[ 3 / biz / cgl / ck / diy / fa / ic / jp / lit / sci / vr / vt ] [ index / top / reports ] [ become a patron ] [ status ]
2023-11: Warosu is now out of extended maintenance.

/sci/ - Science & Math

View post   
File: 65 KB, 640x480, supchester.jpg [View same] [iqdb] [saucenao] [google]
1606724 No.1606724 [Reply] [Original]

Could someone please take the time to assist me with this problem?

Write the equation in standard form of the ellipse with foci (8, 0) and (-8, 0) if the minor axis has y-intercepts of 2 and -2.

I haven't dealt with conics in over a year and I knew these dirty bastards would come back to haunt me.

This thread is also an opportunity for me to show off my cat.

>> No.1606727
File: 192 KB, 2048x1536, IMG00012-20100814-0605.jpg [View same] [iqdb] [saucenao] [google]
1606727

Picture within picture edition.

>> No.1606729

bamp because you dont want the solution

>> No.1606733
File: 900 KB, 569x615, chester_092.png [View same] [iqdb] [saucenao] [google]
1606733

>> No.1606735
File: 3 KB, 127x127, kerrr.jpg [View same] [iqdb] [saucenao] [google]
1606735

>>1606729

WHAT did you just say to me?

>> No.1606743

If the foci are where you claim they are, the center is at (0,0), and the minor axis should be entirely on the y axis.

Do you mean that the ellipse itself has y intercepts of 2 and -2? They are on the minor axis, if that's any consolation...

>> No.1606746

Post more cat.

>> No.1606764
File: 1.25 MB, 896x672, IMG00016-20100814-1048.png [View same] [iqdb] [saucenao] [google]
1606764

>>1606743
Eh, of some assistance but still............ no.
Much love though.

>>1606746
Do you liek Shark Week?

>> No.1606774
File: 263 KB, 1792x1344, IMG00020-20100814-1052.jpg [View same] [iqdb] [saucenao] [google]
1606774

luvin lyf

>> No.1606787
File: 241 KB, 1792x1344, IMG00014-20100814-1049.jpg [View same] [iqdb] [saucenao] [google]
1606787

>> No.1606802
File: 51 KB, 640x480, !uno.jpg [View same] [iqdb] [saucenao] [google]
1606802

I guess it's time to post a lap dance in progress.

1/8

>> No.1606806
File: 691 KB, 599x446, !duex.png [View same] [iqdb] [saucenao] [google]
1606806

So he approached me...

2/8

>> No.1606811
File: 649 KB, 549x449, !treee.png [View same] [iqdb] [saucenao] [google]
1606811

....with a slutty proposition.

>> No.1606812
File: 55 KB, 640x480, !four.jpg [View same] [iqdb] [saucenao] [google]
1606812

Eh, not sure if want?

4/8

>> No.1606814
File: 52 KB, 640x480, !fidorra.jpg [View same] [iqdb] [saucenao] [google]
1606814

Alright, we'll see...

5/8

>> No.1606817
File: 53 KB, 640x480, !666.jpg [View same] [iqdb] [saucenao] [google]
1606817

Continue.

6/8

>> No.1606823
File: 604 KB, 518x446, !7.png [View same] [iqdb] [saucenao] [google]
1606823

Kinda gettin' into this.

7/8

>> No.1606825
File: 54 KB, 640x480, !8.jpg [View same] [iqdb] [saucenao] [google]
1606825

He wanted me.

8/8... jk one more.

>> No.1606827
File: 52 KB, 640x480, !end.jpg [View same] [iqdb] [saucenao] [google]
1606827

Got some.

>> No.1606834

The sum of distances to the foci is equal to the major diameter. The distance from (8, 0) to (0, 2) is sqrt(68), and by symmetry it's the same to the other focus, so the semimajor axis is sqrt(68).

Hence the equation in standard form is
x^2/68 + y^2/4 = 1.

>> No.1606841

>>1606834

Forever indebted to you.
I appreciate it times a zillion.
<3