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/sci/ - Science & Math

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1770579 No.1770579 [Reply] [Original]

so im driving at light speed and i turn my headlights on, what happens?

>> No.1770580

but you can't drive at light speed.

>> No.1770581

you get sage'd

>> No.1770585

oh man, i'm starting to hallucinate about physicist cleffas all over the place now

>> No.1770587

>>1770580
>>1770581
good answer thanks guys!
you know /sci/ is supposed to be the center of light and education on four_chan(dot)org
but really you guys are dicks just like /lit/

i mean come on im not asking you to do my homework or some shit

bitches

>> No.1770589

Speeding ticket.

>> No.1770590

Okay, serious response: You see the light move forward at the speed of light. It has to do with the relativity of simultanea. Relativity states that there is no absolute reference frame or speed, and that no objects are absolutely at rest. When you hit light speed and turn on your headlights, you see the light move forward at light speed. It's fucked up, but it's true.

>> No.1770592

plus this exact question, WORDED the same, gets postet every freakin day.

>> No.1770612

>>1770587
hey. 1770580 here. my answer was totally serious. you can't drive at light speed, that's an integral part of special relativity. the only thing that can move at light speed is light, and it is separate from the observation ordeal.

one of the two axioms of special relativity is that light moves at light speed all the time, at all points of observation. you obviously know this because otherwise you wouldn't have identified a problem with driving at light speed and turning on a light, which shines forward.

the reason this doesn't work is given by the formula for v

v/c = sqrt(1 - (1 / gamma)^2)

by the way, v is the speed you're travelling at, c is the speed of light a constant, and gamma is the coefficient (well sort of) that you use to calculate your relative difference to another frame
if v = c

c / c = 1

1 = sqrt(1 - (1 / gamma)^2)
1 = 1 - (1 / gamma)^2
1 - 1 = 1 - (1 / gamma)^2 - 1

0 = - (1 / gamma)^2
0 = (1 / gamma)^2
sqrt(0) = sqrt(1 / gamma)^2
0 = 1 / gamma

the simple way to prove that it is wrong is

0*gamma = 1 / gamma * gamma

by the axiom 0*a = 0

0 = 1

which is incorrect. but you should know 1 / anything cannot = 0. thus within the definitions of special relativity it is impossible to go at the speed of light. if you are not talking about within the definitions of relativity, then you wouldn't be asking this question because then you wouldn't have the assumption that something weird would happen due to the axiom about the speed of light being the same for all observers. that's all.

>> No.1770613
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1770613

op here
this shits hella homo im off to dump this hott ass set of princess jasmine busting a hott nutt in jafars gook ass

>> No.1770614

>>1770589
/thread

>> No.1770619

Not only do you see the light from your headlights traveling at light speed but everyone that sees the light from your headlights sees it traveling at the same speed.

>> No.1770621

>>1770613
WTF. I keep seeing this.

Can someone explain? I've never seen the set, if there even is one.

>> No.1770661

>>1770619
If they see your headlight light travelling at light speed then doesn't that mean they see you standing still since you are moving a light speed less than the headlight speed

>> No.1770665

>so im in an impossible situation, what happens?

>> No.1770671

for the love of gawd.

everybody always sees the damn light travel at the speed of light. One ray of light flying next to the other sees it traveling the speed of light, and vice versa. If you're gonna troll about the implications, study physics, or at least l2 maxwell.