[ 3 / biz / cgl / ck / diy / fa / ic / jp / lit / sci / vr / vt ] [ index / top / reports ] [ become a patron ] [ status ]
2023-11: Warosu is now out of extended maintenance.

/sci/ - Science & Math


View post   

File: 366 KB, 900x2216, 1268338797376.gif [View same] [iqdb] [saucenao] [google]
1260887 No.1260887 [Reply] [Original]

Dear /sci/

I have a question. Say you have a video stream, and you have the total amount viewer minutes accumulated over a series of days If you divide the amount of minutes by the total days, you'd get the average amount of viewer minutes per day right?

Secondly, if you take the average amount of viewer minutes per day and divide it by the amount of minutes in a day, would that give you the average amount of viewers per day?

Thank you kindly,

in return: something science related

>> No.1260920

OP here, for example:

3,568,702 (total viewer minutes as of 4:30 PM) / 115 (total days active) = 31,032 viewer minutes per day
31,032 (viewer minutes per day) / 1440 (total amount of minutes per day) = 19 (viewers per day)

>> No.1260927

OP here again with second example


276,063 (total amount of viewer minutes for as of 5:30) / 64 (amount of days active) = 4,313 (viewer minutes per day)
4,313 (viewer minutes per day) / 1440 (total amount of minutes in a day) = approx. 3 (viewers per day)

>> No.1260943

>>1260927
2) No, approximately 3 viewers at any given time of the day.

>> No.1260953

Is it possible to determine the average amount of viewers per day with just this information?

>> No.1260985

shameless self bump for help

>> No.1261011

god damn it /sci/

i thought you'd help.

>> No.1261024

>>1260953
not unless you know how long they stayed for. It could be the same 3 people all day, or lots of people tuning in then tuning out a minute later.

>> No.1261063

damn, thank you for your help