/sci/ - Science & Math

[Anonymous No.2096183]

find the first derivative:

10[(1/x)+(x/x+3)]

and

200[5-(9/(9+x)]

[Anonymous No.2097371]

/sci/ please help me i need help with my homework!!

[Anonymous No.2097373]

You really can't take basic derivatives?

[Anonymous No.2097374]

>>2097371
lol +5 internets for you making me laugh

[Anonymous No.2097470]

Humanity

[Anonymous No.2097490]

By the u-du substitution method they are both

ln(original function)+C

[Anonymous No.2097493]

>>2097373

i can, but when i do these two i keep getting the wrong answer and i dont know why. so i figure if i have the solutions then i can work through it knowing where im going. im only taking Calculus I..

[Anonymous No.2097508]

Pic made me lol so I'll do the first one for ya.

Derivative of <span class="math">\frac{1}{x}[/spoiler] is <span class="math">-\frac{1}{x^2}[/spoiler].

Derivative of <span class="math">\frac{x}{x+3}[/spoiler] is <span class="math">\frac{x+3-x}{(x+3)^2} = \frac{3}{(x+3)^2}[/spoiler].

So, derivative of <span class="math">\frac{1}{x} + \frac{x}{x+3}[/spoiler] is <span class="math">\frac{3}{(x+3)^2} - \frac{1}{x^2}[/spoiler], multiply by 10, you're done.

[Anonymous No.2097517]

>>2097490
Integral