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/sci/ - Science & Math


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File: 37 KB, 293x358, 6_59_baboons.jpg [View same] [iqdb] [saucenao] [google]
1905144 No.1905144 [Reply] [Original]

Business Math

Giant Dildo, a dildo company, sells 1 dildo to a new customer every day. 1/5 of there customers become repeat buyers and return to buy a new giant dildo every month and a half.

How many dildos will Giant Dildo sell there first year of business?

pic somewhat related

>> No.1905168

365 x 1/5 = 73

73+365= 438 sales newfag.. this isnt 2nd grade

>> No.1905178

>>1905168
Dumbfuck. Multiply 73 by 8.

>> No.1905200

>>1905178 but not all 73 are gonna repeat 8 times

>> No.1905228

i think i could take on 14 baboons with a giant dildo

>> No.1905258

8 x 45,625 + (7 x 45,625 / 5) = 428.875

>> No.1905269

im really not sure, but 697??? really simple math, but the reasoning takes some thinking.

>> No.1905273

>>1905258

nice

>> No.1905284

Hey op, you need to do a summation. They sell 30 a month regardless from constant new customers, then they sell (1/5)*30 more each month. so
<div class="math"> \sum_{i=0}^12 6x+30</div>

>> No.1905280 [DELETED] 

Hey op, you need to do a summation. They sell 30 a month regardless from constant new customers, then they sell (1/5)*30 more each month. so
<div class="math"> \sum_{i=0}^12 6x+30[\eqn]</div>

>> No.1905292 [DELETED] 

>>1905284
fuck

<div class="math"> \sum_{i=0}^(12) 6x+30</div>

>> No.1905295

>>1905284
fucked that up
<div class="math"> \sum_{i=0}^{12} 6x+30</div>

>> No.1905339

>>1905295
how do you figure that out? guess it isnt simple math

>> No.1905351
File: 1 KB, 214x179, sum of c is n times c; sum of c times j is cn times (n+1) over 2; sum of c times j squared is cn times (n+1) times (2n+1) over 6.gif [View same] [iqdb] [saucenao] [google]
1905351

>>1905339
>simple math

Actually pretty easy

>> No.1905363

>>1905351
How do you make a picture like that?

>> No.1905381

>>1905363

I just copied it from a website and posted it.

>> No.1905380

>1/5 of there customers become repeat buyers
Why would someone buy so many dildos?

>> No.1905382

>>1905380
To start a war with bigots. Beat them with giant dildos.

>> No.1905386

>>1905295
your formula is flawed, it implies that everyone who are re-purchasers in the first month will purchase a second dildo in the second month. which we know they wont because of the month/half delay.

>> No.1905387

>>1905380
Why wouldn't someone buy so many dildos?

>> No.1905403

>>1905380
the majority of customers are engineers

>> No.1905406

>>1905386
Hmm, didn't read that, good point. Just multiply the 6x by 2/3 since they're buying it at two thirds the rate. So

<div class="math">\sum_{i=0}^{12} 4x+30</div>

>> No.1905408
File: 23 KB, 485x323, 20081111-hardcore-gay-sex_0.jpg [View same] [iqdb] [saucenao] [google]
1905408

>>1905144
Sounds more like "engineering math"

>> No.1905418

>>1905403
>>1905408
You have just been banned, have a nice day.

>> No.1905422

>>1905406
I hate that mathematical E
Its intimidating

>> No.1905457

>>1905406
so that's the answer? what is that approximately

>> No.1905471

>>1905457
I solved to = 624. but keep in mind that with the formula 4x+30, the first month is month zero.

>> No.1905717

>>1905471

Actually the first month is 30 with that formula

>> No.1907049

>>1905380
Apparently, they're being worn down.

>> No.1907301

Let's consider every customer as the total number of purchases they make this year.

Every customer that makes a purchase in January makes a total number of 1 + 0.2(11/1.5) purchases this year. That's 2.47 purchases per customer in January. That's 2.47 * 31 = 76.47

Following the pattern, the number of sales in February is 28*(1 + 0.2(10/1.5)) = 65.33
March: 31*(1 + 0.2(9/1.5)) = 68.2
April: 30*(1 + 0.2(8/1.5)) = 62
May: 31*(1+0.2(7/1.5)) = 59.93
June: 30*(1+0.2(6/1.5)) = 54
July: 31*(1+0.2(5/1.5)) = 51.67
August: 30*(1+0.2(4/1.5)) = 46
September: 31*(1+0.2(3/1.5)) = 43.4
October: 30*(1+0.2(2/1.5)) = 38
November: 31*(1+0.2(1/1.5)) = 35.13
December: 30

Total: 630.13

>> No.1907314

It depends on when those repeat buyers show up... If the buyers occur in the pattern (nonrepeat, nonrepeat, nonrepeat, nonrepeat, repeat), the result would be different if it the repeat buyer was the FIRST buyer. Also, who's to say that the 73 repeat buyers are all the last people to buy the dildos? As in, from January to September, no repeat buyers. Problem needs to be defined further if you want a precise answer.