/sci/ - Science & Math

[Anonymous No.11535641]

Can /sci/ solve this?

[Anonymous No.11535647]

Trivial and left to OP as an exercise.

[Anonymous No.11536359]

>>11535641
What's a trig substitution OP?

[Anonymous No.11537336]

>>11536359
My highest level of math knowledge is college algebra

[Anonymous No.11537345]

>>11537336
Algebra is a pretty high level topic, anon, how the fuck do you know algebra without knowing basic integral calculus?

[Anonymous No.11537346]

>>11535641
those are some weird powers on the top
brainlet.jpg
It is arctan(x/carrot) evaliated from 0 to 1 I think btw

[Anonymous No.11537379]

>>11537345
Well I might've skipped it in highschool since I started taking college classes halfway through it and only needed a couple math credits.
I vaguely recognize it but don't remember how to do it at all.

[Anonymous No.11537537]

>>11536359
idk
but if sin(x) ~= x for small x,
then can you write [math]\frac{1}{\sqrt{a^2-x^2}}=\frac{1}{\sqrt{a^2-sin^2(\frac{x}{\infty})}}[/math], then substitute [math]cos^2(\frac{x}{\infty})=1-sin^2(\frac{x}{\infty})[/math], multiply the whole thing by [math]a[/math], then solve for [math]\int_0^1 \frac{dx}{a\,cos^2(\frac{x}{\infty})}=\int_0^1 \frac{dx}{a}[/math] where [math]a=carrot[/math]?

[Anonymous No.11538052]

>>11535641
This is literally just a basic calculus question. The problem is du/(sqrt(a^2 - x^2)) with the antiderivative being arcsin(x/a). This is a definite integral, so
arcsin(1/a) - arcsin (0/a). There is your answer.

[Anonymous No.11538145]

>>11537537
wtf just sub in x=a*sin(u)
cant believe im falling for this bait

[Anonymous No.11538175]

>>11535641
final answer: arcsin(1/carrot), assuming carrot is not equal to 0.

[Anonymous No.11539201]

answer is arcsin(1/carrot)

[Anonymous No.11539219]

>>11535641
Arcsin(1/^)