/sci/ - Science & Math

[Anonymous No.2348302]

Need help with this trig shit

If s=sin ∅' and c=cos ∅' simplify:
1) (c^4-s^4)/(c^2-s^4)?
any help?

I keep getting

cos^2∅ - sin^2∅

and the answers 1 so it should be

cos^2∅ +sin^2∅

[Anonymous No.2348324]

bump for nub

[Anonymous No.2348338]

fuck

looks liike /sci/ cant help me eitheer

[Anonymous No.2348344]

Looks like homework.

[Anonymous No.2348349]

>>implying half the other stuff here isnt

[Anonymous No.2348361]

>>2348349
>Implying the other homework threads get constructive responses.

[Anonymous No.2348365]

>>2348361
see
>>2346658

[Anonymous No.2348369]

>>2348365
Note how his question isn't elementary trigonometry and how he spent time actually writing out explicitly how far he'd come himself instead of just saying "/sci/ do my homework".

[Anonymous No.2348378]

>>2348369


>>Implying this is elementary trigonometry

[Anonymous No.2348397]

>>2348378
>Still no effort on your part.

It is elementary.

[Anonymous No.2348404]

It does not equal 1. Graph it in wolframalpha

[Anonymous No.2348407]

>>2348369

according to google elementary is 5 years

in uk we have years 7-13

7+6=11 so elementary is up to year 11.

Im in year 12 so this is clearly not elementary.

Also worked out how to do it.

[Anonymous No.2348410]

>>2348404

It is.

c^4-s^4 = (c^2-s^2)(c^2+s^2)

so we have (c^2-s^2)(c^2+s^2)/(c^2-s^2) = c^2+s^2 = 1

(cos^2o + sin^2o = 1)

[Anonymous No.2348411]

>>2348407
>Elementary: easy and not involved or complicated; "an elementary problem in statistics"; "elementary, my dear Watson"; "a simple game"; "found an uncomplicated solution to the problem"

and no, you did not solve it.

[Anonymous No.2348418]

>>2348410
it's not what he/she asked though.

[Anonymous No.2348440]

instead of teta ill use x
(c^4-s^4)/(c^2-s^4)=(c^2-s^2)(c^2+s^2)/(c^2-s^4)=
(cos(2x)/(c^2-s^4)=(cos2x)/(c-s^2)(c+s^2)
for the start, you sure youve written it down correctly btw?

[Anonymous No.2348447]

1) (c^4-s^4)/(c^2-s^4)?


should be:

1) (c^4-s^4)/(c^2-s^2)


---


Now i have another (last problem) issue.

It says s√1-s^2 / c√1-c^2

[Anonymous No.2348448]

>>2348440
yeah it's a typo, seeing as though it implies

c^4 - s^4 = c^2 - s^4 ===>
c^4 (x) = c^2 (x) for all x, which is of course nonsense.

[Anonymous No.2348458]

>>2348447
1-sin^2 = cos^2
1-cos^2 = sin^2.

that should be a big enough hint for you to solve it

[Anonymous No.2348461]

>>2348447
....
c^2-s^4=(c-s^2)(c+s^2)=(c-1+c^2)(c+1-c^2)=
c^2 + c - c^3 - c - 1 +c^2 + c^3 + c^2 - c^4 =
-c^4 - 1 + 3c^2 = (2c^2 - 1) - c^4 + c^2 =
cos2x + c^2(1 - c^2)=cos2x + c^2*s^2

[Anonymous No.2348465]

>>2348458

The answer for this is 1 too.

I end up with sin o x cos o / cos o x sin o

Any way i could cancel these out to get 1?

[TRollben No.2348472]

dude, (c^4-s^4) simplifies to (c^2-s^2)(c^2+s^2)
so u have (c^2-s^2)(c^2+s^2)/(c^2-s^2)= (c^2+s^2)

[Anonymous No.2348475]

>>2348465
yeah, actually you end up with
sin|cos| / |sin|cos,

though I doubt that'll be important for your class.

[Anonymous No.2348485]

>>2348475

And that can simplify to 1?

How? Cancelling out/.

[Anonymous No.2348495]

>>2348447
>1) (c^4-s^4)/(c^2-s^2)
=(c^2-s^2)(c^2+s^2)/(c^2-s^2)
=(c^2+s^2)
=1

[Anonymous No.2348502]

Thnx all for help ont hat once. I just need help with one more

s√1-s^2 / c√1-c^2

I got

sin o x cos o / cos o x sin o
Any way i could cancel these out to get 1?