/sci/ - Science & Math

[Anonymous No.2479108]

Solve for X

[Anonymous No.2479116]

I can't see the entirety of the problem, so I can't solve for x

[Anonymous No.2479117]

after 1 in the brackets is the answer for the question

[Anonymous No.2479121]

its a quadratic, btw :3

[Anonymous No.2479122]

Just apply the rules. I'm not going to do it for you.

[Anonymous No.2479123]

Doesn't matter, because this doesn't prove how the moon got there, does it? You can't explain how the moon got there, so why don't you stop pretending to know everything.

[Anonymous No.2479128]

http://www.wolframalpha.com/input/?i=Log[3%2Cx]-2+Log[x%2C3]%3D%3D1&asynchronous=false&equal
=Submit

[Anonymous No.2479129]

>>2479117
so you aren't asking me to solve it, you're asking me to rearrange it?

[Anonymous No.2479137]

>>2479129
nah, man dont worry about it
>>2479128 helped me :3

[Anonymous No.2479135]

>>2479128
oh my gawsh!! thnxx!!

Im studying logarithms now, so i'll be back preetyy soon!!!

[Anonymous No.2479165]

This is trivial, first substitute log3(x) with a variable (such as y), then you have: y-(2/y) = 1 => y^2-2=y => y^2-y-2 = 0, now solve the simple quadratic equation: delta = 1+4*2=9, thus x_0 = (1+3)/2 = 2 and x_1 = (1-3)/2 = -1, which means you can write the equation as (y-2)(y+1)=0. As logarithms are positive, only 2 is a valid solution, which means y=2 => log3(x) = 2 => x = 3^2 = 9.

Thus the solution is x = 9.

[Anonymous No.2479170]

>>2479129

Actually, yeah.
i completly forgot that i need to show algebraically

[Anonymous No.2479181]

>>2479165
>As logarithms are positive
>implying entropy is negavie
>implying the logarithm isn't a surjective function over R.
anyway, nice derivation

[Anonymous No.2479188]

X is 27

[Anonymous No.2479189]

>>2479165
dude you forgot the log3(x)= -1 is still possible, so 1/3 is an answer as well :P

[Anonymous No.2479208]

>>2479189
>>2479181
Oops, you're right. I don't know what I was thinking.

[Anonymous No.2479628]

[Anonymous No.2479695]

Y does log3(x)/logX(3)=logX(3)?