/sci/ - Science & Math

[Ҝӏӆӡ-ҔцԎҬ !Clme9Vzxag No.1249243]

Apologies in advance, but /g/ was being completely unhelpful with this (too busy arguing over graphics cards and AMD vs Intel).

So there's a Dell laptop AC adapter in the lost and found drawer at work with the same connector as the one for my HP laptop.
The HP AC adapter has an output of 18.5V at 3.5A, while the Dell has an output of 19.5V at 4.62A.

Would this thing kill my laptop if I tried to use it?

[Anonymous No.1249248]

>>1249243

There is potential.

Pun intended.

[Anonymous No.1249251]

>>1249248
Only on /sci/...

[Ҝӏӆӡ-ҔцԎҬ !Clme9Vzxag No.1249254]

>>1249248

[Anonymous No.1249256]

>>1249248
came short

[Anonymous No.1249278]

I really don't think that it would hurt. worst that could happen is that your computer bursts into flames

[Anonymous No.1249282]

>>1249240
ＲｅＭoｅV yuｏR_ＩｌｌＧＥＡl ＣlＯｅn_FO_HtＴＰ://wＷｗ.AＮTｏＮｙＴａLk.ｓＥ/ (aｎTｏnｙ = ＡnｏＮ) ｉＭMeIｄＡtely. s zljsvuzz mwdgc tovuwcwo aaiw x d seqr

[Anonymous No.1249286]

I guess in this case you'd just use ohms law
I=V/R
I being the current, V being the voltage and R being the resistance
so the first one is
18.5/3.5=5.28
and the second one is
19.5/4.65=4.19
So the Dell AC adapter actually has less current than the HP AC adapter
I'd say its safe to give it a try

[Spontaneous !!gfzNzzf0qlY No.1249287]

So you have a bit smaller current going through, nothing bad can happen, but it'll take longer to charge the battery. Do it OP.

[Anonymous No.1249293]

>>1249286
>>1249287

You sure you've read things correctly?

[Spontaneous !!gfzNzzf0qlY No.1249309]

I guess I had it backwards, I tend to skim through important information, OP the voltage difference is only about 1V, which really isn't a lot at all. Go for it.

[Anonymous No.1249304]

>>1249293
Either they didn't, or they misunderstood that lesson. The current is the number with the A after it, and resistance isn't coming in to play here.

[Anonymous No.1249301]

Don't use it, the difference between 3.5A and 4.62A is too high. It will send WAY too much electricity through your computer's system, likely frying the weaker circuits.

[Anonymous No.1249313]

Your laptop should only take as much power as it needs.

[Anonymous No.1249326]

>>1249313

It should, huh? Well, sir, this is an American laptop, not a COMMUNIST laptop! Take yer Marxism back to Apple!

[Anonymous No.1249328]

>>1249309

Please read this comment:
>>1249301

[Ҝӏӆӡ-ҔцԎҬ !Clme9Vzxag No.1249333]

>>1249301
Thanks.

[Ҝӏӆӡ-ҔцԎҬ !Clme9Vzxag No.1249342]

>>1249326
Actually, it was manufactured in China, so I guess it is a communist laptop.

[Anonymous No.1249344]

>>1249287
>>1249286
You seem to have no idea of electricity:
I = current, measured in amperes (A), the amount of electricity running through
V = voltage, measured in volts (V), the "strength" of the electricity
R = Resistance, measured in ohm (Ω), how hard a certain material resists having electricity run through it
P = Power, measured in watts (W), how much net energy runs through the system (that's what he was trying to, and failing in, calculating)

It's the amperage that kills the circuits (and people, btw), not the voltage. If the adapter has a higher amperage output than the computer is made to handle, DON'T USE IT.

[Anonymous No.1249346]

I'm sure its a switching power supply; the Dell adapter will feed 19.5V until your HP dies.

[Anonymous No.1249350]

>>1249326
I liek

[Anonymous No.1249356]

>>1249344

Voltage also kills btw. Ever had your ribcage constricted so that you can't breathe by your own muscles?

[Anonymous No.1249357]

>>1249301
The adapter supplies up to 4.62A at 19.5V.

It will always supply 19.5V. If your computer draws less than 4.62A at that voltage, the adapter supplies less than 4.62A.

It's not going to push four amps through a computer only using two.

[Anonymous No.1249364]

>>1249344
Oh I looked it up, I got it mixed up...
OP should use the Watt formula
W = VA
That one is kind of self-explanatory
so yeah don't do it faggot...