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/sci/ - Science & Math

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1970850 No.1970850 [Reply] [Original]

Trying to sharpen my algebra skills so I can learn calculus in my spare time. Haven't taken a formal math class in 6 years and haven't used stuff like this since. Halp me halp myself

>> No.1970857

lol, 4 reminds me of the limit definition of derivative

the memories

>> No.1970911

1 and 2 don't make sense

x/y is not equal to x*y

what you need to be doing is
j(x+h)= (3x+3h-2)/(2x+2h +3)
j(x)=(3x-2)/(2x+1)

then find a common denominator of (2x+2h+3)*(2x+1) and subtract to find j(x+h)-j(x)
(3x+3h-2)(2x+1)-(3x-2)(2x+2h+3)
all over
(2x+2h+3)*(2x+1)

simplify that and then divide by h

>> No.1971010

Yeah your method is way off. First right out the j(x + h):
(3(x+h) - 2)/(2(x+h) +3)

then right out j(x):
(3(x) - 2)/(2(x) +3)

j(x + h) - j(x):
(3(x+h) - 2)/(2(x+h) +3) - (3(x) - 2)/(2(x) +3)

You need to combine under a common denominator and then expand the equations (using the FOIL method). Let me know once you get here and I'll keep going.