[ 3 / biz / cgl / ck / diy / fa / ic / jp / lit / sci / vr / vt ] [ index / top / reports ] [ become a patron ] [ status ]
2023-11: Warosu is now out of extended maintenance.

/sci/ - Science & Math


View post   

File: 50 KB, 678x525, apu.png [View same] [iqdb] [saucenao] [google]
15032893 No.15032893 [Reply] [Original]

Hey frens.
I'm in a wooden box factory. Boxes are from 0 to 1m in length.
I'm having a bet with my friend on what's the average length of a box be.
Which value should I take?
Thanx frens

>> No.15033089

Whats the box's length distribution ? Is it uniform ?

>> No.15033093

>>15032893
>from 0 to 1m in length
>0 in length
???

>> No.15033126

>>15033089
idk me and my friend are both autistic so we don't have the balls to ask anyone
I'm just looking for a sensible value that I should use
what do you guys think?

>> No.15033129

>>15032893
Without knowing the probability distribution of lengths there is actually no way to know. I would just arbitrarily put it at 0.3 for fun

>> No.15033133

One yard.

>> No.15033146

>>15033129
so all values are equally likely?
wouldn't that make expected average value 0.5?

>> No.15033149

>>15032893
If by average you mean the most common then they are all equaly likely, otherwise it's 0.5 me thinks.

>> No.15033174

>>15033149
>If by average you mean the most common then they are all equaly likely
Yeah but if they're all equally likely, then the average value will be 0.5 right?

>> No.15033285

>>15033174
yes

>> No.15033299

>>15033285
Ok but what if we bet on the area of the cube side?
Would the average value be 0.5 m^2 or 0.25 m^2?

>> No.15033301

>>15033126
I think you should get over your social anxiety and ask your boss what the distribution of lengths is. Don't wallow in your mental illness, try to fix it
(yes I am aware that you're larping)

>> No.15033303

>>15033174
Yes, it will be 50% because it either happens or it doesn't

>> No.15033350

>>15033301
This is a great example of thinking outside of the box.

Heh, heh. Get it?