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/sci/ - Science & Math

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2529607 No.2529607 [Reply] [Original]

Ok /sci/ducks a /b/tard needs help w/ his entry level chem homework. In return dat ass.

A 500.g-g iron bar at 212°C is placed in 2.0L of water at 24.0°C. What will be the change in temperature of the water?(Assume no heat is lost to the surroundings)

please don't just give me the answer i want to know how to figure these problems out

>> No.2529631

herp derp

formula:
cmT1 + kMT2 = T3(cm + kM)

where c is specific heat of iron, m is mass of iron, T1 is kelvin heat of iron

and k is specific heat of water, M is mass of water, T2 is kelvin heat of water

solve for T which is the final temperature of both water and iron in kelvin

>> No.2529642

>>2529631
So is it necessary for me to convert the °C to Kelvin and then convert back?

>> No.2529755

yes, definitely

>> No.2529972

>>2529755
What would be the difference if i left it in Celsius degrees?

>> No.2529983

>>2529972
Because the formula is designed for Kelvin degrees. It wouldn't be the same with Celsius.

>> No.2530018

>>2529972
Kelvin measures the heat content, since no heat=0. Celsius doesn't, since freezing water=0. Frozen water still has heat in it.

>> No.2530019

>>2529983
I'm really having trouble figuring this out. Could you work out the equation for me because i keep getting the wrong answer.

>> No.2530026

5.00 X 2.0L /212

?

>> No.2530072

do i also have to convert the specific heat to kelvin?

>> No.2530371

op bamp im still stuck on this can anyone help?