/sci/ - Science & Math

[Anonymous No.1990641]

Help please? I am nub at maths (Alegbra 2 PAP)
cannot figure this out or at least I'm getting the wrong answer somehow. Please show the steps involved in solving the equation.

-2(x-1)^2=36

Attempt: + or - SQRT(6

[Anonymous No.1990652]

Bump 1 with cool pic

[strawman !!9eSatjbJatr No.1990651]

>complex numbers, how do they work?

[Anonymous No.1990657]

>>1990651
Yes, how DO they work, sir?

[strawman !!9eSatjbJatr No.1990659]

>>1990657
i bet google knows

[Anonymous No.1990673]

>>1990659
Wolfram.com knows, but it's not helping me with the current situation I am in.

Sir, I came here for help not for an explanation of how to solve the question, not some googled shit.

Thanks.

[strawman !!9eSatjbJatr No.1990689]

>>1990673
and sir, i came here because /new/ is filled with shitty election trolls and i wanted something interesting, not to do your homework for you

[Anonymous No.1990693]

>>1990689
Then don't join the conversation.

[Anonymous No.1990725]

Go back to Wolfram
Add "solve" before the equation
Click "show steps"

[Anonymous No.1990729]

<span class="math">1+2\sqrt{3}i[/spoiler]

i remember when math was that easy

[Anonymous No.1990777]

>>1990729
isn't it
<span class="math">\pm i\sqrt{18}[/spoiler]
So
<span class="math">\pm 3i\sqrt{2}[/spoiler]

Hope my TeX works.

[Anonymous No.1990782]

>>1990777
+1 of course. I ommited that just because it wasn't what I was contending.

[Anonymous No.1990783]

>>1990777
>>1990729
lol both wrong

[Anonymous No.1990791]

>>1990777
>>1990729
It's <span class="math">1±3 i \sqrt{2}[/spoiler].

[Anonymous No.1990796]

>>1990783
Mine is right according to: >>1990791

[Anonymous No.1990804]

>>1990673
<span class="math">\sqrt{-1} = i
\sqrt{-a} = i\sqrt{a}[/spoiler]

Capiche?

[Anonymous No.1990810]

>>1990804
might have helped if you had included a in your first expression

[Anonymous No.1990811]

>>1990804
Actually it's
<span class="math">\sqrt{-1} = i[/spoiler]
<span class="math">\sqrt{-a} = i\sqrt{a}[/spoiler]

Problem is i'm a noob at TeX

[Anonymous No.1990829]

What you get is a number with a real part:
<span class="math">1[/spoiler]
and an imaginary part:
<span class="math">\pm 3\sqrt{2}i[/spoiler]

Numbers with a real and imaginary part are called complex numbers.

<span class="math">i[/spoiler] is the imaginary unit and is equal to <span class="math">\sqrt{-1}[/spoiler]

[Anonymous No.1990833]

>>1990829
and to add:

<span class="math">1 + 3\sqrt{2}i[/spoiler]
and
<span class="math">1 - 3\sqrt{2}i[/spoiler]

are called complex conjugates.

[Anonymous No.1990848]

without looking at any other posts in this thread
-2(x-1)^2=36
(x-1)^2=-18
(x-1)=3i(sqrt(2))
x = 1 + 3i(sqrt(2))
howd i do?

[Anonymous No.1990878]

how2 tex?

The quadratic formula is $-b \pm \sqrt{b^2 - 4ac} \over 2a$
\bye

[Anonymous No.1990887]

>>1990878
Put it in between [eq.n] [/eq.n] or [mat.h] [/mat.h] tags (without the dots in there of course). Also, text never works well, so always get that out of the equation.

The quadratic formula is [ma.th] -b \pm \sqrt{b^2 - 4ac} \over 2a[/ma.th] without the dots will give:

The quadratic formula is <span class="math"> -b \pm \sqrt{b^2 - 4ac} \over 2a[/spoiler]

[Anonymous No.1990923]

Niggers = <span class="math">-b \pm \sqrt{b^2 - 4ac} \over 2a[/spoiler]