/sci/ - Science & Math

[Anonymous No.2008416]

hello /sci/
i'm curious how you would answer this question:

what is the square root of 'x' squared?

[Anonymous No.2008418]

x

[Anonymous No.2008423]

The absolute value of x, or |x|.

[Anonymous No.2008425]

*sigh*

abs(x)

[Anonymous No.2008427]

Positive or negative x.

[Anonymous No.2008429]

black people

[Anonymous No.2008433]

>>2008427

[Anonymous No.2008437]

op here; hoping there are trolls in this thread

[Anonymous No.2008456]

the euclidean norm of course

[Anonymous No.2008458]

>>2008437
Hence the troll face. It's +-x, OP. The square root of (-2)^2, for example, is the square root of 4, which is positive or negative 2.

[Anonymous No.2008488]

it's not plus or minus x, it's just x.

the square root and the square cancel each other out.

[Anonymous No.2008499]

>>2008488
The square of the square root of x is just x, but not the square root of the square...

[Anonymous No.2008501]

>it's not plus or minus x, it's just x.

the square root and the square cancel each other out.

[Anonymous No.2008511]

Absolute value, niggers.

[Anonymous No.2008515]

Let x = -4.
x^2 = (-4)^2 = 16
sqrt(16) = 4
So sqrt(x^2) = |x|

[Anonymous No.2008525]

>>2008515
>sqrt (16) = 4
>mfw

[Anonymous No.2008526]

Is this what that funny | key is for?

[Anonymous No.2008530]

Nice troll due to the somewhat ambiguous language.

<div class="math">\sqrt{\left (x^2 \right )} or \left ( \sqrt{x}\right )^{2}</div>

[Anonymous No.2008533]

>>2008525
yes you are a troll

[Anonymous No.2008578]

>>2008515
>prove one case
>declare something proven

HA HA HA OH WOW.

Hay guise, <div class="math">let x=y=2</div>
<div class="math">x^{y} = 2^{2} = 4</div>
<div class="math">x \cdot y = 2 \cdot 2 = 4 </div>
<div class="math">\therefore x^{y} = x \cdot y </div>

QED LOL