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1751526 No.1751526 [Reply] [Original]

Can anyone help me on this hw problem?
A mixture of 0.10mol of NO, .05mol of H2, and .10 mol of H2O is placed in a 1.0- vessel at 300K.
The following equilibrium is established: 2NO+2H2-->N2+2H2O
At equilibrium [NO]=.062M
Calculate equilibrium (Kc) of H2, N2, and H2O

pic sort of related

>> No.1751616

make an ICE table nigga (Initial, change, equilibrium)

NO H2 N2 H20
I 0.10 0.05 0 0.10
C -x -x 0.5x +x
E 0.062 0.05-x 0+0.5x 0.10+x

0.062=0.10-x
x=0.038

THEREFORE, [NO]= 0.062M, [H2]= 0.012M, [N2]= 0.019M, [H2O]= 0.138M

i think i fucked up...

>> No.1751708

>>1751616
nah, dude. you're solid. thanks much for the help.