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/sci/ - Science & Math


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1453436 No.1453436 [Reply] [Original]

http://www.wolframalpha.com/input/?i=%2836%29^%281%2F2%29%3D-6

how the fuck is it false? (-6)*(-6)=36

>> No.1453447

How is it not? The square root of 36 is 6.

>> No.1453467

no.

>> No.1454018

PLEASE tell me you're trolling

>> No.1454036

That's interesting

anyone with a deeper knowledge of Alpha know what's up here? -6^2 is definitely 36

>> No.1454040

you just went 250% retard, op

in case you don't get this, you went (250²)^½ % retard

>> No.1454049

you just went 250% troll, op

in case you don't get this, you went (250²)^½ % troll

>> No.1454065

>>1454036

just because (-6)^2=36 doesn't mean that the square root of 36 = -6. Go re learn basic math

>> No.1454086

http://www.wolframalpha.com/input/?i=((36)^(1/2))^2%3D(-6)^2

>> No.1454089

>>1454065
it's +/-6. Neither is more correct than the other.

>> No.1454097

>>1454089
Only shred of intelligence in this thread.

>> No.1454101

Radical 36 produces two roots, +6 and -6. The negative is usually omitted as it doesn't have physical applications, and wolfram follows this convention it appears.

>> No.1454108

The 6 is squared, then the minus sign operates on it. Same thing happens on Ti Calculators.

>> No.1454128

>>1454101
if your direct, explicit input is that it's -6 I think it's pretty misleading to show this as incorrect. For us, it's fine (we know it is both) but for x number of high schoolers checking their math on the web this is going to confuse and distort the truth

>> No.1454130

>>1454089
The square root is defined as "the positive number that squared gives x"

That's why you put the +- symbol when you want to use both.

>> No.1454151

order of operations up in this bitch

>> No.1454161

ITT: noone knows what a function is.

The square root function is, guess what, a fucking function.
That is: you plug one value in and you get one value out.
The value you get by definition is the unique positive number x for which x^2 equals the number you put into the square root function.

Guess what: 1^(1/100) has 100 hundred distinct solutions in the complex numbers, but as a function you'll get back the value 1.
Now stfu and die in a stamp collecting related accident, you shit stain of society.

>> No.1454164

>>1454101
>The negative is usually omitted as it doesn't have physical applications
>it doesn't have physical applications
Never done physics, have you? Analytical solutions to elastic potentials often require the negative solution to a square root.

The square root has two solutions. Always. Any physicist knows this.

>> No.1454186

>>1454161
>High school mathematical semantics
>Ignores an equally cardinal set of valid solutions
>Never would have discovered anti-particles.

>> No.1454285

>>1454186
omg, the mere possibility that you're serious makes me wanna kill you over and over again. My fucking god...

Look, the square root function is simply defined that way. It has to return only one of the two values, because a function doesn't yield more than one value, ever.
Technically a function is a special kind of relation. Say f : X -> Y, then technically, f is a subset <span class="math">f \subset X \times Y[/spoiler] such that for each x in X you have <span class="math">|{ (x,y) \in f }| = 1[/spoiler]. That is: every input yields exactly one fucking output. What don't you understand about this you raging fuckshit?

I'm very well aware, that the algebraic equation X^2 - a has two fucking solutions, so go fuck yourself. Infact, I've pointed out that there are 100 distinct 100th roots of unity in the complex plane, what don't you understand about this?

>> No.1454297

>>1454285
*for each x in X you have <span class="math">|\{(x,y) \in f\}| = 1[/spoiler]
(forgot the fucking backslashes)

>> No.1454345

>>1454297
actually, let me rewrite that again:
for every x in X you have <span class="math">|\{ y : (x,y) \in f \}| = 1[/spoiler].
There, now I feel less dirty.

>> No.1454369

>>1454186
what the fuck is an equally cardinal set?

>> No.1454410

>>1454369
It's a term 3rd graders use to troll math students.