUFnQ No.2599459]

>>2599436

yeh, absolutely fucking furious.

>>2599440
demonstrate what?

the troll was more sofistikatid that that. why do you think he wasted 2 minutes of my time and not 2 seconds?

>>2599441
nah, just you.

>>2599442

[EK !EKFQOBUFnQ No.2599467]

>>2599436

yeh, absolutely fucking furious.

>>2599440

the troll was more sofistikatid that that. why do you think he wasted 2 minutes of my time and not 2 seconds?

>>2599441
nah, just you.

>>2599442
demonstrate what?

[Anonymous No.2599479]

>>2599411
ITT: Retards who can't tell trolling from legit mathematics.

[EK !EKFQOBUFnQ No.2599495]

>>2599491
would if i could, darling.

[Anonymous No.2599493]

>>2599455
What the fuck you on about?
I was doing my working on paint, as if I can be arsed to write it out properly. You've got to be a stupid not to follow what I'm doing

[Anonymous No.2599491]

EK. go fuck yourself

[Anonymous No.2599502]

>>2599495
I don't mean in the literal sense, I mean gtfo /sci/ and never come back

you're as bad as the cancerous Aether or whatever the fuck that angsty teenager claims his trip is

[EK !EKFQOBUFnQ No.2599508]

>>2599502
>you're as bad as the cancerous Aether
>you're as bad as
>you're

at least aether knows grammar, which is more than i can say for you...

[Anonymous No.2599513]

>>2599508
babies troll
gtfo seriously

[Anonymous No.2599514]

>>2599508
Have my children.

[Anonymous No.2599515]

>>2599508
Anyone else really hate EK?

[Naggarothian !!0S4L3hs2lkr No.2599521]

>>2599502
>you're as bad as the cancerous Aether
Cancerous is too nice a word to describe him.

[EK !EKFQOBUFnQ No.2599529]

>>2599513
>>2599515
>>2599521

BAHAHAHAHHHHHAAA!!

[sage No.2599536]

Guys stop bumping this thread.

[Anonymous No.2599541]

>>2599529
failure
I told you "babies troll"
I knew you were failing right there.
Get the fuck out.

[Anonymous No.2599553]

>>2599547
You suck
Go figure out why /sci/ hates you so much.
oh if only janitors were approved.

[EK !EKFQOBUFnQ No.2599547]

>>2599541
babies troll maybe...but definitely not babbies FIRST troll!
...ohhhh yyyeeeeaaaahhh!

[Anonymous No.2599570]

>advanced mathematics thread
>flame war
never change

[EK !EKFQOBUFnQ No.2599572]

>>2599553
>mfw if they were approved, i would probably be one by now

[Anonymous No.2599577]

>>2599553
Because last time it worked so well, amirite?

>post the word 'guess' in OP
>get instaban

[Anonymous No.2599578]

Part of me hates that she's just over-trolling these days from what I've seen, but part of me also wants to fuck her while solving math problems.

[Anonymous No.2599582]

>>2599452
15%

[EK !EKFQOBUFnQ No.2599587]

>>2599578
wait...just so i have this correct...are you fucking me while I am the one solving maths problems, or are YOU solving maths problems at the same time as fucking me?

[Anonymous No.2599590]

Eh, the hardest EK ever trolled me was when she saved an image I really wanted as the thumbnail. I don't mind her. You guys are too easy to troll.

[EK !EKFQOBUFnQ No.2599597]

>>2599590
what?
i dont remember doing that..it might have been an accidental troll.
what was he image?

(also, yeh, basically >90% of all the posts i have made tonight were trolls :D)

[Anonymous No.2599610]

>>2599587

Either and both, as long as one of us picks an interesting problem.

[Anonymous No.2599626]

>>2599597
being a troll is an excuse to be a fucking retard.
Go find some productive to do asshole.
You are the reason why we cant have nice things.

[Anonymous No.2599634]

>>2599572
Nope. Not you.
You're a fat and stupid

[EK !EKFQOBUFnQ No.2599639]

>>2599610
hmmm...this intrigues, me, i am actually literally gonna fucking try this, if i can find a guy open minded enough.

...hey! he might last longer as well....
fucking genious anon!

[Anonymous No.2599645]

>>2599639
>implying anyone would fuck a whale

[Anonymous No.2599658]

>>2599582
Nope. Full problem w/ MC answers.

[Anonymous No.2599662]

>>2599639

It's worked for me, but that's because the girl had a thing for being ignored, so I would put the paper on a clipboard and place it on her back and tell her to stop being so loud because it was distracting me. Definitely memorable.

[Anonymous No.2599670]

@ Ek
You expend a way too much time "trolling",
If you have the intellect you claim to have, you would notice that doing such a thing is a huge waste of time, time that could be expend making sandwiches.
so let me sum everything
>>> less trolling
>>> more sandwiches

[EK !EKFQOBUFnQ No.2599674]

>>2599645
I know right!
im really fat, and im so self conscious about it, and i wish i were skinny but its just so hard

WHY WONT ANYONE LOVE ME /SCI/
WHY WONT ANYONE LOVE ME!!???


WHY!!?????

[EK !EKFQOBUFnQ No.2599681]

>>2599670
ahaha! i actually thought you were being dead fucking serious untill i read the end of he second line.

well played...

[EK !EKFQOBUFnQ No.2599683]

>>2599662
awesome...im gonna do it.
:D

[Anonymous No.2599684]

>>2599674

wat

[Anonymous No.2599682]

>>2599658
35-100=65
-65=40+35+c
c=5/100
c=0.05 or 5%

[Anonymous No.2599690]

>>2599681
you fucking faggot.
take yourself and every other tripfaggot out of /sci/

[EK !EKFQOBUFnQ No.2599701]

>>2599690
well you are correct that i do indeed have power over all tripfaggots...if i order them to leave, they will indeed acquiesce...
however, what will i get in return?

[Anonymous No.2599704]

Oh EK, how sad you are.
You realize you're here for nothing else but for attention in a SCIENCE BOARD and as such, you can't keep up with the math, trolling and science posted here, so you excuse yourself with having "trolled" when in reality you're actually that stupid.

[Anonymous No.2599702]

>>2599682
Correct. Since this isn't about math anymore, I won't be posting. The problems are all from the 2009 actuary exam I took. 140 problems. gl.

[Naggarothian !!0S4L3hs2lkr No.2599698]

>>2599690
>take yourself and every other tripfaggot out of /sci/
Woah there, buddy. Don't want to throw out the baby with the bathwater......

>(not to imply that I'm great or anything)
>(I've just seen a few awesome tripfags around here, like Physics Guy)

[Naggarothian !!0S4L3hs2lkr No.2599710]

>>2599701
Oh, quit being such an arrogant, self centered faggot.

I'm actually more likely to leave if you STAY on /sci/

[Anonymous No.2599711]

>>2599698
>tripfag
>physics guy
>doesn't have my tripcode
>he gives about two fucks about impersonated, unlike your dumbass attention-whore tripcode.
GTFO

[Anonymous No.2599717]

>>2599553
>>2599690
>>2599704

I just want to congratulate EK, today from all days, for her heroic efforts to cause enough tears to solve the midwestern drought.

[EK !EKFQOBUFnQ No.2599723]

>>2599710
>I'm actually more likely to leave if you STAY on /sci/
>well you are correct that i do indeed have power over all tripfaggots...if i order them to leave, they will indeed acquiesce...

...god works in mysterious ways...
=p

[Anonymous No.2599725]

obviously 24%

[Anonymous No.2599726]

do i satisfy?

[Anonymous No.2599729]

Seriously guy, in order to save /sci/, you must remove any 4chan culture it has as an imageboard.
Forget the tripcodes, forget the trolling, forget the chatting and humour. Just go full math & science, science & math everywhere.

But that might be impossible, since almost everybody here is most likely still in high school and such thing would overwhelm them

[EK !EKFQOBUFnQ No.2599738]

>>2599717
ahh...trolling is indeed a art.

[Anonymous No.2599739]

>>2599738
when you samefag, it's not.

also, trolling /sci/ is like stealing candy from a baby.
That only proves you're cancer.

[Anonymous No.2599755]

>>2599450
Correct. All others are just dumb.

[Anonymous No.2599756]

>>2599572
who the fuck is that ugly fat whore? she looks like a pelican mixed with a hippo. stop posting

[EK !EKFQOBUFnQ No.2599762]

>>2599739
yeh i know rite?
its just the thing is, i was getting impatient that my troll wasnt working, so i was like "i know! i have a great idea! i will post as anon, and get trolled, and then post as anon, and compliment myself as EK!"

so i did it, and then i was like...fuck yeah!!!

...oh wait, i shouldnt have told you that!

[Anonymous No.2599769]

>>2599452
5%?

[Anonymous No.2599770]

>>2599762
my compliments, from me to you, two different people entirely. your brilliant!

[Anonymous No.2599772]

>>2599457
0/10

[EK !EKFQOBUFnQ No.2599774]

>>2599770
>your brilliant!
>your

lol, as are you!
:D

[Anonymous No.2599792]

>>2599426
>>2599441
>>2599452
are you guys trolling or just fucking retarded? the answer is obviously 24%

[Anonymous No.2599809]

>>2599792
The answer it 52%, idiot.

[Anonymous No.2599814]

>>2599809
the first three are all you need, the other points are irrelevant.

[Anonymous No.2599823]

people in this thread r retard. Answer is 44%. Seriously, not hard

[Anonymous No.2599826]

>>2599809
can you explain why? i looked at the chart but I don't get why you added and subtracted instead of just using the percentage of those that watched each show

[Anonymous No.2599853]

52%

time: 55 sec.

[Anonymous No.2599878]

52%.

/thread

[Anonymous No.2599886]

52%
time: the time it took me to find a fucking pen, ~1 min.

[Anonymous No.2599887]

>>2599814

No.

This is an elementary problem. If you can't solve it you are either terrible at understanding probability and statistics, or you haven't taken a legitimate class in it yet.

[Anonymous No.2599929]

>>2599887
>Probability

lolwut

[mathfag No.2599930]

This is what counts for hard these days in school? Let's do this thang.

P((A\/B\/C)^{c}) means "the probability that someone did not watch A or B or C", ie, "the probability that someone did not watch any of the three sports."

Now, since P(A^{c}) = 1 - P(A), we have

P((A\/B\/C)^{C}) = 1 - P(A\/B\/C).

It therefore suffices to find P(A\/B\/C). But you're in luck, because there's a formula that's easy to derive:

P(A\/B\/C) = P(A) + P(B) + P(C) - (P(A/\B) + P(A/\C) + P(B/\C)) + P(A/\B/\C).

Plugging in values,

P(A\/B\/C) = 28 + 29 + 19 - (14 + 12 + 10) + 8 = 76 - 36 + 8 = 48.

Suck it.

[mathfag No.2599940]

>>2599930

This is where you get the 52, btw. 1 - 0.48 = 0.52. Hence 52%.

Captcha: PRINCE hqira

[Anonymous No.2599943]

>>2599930
Wrong.

[Anonymous No.2600035]

>>2599658

5%

65% get nothing done, 30% +40% get something done, so 5% must get both things done and are overlap.