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/sci/ - Science & Math


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11604521 No.11604521 [Reply] [Original]

0.999... + 0.000... 001=1

>> No.11604535
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11604535

0.999....-0.000...001=1

>> No.11604539

>>11604521
Yes, adding 0 to a number does give back that same number.

>> No.11604543
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11604543

>>11604539
>Yes, adding 0 to a number does give back that same number

>> No.11604545

0.999...+ 0.999...=2

>> No.11604561
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11604561

>>11604545
[math]\sum^\inf_1{0.00...1}=1[/math]

>> No.11604569

>>11604561
[eqn]\sum^\inf_1{0.00...1}=1[/eqn]

>> No.11604580
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11604580

>>11604545
.999... + .999... = 1.99..8

>> No.11604608

>>11604569
multiply both sides by 10 and you get
[eqn]\sum^\infty_1{0.00...1}=10[/eqn]
thus
[eqn]
10 \sum^\infty_1{0.00...1} = \sum^\infty_1{0.00...1} \\
9 \sum^\infty_1{0.00...1} = 0 \\
\sum^\infty_1{0.00...1} = 0 \\
[/eqn]
therefore [math]0.00...1=0[/math]

>> No.11604609

>>11604521
No, because 0.999... is infinitely repeated while the 0s in 0.000...01 eventually end, meaning it repeats a finite amount of times.

>> No.11604618
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11604618

>> No.11604627

>>11604609
something can end with infinite things before it ends

>> No.11604628

>>11604627
If it ends, it’s not infinite, it’s finite.

>> No.11604631

>>11604627
Prove it.

>> No.11604643

>>11604628
>>11604631
There are infinite points in [0,1) and 1 comes after. You should finish high school before posting here

>> No.11604644

>>11604643
But there aren’t infinitely many, it ends.

>> No.11604649

>>11604631
how do i prove things

>> No.11604660

>>11604644
>there aren't infinitely many points in [0,1)
Retard

>> No.11604680

>>11604643
That's a different thing entirely. If you were to list all of the numbers in [0,1) and then put 1 at the end of that list, you would not be able to, because the list would never end, since there are infinitely many numbers in [0,1).

>> No.11604722

>>11604680
That's what the ... is there for. Obviously you can't physically list all the 0s, it's math. By your reasoning 999999999! doesn't exist because nobody has listed all the integers up to 999999999!

>> No.11604855

>>11604569
0.1=10^-1
0.01=10^-2
0.001=10^-3
:
0.0...1=10^-inf=0

>> No.11604862

>>11604521
Only if the amount of 9s in the former is greater than the amount of 0s following the decimal in the latter by 1

>> No.11604864
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11604864

>>11604521
Fuck off, retard.

>> No.11604919

>>11604864
Brainlet here, actually curious: if 0.999.......=1, then 6,999.....=7, n.99999....=n+1? (this notation probably doesn't exist but you know what i mean)

>> No.11604932

>>11604919
Thats correct

>> No.11604934

>>11604919
0.123999... = 0.124

>> No.11604953

>>11604722
Your obvious straw man is obvious and also isn't relevant.
He's pointing out that if you made of list of the numbers in [0,1) it would not terminate, so there is no last number that you can put before you put a 1 at the end.
0.999... is the number that the list would be approaching. It can also be shown easily that its approaching 1, which is why the two numbers are equal.

>> No.11604959

>>11604521
I love how easily these threads reveal the brainlets on this board who don't understand basic concepts like limits

>> No.11605377

>>11604627
>something can end with infinite things before it ends
no such things represents a real number though