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/sci/ - Science & Math


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11507816 No.11507816 [Reply] [Original]

hello anons, very original thread idea
prove to me that 0.999... is equal to 1.
ive seen alot of threads about this topic pass around but ive never seen an actual conclusive answer.

>> No.11507839

10x=9.99999...
- x=0.99999...
——————————
9x=9
x=1

If x=0.999...
and x=1
then 0.999...=1

>> No.11507860

3/3 = 1
As is demonstrated in your pic, .999... = 3/3
Therefore .999... = 1 :)

>> No.11507884

>>11507816
If the picture you posted doesn't convince you I have nothing to say because there's no way of putting it in simpler terms
You're just stubborn
1) decompose 0.999... in fractional form
2) get 3/3
What does a/a ALWAYS equal to when a∈R and a≠0?

>> No.11507887

>>11507816
You wouldn't understand the proof anyways. This thread is a troll and waste of time.

>> No.11507894

>>11507884
Not stubborn, I had always thought that it was equal to 1 but some people say the weirdest shit just to not make it equal 1.
>>11507887
show us the proof bigman

>> No.11507902

>>11507816
shitty thread
https://en.wikipedia.org/wiki/0.999......

>> No.11507916

>>11507816
You will never see proof that 0.99 equals 1, because it's a religious belief.

>> No.11507925

>>11507816
Does this mean that you can't truly divide something into perfect thirds? One piece will always be .00000000000000000000000000000000000~1 more than the other two pieces

>> No.11507933

>>11507925
the world is not constrained by our base ten number system

>> No.11507960

>>11507933
probably the the best response of the thread

>> No.11507972

>>11507933
I mean to divide something into perfect thirfs outside of abstractly is seemingly impossible. How woukd you assure you have the same number of atoms or electrons. I guess you could seperate three electrons or something really small, but anything large would be hard

>> No.11507985

This is how I make sense of it in my head so it's not a mathematical proof or anything but hear me out.
Say we start with 0.9 or 9x10^-1
Then we add 9x10^-2 to get 0.99
And so on infinitely until you get 0.999....

If we put these points on a graph, we can see that our number gets closer to 1 each time we add another 9x10^-n
In fact, every time we add another 9, the difference between 1 and our number decreases expressed by 1x10^-n
When n is infinity, the number is infinitely close to 1, and the difference between 1 and the number is infinitely small i.e. 0
Therefore 0.999... = 1

>> No.11508001

0.999...+0.000...1=1

>> No.11508009

0.9999 has oneness
Aristotle eat a dick

>> No.11508015

>>11508001
Yeah but 0.999... = 1 and 0.000...1 = 0 so:
0.999... + 0.000...1 = 1 + 0 = 1

Math still checks out.

>> No.11508034

>>11507972
I mean to divide something into perfect tenths outside of abstractly is seemingly impossible. How would you assure you have the same number of atoms or electrons. I guess you could separate ten electrons or something really small, but anything large would be hard

>> No.11508046

0.999...

what does it mean?
0 is a number
. is a decimal indicator
9 is a number

but what does "..." mean?
continued? Repeating?

laziness, is what it is.
Not lazy for unwilling to write out more 9's. No. Rather, the laziness is the invention and loose application of what "..." is meant to define.
Laziness in failing to analyze the meta differences between fractional and decimal notation. Laziness in failing to analyze the meta act of what it means to try solving a maths problem.

1/3 != 0.3
1/3 != 0.33
1/3 != 0.333
1/3 != 0.3333
as you continue the steps towards attempted solution, it becomes clear that the repeating number you're writing doesn't even equal the fractional division.
And that raises a question of how many significant digits in the decimal do you actually need to simply settle for "close enough"?

Well, /sci/?
How many decimal digits of accuracy are required before we can just say it's close enough and apply rounding to the final digit?
15? 30? 60?

>> No.11508054

>>11508046
>how many significant digits in the decimal do you actually need
no finite is enough --> infinite

>> No.11508057
File: 4 KB, 256x242, Untitled.jpg [View same] [iqdb] [saucenao] [google]
11508057

You mad, broham?

>> No.11508064

>>11508054
infinite is far too much. You can't even work with it or calculate it. It's too big for your tiny pea sizes brain to comprehend.

>> No.11508068
File: 144 KB, 1024x762, 1584671966812.jpg [View same] [iqdb] [saucenao] [google]
11508068

>>11507816
Not this fucking thread again.

>> No.11508073

>>11508064
>You can't even work with it
1/inf=0, no problem

>> No.11508075

There are infinitely many numbers between a and b, where a =/= b.

Because you can "define" one number, and it is also countably singular (.00...1), .999... and 1 must not be different numbers since the set of numbers containing only {.00...1} is not infinitely large.

.999... =/= 1 is an illusion.

>> No.11508082

>>11508073
1/magical chinese dragon = 0 too, whats your point?
Do you find value in asking how many times a non-number goes into 1?

... do you take brain medecine?

>> No.11508089

>>11508082
https://www.wolframalpha.com/input/?i=1%2Finf

show your reference

>> No.11508092

>>11508075
"0.999... = 1" is functionally the same as saying "0.999... doesn't even exist"

You can't prove that 0.999... doesn't exist, and I'm unfalsifiable in my justification because infinity itself is unproveable, and my attribution of 0.999... hinges on infinity.

You must submit.

>> No.11508094

>>11508092
>"0.999... = 1" is functionally the same as saying "0.999... doesn't even exist"
nope
0.9... exists, and is as large as 1

>> No.11508098

Just as [math]\frac{1}{3}[/math] doesn't have a direction translation in decimal, neither does [math]0.\overline{999}[/math] have a direct translation into fractional.

Decimal != Fractional
English != German
0.999... != 1

>> No.11508100

>>11508098
>English != German
>0.999... != 1
ooooooooh science
>kek these idiots are hilarious

>> No.11508103

>>11508094
Numbers are unique you double retard. X=Y only when X and Y are the same goddamn number.

0.9 != 1
0.99 != 1
0.999 != 1
0.9999 != 1
...
0.999... != 1

It onpy gets to equal 1 if you round on the last digit, which necessarily requires a last digit, which means you're treating infinite as finite.

>> No.11508113

>>11508103
>X=Y only when X and Y are the same goddamn number
well we're in luck then

>0.9999 != 1
>...
>0.999... != 1
nope, finite isn't infinite
duh

>> No.11508114

>>11508103
>you're treating infinite as finite.
classic projection

>> No.11508117 [DELETED] 

[math]\sum_{n=1}^{\infty} \frac{9}{10^n} = [ \frac{9}{10^1} + \frac{9}{10^2} + frac{9}{10^3} + .... + \frac{9}{10^{\infty}} ] = [ \frac{9}{10} + \frac{9}{100} + \frac{9}{1000} + ... + \frac{9}{\infty} ] = [ 0.9 + 0.09 + 0.009 + ... + 0] = 0.\overline{999}0 \neq 1.\overline{000} [/math]

>> No.11508123
File: 59 KB, 960x960, 1538640230591.jpg [View same] [iqdb] [saucenao] [google]
11508123

>>11508113
infinite doesn't mean what you think it means, bozo.

>> No.11508127

[math]\sum_{n=1}^{\infty} \frac{9}{10^n} = [ \frac{9}{10^1} + \frac{9}{10^2} + \frac{9}{10^3} + .... + \frac{9}{10^{\infty}} ] = [ \frac{9}{10} + \frac{9}{100} + \frac{9}{1000} + ... + \frac{9}{\infty} ] = [ 0.9 + 0.09 + 0.009 + ... + 0] = 0.\overline{999}0 \neq 1.\overline{000} [/math]

>> No.11508130

>>11508123
I agree with WA

https://www.wolframalpha.com/input/?i=infinity
An unbounded quantity that is greater than every real number.

>> No.11508131

>>11508127
no

>> No.11508140

[math] \displaystyle
\boxed{0 < p < 1} \\
p^n-1 = (p-1)(p^{n-1}+p^{n-2}+ \dots +p+1) \\
\dfrac{p^n-1}{p-1} = \sum \limits_{j=0}^{n-1}p^j \\
\displaystyle
\lim_{n \to \infty} \dfrac{p^n-1}{p-1} = \lim_{n \to \infty} \sum \limits_{j=0}^{n-1}p^j \\
\displaystyle
\dfrac{0-1}{p-1} = \sum \limits_{j=0}^{\infty}p^j \implies \dfrac{1}{1-p} = \sum \limits_{j=0}^{\infty}p^j
[/math]

[math] \displaystyle
p=0.1 \\
\dfrac{1}{1-0.1}=\frac{10}{9} = 1 + \frac{1}{9} \\
\sum_{j=0}^\infty 0.1^j= 1 + \sum_{j=1}^\infty 0.1^j \\
9+1=9+9\sum_{j=1}^\infty 0.1^j \\
1=9\sum_{j=1}^\infty 0.1^j \\
\dfrac{1}{3} = 3 \sum_{j=1}^ \infty 0.1^j = 0.333...
[/math]

>> No.11508141

>>11508046
0.999... means [math] \lim_{n \to \infty} \sum_{i=1}^{n} \frac{9}{10^i} [/math]. This is calculus 1, dude. There's no "meta differences between fractional and decimal notation". [math] \frac{1}{3} = \lim_{n \to \infty} \sum_{i=1}^{n} \frac{3}{10^i} [/math] 0.333... and 0.999... are just shorthands because writing all of that is a pain in the ass.

>> No.11508144

1/9 = 0.111...
2/9 = 0.222...
3/9 = 0.333...
4/9 = 0.444...
5/9 = 0.555...
6/9 = 0.666...
7/9 = 0.777...
8/9 = 0.888...
9/9 = [0.999...] 1

>> No.11508148

>>11508130
do you know what the individual words in that definition mean?
Do you know what "quantity" means?
>quantity
https://www.wolframalpha.com/input/?i=Quantity
>>how much there is or how many there are of something that you can quantify.
>quantify
https://www.wolframalpha.com/input/?i=Quantify
>>express as a number or measure or quantity

Is infinity a number?
https://www.wolframalpha.com/input/?i=Is+infinity+a+number%3F
>∞ is not a number

So what was "infinity" again?
An unbounded quantity greater than any other number?
Yet, infinity is unquantifiable, and it isn't a number.

The only infinite thing here is your loop of retardation.

>> No.11508153

>>11508148
>what "quantity" means
not "magic dragon" that's for sure
this case it means that the word "big" has a mathematical meaning
r<inf, where r is in R

>> No.11508155

>>11508148
>other number
"other"?
stop pulling shit out of your ass

>> No.11508156

>>11508148
>unquantifiable
nope it's a quantity

>> No.11508168
File: 1 KB, 100x100, B5882EC7-CB0F-4A48-B26C-3208AB9187FE.png [View same] [iqdb] [saucenao] [google]
11508168

.99999999999 = 1-infinity^-1

>> No.11508171

>>11508141
[math]\sum_{n=1}^{\infty} \frac{3}{10^n} = 0.\overline{333}[/math], this is a true statement, sure.
However the number value of [math]\frac{1}{3}[/math] is greater than than it.

>there is no meta differences
retard. 0.333... is neither a whole or easily rendered representation of [math]\frac{1}{3}[/math]. The fraction is simple as. The decimal "translation" of that fraction can't settle on a final solveable step denoting equality. There are clear differences, no less than when converting from one base to another.
>doesn't exist
gimme a break brainlet.

>> No.11508174

>>11508171
>value of 1/3 is greater than than it.
nope
>>11508140

>> No.11508178
File: 13 KB, 300x241, RoXKNzi.jpg [View same] [iqdb] [saucenao] [google]
11508178

>>11508155
>what the fuck does "other" mean, damn this guy is smart with his big words n shit
embarrassing

>> No.11508180

>>11508156
Quantity = number
infinity is not a number
that means it cannot represent a quantity
and is therefore unquantifiable.

Its all right there on wolframalpha, your holy book of truth.

>> No.11508183

>>11508178
"other" isn't in the definition >>11508130

"other" implies that inf is a number.
inf isn't a number, that's why the definition calls it a quantity

>> No.11508185

>>11508180
>Quantity = number
nope
3-3=0
inf-inf=undefined

>> No.11508187

>>11508180
>right there on wolframalpha
"An unbounded quantity "
it sure is

>> No.11508196

>>11508183
I see you're tripping on words for no reason. Feel free to read the post of definitions again, then supplant wolframs actual definition with what i said about it.

Nothing changes.
>unbounded quantity greater than any real number
>DEFINE quanity: quantify
>DEFINE quantify: numbers
>IS INFINITY A NUMBER?: no
making infinity unquantifiable and wolfram's definition of infinity complete made-up nonsense.
The real kick in the nuts for you is why wolfram wouldn't just say infinity IS a number. Would make the case for it's usage a little more sensible, wouldn't it?
Why is 1/inf = 0 if infinity isn't a number?
That must mean 1/(anything that isn't a number) = 0, so 1/magical chinese dragon = 0 too.

>> No.11508198

>>11508103
can you please read up the definition of the real numbers, your issue isnt with .9999... it's with the entire system of numbers we call the "real numbers"

>> No.11508202

>>11507816
easy
function Equals(a, b) => { return Abs(b - a) < Max(0.000001f * Max(Abs(a), Abs(b)), epsilon * 8) }
Equals(1, 0.999999f) => true

checkmate mathlets

>> No.11508203

>>11508196
>Why is 1/inf = 0 if infinity isn't a number?
because if 1/inf>0, inf would somehow be bounded

>> No.11508204

>>11508196
>The real kick in the nuts for you is why wolfram wouldn't just say infinity IS a number.
inf isn't a number, so no problemo

>> No.11508207

>>11508196
>you're tripping on words for no reason
you're inserting new words for no good reason

>> No.11508210

>>11508198
[math]\sum_{n=1}^{\infty} \frac{9}{10^n}[/math] is a real number. Just as [math]\frac{1}{3}[/math] is a real number.

The former is a clean string of unambiguous 9's with no wiggle room towards producing a non-9 number in it's continued expansion. So why can't you accept that 0.999... exists as a real number?

>> No.11508213

>>11508210
who are you talking to?

>> No.11508215

>>11508210
.9999.... is an equivalence class of cauchy sequences, which is the definition of a real number. 1 is also an element of that same equivalence class.

>> No.11508218

>>11508213
lrn2read

>> No.11508224

>>11508215
equivalence classes are defined by convergence. If one cauchy sequence converges to another those cauchy sequences are said to be equivalent. Whether you believe that two numbers can be equal if they are not the same is irrelevant, they have been defined to be the same. So .9999... != 1 fags really have an issue with the actual definition of equality in the real numbers.

>> No.11508226

Pi doesn't exist. That's impressive.
I didn't know that, but it must be true.
The true, real value of pi has merely been predicted and labelled on the numberline as [math]\pi[/math], and for all the 50 trillion digits that have been discovered so far, there is still even more to discover.
But
Pi > 3
Pi > 3.1
Pi > 3.14
Pi > 3.141
Pi > 3.1415
Pi > 3.14159
its crazy. We know pi must exist on the numberline, yet we can't actually touch it. We reach out but never grasp it, always just settling with using some comprehendable handful of digits and calling that "close enough".

So if its okay to say
>3.14159265359 = pi
its easy to understand why we also say
>0.99999999999 = 1

It's cause we're all mentally retarded.

>> No.11508231

>>11508226
in base pi, pi is "10"

>> No.11508232

>>11508215
Equivalence isn't equality.
1/3 is equivalent to 0.333..., but not equal.
Equivalent is approximate.

>> No.11508235

>>11508232
>Equivalence isn't equality.
[citation needed]

>> No.11508247

>>11508235
Heres a good laugh at definitions and usages
https://www.dictionary.com/browse/equivalent

one of note is what it says for math
>(of two sets) able to be placed in one-to-one correspondence.
so imagine two sets of numbers and each set has the same length
>A: [ 1 . 0 0 0 0 0 0 0 0 ... ]
>B: [ 0 . 9 9 9 9 9 9 9 9 ... ]
wheres the one-to-one equivalency beteeen A and B? they're different for every element.

>> No.11508259

If 0.999... = 1.000...
then
0.999... × V = 999...
1.000... × V = 1000...
999... = 1000...
if numbers get too small that we can safely ignore their differences, then too numbers must also get so big that we can safely ignore their differences.

>> No.11508272

>>11508247
>hahaha im soo smart
start your own WA then wise guy
>fuck these rando retards

>> No.11508274

>>11508247
oh no 500/1000 isn't 1/2 see the digits look different....
seriously, do you piss in your cereal?

>> No.11508280

>>11508274
At least i eat cereal with mine. Seems you can't help but just piss right into your own mouth and all over your face however.

>> No.11508287

>>11508280
>i have no argument

>> No.11508338

The largest number is 1,000.
Describing larger numbers hinges on 1,000 being established.
You might think a million is a big number, but check again
>1,000,000
thats just 1,000 with 3 more zeros
Alternatively, its 1 with 6 zeros, or 7 digits.
7 is a small fraction of 1,000.
this goes on for a while.
What would you call 1,000 with 1,000 zeros after it?
"Too big, impossible" is what you'd first say. You'd be right.
but then its just [1,000]×10^[1,000],
And whats the smallest number?
Thats easy.
It's 1/(10^50)
Why?
I'll show you why.
It's 1,000 with 47 zeros after it.
It's 1,000^(16 + (2/3))
Its 50 digits long.
Nigga can you even do math with 50 digits?
No. You do finger math, 1 digit. You'll grab a pen and paper and do like 3 digit math.
You'll use your casio calculator and do 8 digit math. That shit is accurate enough to put niggas on the moon. 8 digits. Think about it.

You learn how to program computer and you'll get 15 digit math. They do flybys with pluto on 15 digit math, nigga. Think about it.

So whats special about 50 digits?
nigga, map(8,15 -> moon,pluto)
(8) Moon: 2.4 × 10^5 miles
(15) Pluto: 2.6 × 10^9 miles
(50) = 2.8 × 10^24 miles
size of the universe is 5.5 × 10^23 miles

16 + (2/3) = 16.6666...
guess what that is, nigga.
16.6666... milliseconds × 60 = 1 second
60 minutes in an hour
60 seconds in a minute
60 (16 + (2/3))milliseconds in a second.
60 + 60 + 60 = 180°, half a circle
Whats half a circle?
[math]\pi[/math].
Think about it.

>> No.11508356

>>11508338
the pills won't help if you don't actually take them

>> No.11508361

>>11508356
bozo who believes in infinity trying to give advice to anyone else.

[math] L M A O [/math]

>> No.11508370

>>11508171

based

>> No.11508389

>>11507839
what makes you think 9 times 0.99999... is 9?

>> No.11508390

>>11508361
>i have no argument

>> No.11508394

>>11508370
>than than based
>every retard ever

>> No.11508396 [DELETED] 

>>11508389
>what makes you think i think 9 times 0.99999... is 9?

>> No.11508398

>>11507816
Well some mathematical systems do allow infinitesimals

>> No.11508399

>>11508389
what makes you think i think 9 times 0.99999... is 9?

>> No.11508411
File: 182 KB, 953x613, .9 Repeating = 1.jpg [View same] [iqdb] [saucenao] [google]
11508411

>>11507894
>>11507916
>>11508001
>>11508015
>>11508046
>>11508064
>>11508098
>>11508103
>>11508127
>>11508171
>>11508259

>> No.11508414

>>11508411
tldr can you remake this image in the form of a wojak comic so i can understand it

>> No.11508416

>>11508414
>can you remake this image
no

>> No.11508425

>>11508414
No.

>> No.11508435

"0.999..." means [math]\sum_{n=1}\frac{9}{10^n}[/math]
Thats what "0.999..." means.
It doesn't mean it has infinite 9's, it just means that any measure will have as many finite 9's as you're willing to deal with for any given required application. As many as you want for which you can calculate with. You can't "have them all" because you can't calculate with infinite digits, the work would never end, and you'd never get a result.

Moreover, "0.999..." is NOT the result you get when you equate 1/3 into decimal and multiply it by 3.
That repeating 9 number you get in that case is strictly an error in the way we look at the math. As in, we expect an answer to be solved, and find it hard to understand that an answer provided from attempting to solve would actually be unsolved.
It's not
>1/3 = 0.333...
>3(1/3) = 3(0.333...)
>3/3 = 0.999...

It's
>1/3 > 0.333...
>3(1/3) > 3(0.333...)
>3/3 > 0.999...

There is no ambiguity that [math]\frac{n}{n}[/math]=1, however not all [math]\frac{n}{k}[/math] have direct translations from fractional to decimal.
[math]\frac{1}{2} > \frac{1}{3} > \frac{1}{4} \frac{1}{5} > \frac{1}{6} > \frac{1}{7} > \frac{1}{8} > \frac{1}{9}[/math]
[math]0.5 > x > 0.25 > 0.2 > x > x > 0.125 > x[/math]
the x's are decimal values that have no direct translation from their fraction counterpart.

With that established, it must be understood that any observation or usage of an instantiated repeating number, such as:
>x = 0.999...
must also convey information about the finite degree of accuracy desired to work with it.
>x = 0.9999999999
for example
and now we can do math with it
>10x = 9.9999999990
>10x-x = 8.9999999991
>9x = 8.9999999991
>x = 0.9999999999

remember infinity is not a number.

>> No.11508439

>>11508411
You're really proud of this image and constantly repost it in every thread despite every single thing it's claiming is false.

>> No.11508443
File: 3.00 MB, 1280x9474, 1554337018090.jpg [View same] [iqdb] [saucenao] [google]
11508443

>>11507816
The inability many people today who view themselves as being "scientific" as well as math fans (left-brain prisoners) have in comprehending that .999 isn't the same as 1, is completely connected to their inability to grasp eternity and infinity. Their minds have basically been programmed to believe eternity and infinity are impossibilites. Over the course of the last 10 or so centuries of indoctrination into an alien world-view, they've "learned" to be unable to comprehend it.

This difficulty they have with eternity/infinity shows up in many different fields, from math to astrophysics.

This mental handicap is inherited directly from the (((Abrahamic))) religions, more specifically Christinsanity for us Westernerns. In it's origin, the inability to understand infinity and eternity is 100% Judaic in thought/philosophy. In contrast, the non-Jewish man; the Pagan man, at least the /European/ Pagan man, never had any problem with infinity and eternity. Christinsanity introduced into the minds of people the idea of life and the world/universe being linear, starting from point A and ending with a point B, whereas in the Native European world-view everything is infinite, a circle.

That's why many people today can't understand that .999 repeating forever will never reach 1 -- they refuse to accept the idea of an infinite/eternal repetition. Saying "it's 1" is their method of escaping from the uncomfortable (and to them insurmountable) challenge which the concept of infinity/eternity is to thier Judaically-induced mental disease.

>> No.11508444

>>11508411
Autism

>> No.11508448

>>11508439
I’m going to make an image to counter it

>> No.11508461

>>11508443
No, infinity and eternity exist, it just has nothing to do with numbers.

That was a big wall of text for nothing.

>> No.11508462

>>11507816
there are two options:

either 1 - 0.999... = 0
or 1 - 0.999... > 0

the second option results in contradictions. therefore it's the first option which is true.

QED

>> No.11508466
File: 468 KB, 420x420, 55276badb4dd080a5be872d5f8617bbb.png [View same] [iqdb] [saucenao] [google]
11508466

>>11508462
>1 minus a number smaller than 1 is greater than 0
>this is a contradiction

>> No.11508468

>>11508461
Congratulations, your mind isn't entirely Jewish.

>> No.11508469

>>11508466
>0.999... is smaller than 1
prove it

>> No.11508472

>>11508469
1 > 0.9

>> No.11508474

>>11508472
true and irrelevant

>> No.11508482

>>11508474
1 > 0.9000000000000000000...
1 > 0.9900000000000000000...
1 > 0.9990000000000000000...
1 > 0.9999000000000000000...
1 > 0.9999900000000000000...
1 > 0.9999990000000000000...
1 > 0.9999999000000000000...
1 > 0.9999999900000000000...
1 > 0.9999999990000000000...
do you see a repeating pattern forming here and can you imagine what it would continue to look like?
...
1 > 0.9999999999999999999...
1 > 0.999...

thats just how it do.
thats just how it be.
simple as.
intuitive.

>> No.11508483

>>11508461
>nothing to do
there is a defined relation
>>11508130
>>11508153

>> No.11508485

>>11508439
>Pouring one bottle of water into three cups, then back into one, results in less than one cup
>false statement
Fucking weapons-grade retardation

>> No.11508488

2 real numbers are equal if there is no rational number between them, by the dedekind cuts definition (a real number is equal to the set of rational numbers smaller than it).
There is no rational number between 0.999.... and 1.
Hence 0.9999...=1

>> No.11508489

>>11508435

If we use base 9 for the 1/3 argument:

>1/3 = 0.3
>2/3 = 0.6
>3/3 = 1

Or if we use base 6:

>1/3 = 0.2
>2/3 = 0.4
>3/3 = 1

Or base 3:

>1/3 = 0.1
>2/3 = 0.2
>3/3 = 1

Then we can see the 0.9999 shit is only caused by our base 10 decimal system.

>> No.11508491

>>11508482
>zero repeating is same as 9 repeating
lol no
total retard

>> No.11508492
File: 277 KB, 585x606, 1585113630285.png [View same] [iqdb] [saucenao] [google]
11508492

>>11508483
wow retard.
>>11508148

>> No.11508493

>>11508482
1 > 0.99....9 for any finite string of 9's only implies
1 ≥ 0.999...

but this is a common beginner mistake, don't worry about it

>> No.11508496

>>11508492
cool argument bro

>>11508148
so?

>> No.11508497

>>11508482
0.99>0.9
0.999>0.99
0.9999>0.999
0.99999>0.9999
0.999999>0.99999
do you see a repeating pattern forming here and can you imagine what it would continue to look like?
....
0.999...>0.999...

>> No.11508499

>>11508497
kek

>> No.11508502

>>11508493
>>11508140

>> No.11508503

>>11508482
0.999... > 0.9
0.999... > 0.99
0.999... > 0.999
0.999... > 0.9999
0.999... > 0.99999
do you see a repeating pattern forming here and can you imagine what it would continue to look like?
...
0.999... > 0.999...

M I N D B L O W N

>> No.11508513

>>11508488
[math]sum_{n=1}^{\infty} \frac{9}{10^n} = 0.\overline{999}_9 < \sum_{n=1}^{\infty} \frac{10}{11^n} < \sum_{n=1}^{\infty} \frac{11}{12^n} < \sum ... < 1.0[/math]
learn how to do math.

>> No.11508517

>>11508513
that looks like a zodiac killer letter
try real math sometimes

>> No.11508518

>>11508503
I mean you're not wrong, if both sides grew at the same rate then there were always more 9's on the left side number.

Oh wait, do you think infinite is finite?

>> No.11508529

>>11508518
>both sides grew
left hand side remains constant

>> No.11508531

>>11508513
another reminder that [math]a_n < K[/math] doesn't imply [math]\sup_{n \in \mathbb{N}}\{a_n\} < K[/math]

>> No.11508532

>>11508503
>>11508497
>these mentally retarded niggers whose mothers' drank bleach while pregnant literally think infinity is a process that ends

>> No.11508534

A sequence of rational numbers (q_i) is called Cauchy if:
- For any positive rational number e>0, there exists a natural number N such that for all natural numbers n,m>N, |q_n - q_m|<e.
-----------------
Real numbers ARE NOT:
- sequences of digits with a decimal point somewhere
- mystical undefined quantities that behave like magic
- infinite processes (whatever that means)

Real numbers ARE:
- Equivalence classes of Cauchy sequences of rational numbers ( sequence a_n is equivalent to b_n if the sequence (a_n -b_n) converges to 0 in the rational numbers)
- Equivalently, the set of Dedekind cuts (nonempty proper subsets of the rational numbers A such that 1) for all x in A and y<x implies y in A; 2) A does not contain a maximum
--------------------
The notation x=0.(d_1)(d_2)(d_3).... (d_i are digits) DOES NOT stand for:
- An infinite process (this term is meaningless in mathematics).
- The sequence of digits d_i
- An element of hyperreals or surreal numbers.

It DOES stand for:
- The least real number (or the least rational number, if such exists, because they are the same) that is not smaller than any of the numbers {0.d_1, 0.d_1d_2, 0.d_1d_2d_3,...}
- Equivalently, the real limit of the Cauchy sequence (0.d_1, 0.d_1d_2, 0.d_1d_2d_3,...).
- Equivalently, the equivalence class of in the Real numbers of the Cauchy sequence (0.d_1, 0.d_1d_2, 0.d_1d_2d_3,...).
- Equivalently, in the Dedekind cuts definition of the real numbers, the Dedekind cut containing all the numbers (0.d_1, 0.d_1d_2, 0.d_1d_2d_3,...) together with all the rational numbers smaller than any of its elements.


Now that we've got the definitions out of the way,
- By Dedekind cuts definition of the real numbers, two different real numbers have a rational number strictly between them.
...cont

>> No.11508535

>>11507925
If there are three apples and you take one. You have taken exactly a third of the apples.

>> No.11508537
File: 76 KB, 239x243, 1551451198820-1.png [View same] [iqdb] [saucenao] [google]
11508537

>>11508529
>lets pretend infinite is finite
shit nigga its like it's literally just impossible for you to win.

>> No.11508538

>>11508534
- Same holds for the Cauchy sequence definition of the real number: if x<y are different real numbers, let the Cauchy sequences x_i and y_i represent them. Then (y_i - x_i) is a Cauchy sequence that is bounded above by some e>0. Thus there is a rational number strictly between x_i and y_i.

In conclusion, since 0.999... and 1 have no rational numbers between them, they must be equal.

>> No.11508542

>>11508537
>I have no argument

>> No.11508543

>>11508535
alright billybob, now convert those apples into a fraction and convert that fraction into a decimal.
Technically you have to stop at the fraction for final equality since the decimal suffers translation error.

>> No.11508547

>>11508542
Who are you quoting?

>> No.11508548

>>11508535
imagine the smell

>> No.11508550

>>11508287
>>11508390
>>11508542
oh you're quoting yourself.

>> No.11508552

>>11508543
0.1, in base 3

>> No.11508553

>>11508547
you

>> No.11508554

>>11508144
^underrated

>> No.11508555

>>11508552
decimal is base 10.

why are you talking about trinary.

>> No.11508563

>>11508532
>I don't know what a supremum or a limit is

>> No.11508574

imagine teeter tottering between thinking infinity is either A or B, when in reality it's C and you're nowhere close.

>> No.11508575

>>11508555
what's holy about base 10

1/2 is 0.333... in base 7
does that mean 0.5 doesn't exist?

>> No.11508585

>>11508555
0.1 in base 3 = 0.333... in base 10

The base doesn’t matter

>> No.11508596

>>11508585
>0.1 in base 3 = 0.333... in base 10
>=
wrong.
no equality.
0.1[END] in base-3.
0.[math]33333[/math]33333[math]_{3333...}[/math]
endlessly in base-10.
no final mantissa means no final solution means no direct equality.

>> No.11508599

>>11508596
>>11508575

>> No.11508632

>>11508554
tl;dr
1/9 = 0.111...
+
8/9 = 0.888...
=
9/9 = 0.999...

>> No.11508677

>>11508632
a fraction or identity which, when rendered as a decimal containing repeating sequences, holds that the value of the fraction or identity is greater than the decimal rendering.
1/9 != 0.1111...
1/9 > 0.111...
8/9 > 0.888...
9/9 > 0.999...
repeating decimals like these, in relation to fractions like these, have a different component of truthfulness to them than a decimal with a last digit, like 1/2 = 0.5

(9/9 = 0.999...) is a false statement. The fraction equate to 1, and the decimal is in error (not in rendering, but in comparison to what it's being rendered from), relative to the truth component being "="
However
(9/9 > 0.999...) is a more truthful statement. The fraction equates to 1, and 1 is larger than some 0.9 number, relative to the comparison ">"

And even though the latter is "more truthful", it still is not entirely truthful, because "0.999..." can represent infinitely many different values in the spectrum of [math]\lim_{k\rightarrow \infty} \sum_{n=1}^{\infty} \frac{k}{(k+1)^n}[/math], which itself is an allowable inconvenience because [math]\infty[/math] wasn't ejected out of mathematics with hearty laughs the moment it was introduced like it should have been, leading to the modern day where "..." is used to hide or otherwise ignore unique identifiers in long numbers that are too inconveniently long to write out.

>> No.11508679

>>11508677
wall-of-text schizo

>> No.11508712

>>11508679
infinite is infinite, and you don't have the capacity to deal with it.

>> No.11508723

threadly reminder that
[eqn]0 \leq 1 - 0.999\dots \leq \tfrac{1}{10^n}[/eqn]
holds for every [math]n[/math]. unless you can prove that there exist non-zero non-negative numbers which are smaller than [math]\tfrac{1}{10^n}[/math] for all [math]n[/math], this implies
[eqn]1 - 0.999\dots = 0[/eqn]

>> No.11508744

>>11508712
>deal with it
it's big, so 1/inf=0

>> No.11508764

>>11508723
>my statement is correct unless you can prove otherwise.
Anon, that's not how proofs work.

>> No.11508766

>>11508764
>i can't find the error
m-muh feelings

>> No.11508774

>>11508764
it's not supposed to be proof, it's an attempt to lure schizos into trying to prove something which is false

>> No.11508780
File: 10 KB, 618x175, Slope Proof .999...≠ 1.png [View same] [iqdb] [saucenao] [google]
11508780

What is the slope of line BZ?
How is it different from line BW?

Note that if you try to claim that line ZW is meaningless or doesn't exist somehow, then neither does .999...

>> No.11508787

>>11508780
pic "proofs" aren't proofs
can draw another "proof" that shows the opposite
in both cases it's just a nice analogy, nothing more

>> No.11508794

>>11508787
>can draw another "proof" that shows the opposite

No you can't. Try it.

Or better still, answer the question instead of trying to "disqualify" it.

>> No.11508802 [DELETED] 

>>11508794
https://i.imgur.com/BKxlscC.png
As long as the distance AB>0, C moves along the bottom horizontal line.
Once AB=0, C is on the top horizontal line, if anywhere.
This is infinity. Infinity is larger than any real number. Infinity isn't a number.

>inb4 assuming circles exist
>thinks continuity is important here

>inb4 assuming infinite lines exist
if you think a line can't be longer than M,
it still stands that an M length BC line
reaches less to the right, than an M-long horizontal line along the top horizontal

>> No.11508803

>>11508780
Did you just try to appeal to intuition by assigning infinity to a distinct point in a geometric illustration? As far as that can charitably be said to make sense at all, the slope of line BZ is 0, the proof of witch would be essentially the same proof by limits as proving 1=0.999...

>> No.11508804

>>11508787
>pic "proofs" aren't proofs
It is apparent that OP has not even a high-school level understanding of math. So what other means do you think are available to prove something to him?

>> No.11508806

>>11508794
https://i.imgur.com/BKxlscC.png
As long as the distance AB>0, C moves along the bottom horizontal line.
Once AB=0, C is on the top horizontal line, if anywhere.
This is infinity. Infinity is larger than any real number. Infinity isn't a number.

>inb4 assuming circles exist
thinks continuity is important here

>inb4 assuming infinite lines exist
if you think a line can't be longer than M,
it still stands that an M length BC line
reaches less to the right, than an M-long horizontal line along the top horizontal

>> No.11508811

>>11508034
yes but who cares?

>> No.11508815

>>11508596
yes because 0.333... < 1/3

>> No.11508818

>>11508804
pics assist in understanding, but that's all.
They fail as a rigorous proof because just-graphics assumes distance=length, which the density-of-numbers easily breaks.

>> No.11508822

>>11508811
this guy >>11507972

>> No.11508831

>>11507839
This same logic was taught to me by a
Math doctor
It seems legit

>> No.11508833

>>11508723
what you're saying is not a reasonable math function without first addressing how you're creating your 0.999.... reference.

for example:
[math]1 - \sum_{n=1}^{\infty} \frac{9}{10^n} \leq \frac{1}{10^n}[/math] might be more of what you're trying to express.

And in that case, it works out fine in proving small numbers exist.
for example when n=3
1 - 0.999 = 0.001; 1/10^3 = 1/1000 = 0.001
all checks out.

the issue of virtually all misunderstandings of this revolve explicitly around what the fuck infinity means and what the fuck "..." dot repetition means, of which neither are explained well or used correctly.

to break it down, you seem to want to treat [math]0.999\dots[./math] as if it were a finite, contained, bounded set of knowable length, of which at some arbitrary point within (or at the end of) that set, some arbitrary (unnoted) restriction arises where there can be no more continued math, such that you treat it like:
[ 0 . 9 9 9 9 9 9 9 9 . . . ]
aka, "contained" between the [ and ] brackets, leading to your math of
>[ 1 . 0 0 0 0 0 0 0 0 . . . ]
- [ 0 . 9 9 9 9 9 9 9 9 . . . ]
=[ 0 . 0 0 0 0 0 0 0 0 . . . ]
while either not realizing the problem or otherwise hoping no one else notices the problem of what information " . . . ] " is being used to hide.

if we take that infinity is unbounded, unlimited, on-going, continual, ever-lasting; then there is no identifiable unique "chunk" or sequence we can attain from within it. If we also take that the word "infinite" can be used to describe the size of "the set of all numbers", aka:
[math] \underbrace{[ 0, 1, 2, 3, 4, 5, 6, 7, \dots ]}_{size=\infty}[/math]
but this is a collection of definitely finite values 'between' [math] {1\rightarrow \infty}[/math]
which ultimate derives a definition of infinity which means any test of n as an element within an infinite set, is indeed a finite number, and always will be, continually.

>> No.11508842

>>11508818
>pics assist in understanding, but that's all.
>They fail as a rigorous proof because just-graphics assumes distance=length
OP is nowhere near that level. His teacher has shown him a pic of an apple, a pic of a car, and a pic of a nose, and OP is supposed to know from that what "1" means to everybody. Pics of two apples, two cars and two ears prove to OP that "1" is not "2", and so on. It is not a wonder that he thinks that his equation needs "proof". Indeed, it is very much in doubt that he even knows the meaning of the symbols on the LHS.

>> No.11508844

>>11508833
>how you're creating
i create them by dancing around the house in clogs
now what?

>> No.11508846

>>11508844
so you're merely just pretending to do math?

>> No.11508852

>>11508846
nein nein nein...

>> No.11508857

>>11508852
>nein nein nein...
Prove nein nein nein... = nazi

>> No.11508858

>>11508534
>>11508538
You are completely correct. But who says we have to be talking about the real numbers, especially given that non-archemedian systems which include infinitesimals can be rigorously defined?

>> No.11508860

>>11508833
>to break it down, you seem to want to treat [math]0.999\dots[./math] as if it were a finite, contained, bounded set of knowable length, of which at some arbitrary point within (or at the end of) that set, some arbitrary (unnoted) restriction arises where there can be no more continued math, such that you treat it like:
Incorrect.

>if we take that infinity is unbounded, unlimited, on-going, continual, ever-lasting; then there is no identifiable unique "chunk" or sequence we can attain from within it.
Completely wrong. Since the digits repeat we know exactly what every part of the sequence is. You assume, based on nothing, that just because something is infinite in some way it cannot be operated on. There is an entire field of math that does just that, called the calculus.

>which ultimate derives a definition of infinity which means any test of n as an element within an infinite set, is indeed a finite number, and always will be, continually.
So what?

>> No.11508862

>>11508857
the clogs are dutch you dork

>> No.11508864

>>11508815
0.333 < 1/3
0.3333 < 1/3
0.333...n =/= 0.333... for any n

>> No.11508873

>>11508864
>0.333 < 1/3
>0.3333 < 1/3
yes

>0.333...n =/= 0.333... for any n
nope, the "..." means infinite digits
n*10^-inf=0, so it's meaningless
so you get 0.333...=0.333...

>> No.11508884

>>11508873
>nope, the "..." means infinite digits
You just agreed with him.

>n*10^-inf=0, so it's meaningless
It's undefined, but that's a non sequitur anyway.

>0.333...=0.333...
But 0.333...3 =/= 0.333..

>> No.11508886

0.999... = 1
1-(1/infinity) = 1
-(1/infinity) = 0
1/infinity = 0

if 1/infinity = 0 then

e = (1+(1/infinity))^infinity
e = (1)^infinity
e = 1

so 0.999... != 1

>> No.11508888

excuse me sirs, but the very first assumption is dubious. is 1/3 really equal to 0.333..? isnt 4 the last digit?

>> No.11508892

>>11508860
calculus is explicitly finite. Any math that "deals" with "infinity" yet produces an answer in real time is always, explicitly using finite operations to do so. Fourier transforms, even the [math]\sum_{n=1}^{\infty} \text{and} \lim_{n \rightarrow \infty}[/math] functions use this shit explicitly finitely and tend to mean that their use of [math]\infty[/math] is either [math]not[/math] literal, or that their literal usage is as defined here:
>which ultimately derives a definition of infinity which means any test of n as an element within an infinite set, is indeed a finite number, and always will be, continually.
with an addendum:
>(finite to user's discretion per application)

"proving" infinity "exists" is almost as difficult as proving something that no longer exists ever existed at all. Can you "prove" the WTC twin towers exist? All you could use to "prove" it are photos and videos, but if anyone never saw the WTC twin towers for themselves, those photos and videos merely represent something that is completely out of reach of ever getting to personally see.

that aspect of "infinity" is also completely out of reach of ever personally getting to see it, account for it, measure it, etc. It's like looking out into space and saying you can see the edge of the universe as clearly as you might see an edge of a cardboard box, or the edge of a cliff hanging over a coastline facing the ocean. The truth is, you can't "see" the edge of the universe, and you certainly can't grasp it or reach it even if you could. Same goes for infinity. You can't "see" where it ends, and you certainly can't grasp it or reach it even if you could.

This is all in relation to assuming [math]0.999\dots[/math] explicitly contains infinite 9's, as if you know it as truth, as if you'd seen it yourself, as if you'd measured it and contained it conveniently in 8 text characters; and this is the false assumption leading to the issues at hand.
There are not "infinite" 9's there.

>> No.11508896

>>11508873
>the "..." means infinite digits
Exactly. And "...n" means finite digits. So?

>n*10^-inf=0, so it's meaningless
This is completely irrelevant to anything I said.

>> No.11508906

>>11508896
>"...n" means finite digits.
nope

>> No.11508909

>>11508892
>calculus is explicitly finite
lol no

>> No.11508911

>>11508888
>>11508140

>> No.11508914

>>11508909
>lol no
then calculus doesn't produce usable answers.

but it does.

so it must use infinity explicitly finitely, because doing infinite work would require infinite time, meaning no answer would ever be produced in finite time.

>> No.11508915

>>11508886
>e = (1+(1/infinity))^infinity
1^inf is undefined

>> No.11508916

>>11508858
Well I was talking about the standard notation of course. The point is, if you're using a different number system, you should specify this. 0.9999...= 1 is a trivial theorem following from the way we define decimal expansions.
This whole thread is all about people confusing notation with the meaning behind it.
0.999... is an expression that has a standard meaning in mathematics. "0.999..." itself is not a number, it's an expression that represents a number.
The whole debate would be instantly solved if they people who claim 0.999... =/= 1 would specify what they mean by 0.999.... But they never do. They always give vague, meaningless answers about "processes" and "infinities". Nonsense really. I don't know why people still engage with these retards.

>> No.11508917

>>11508914
>then calculus doesn't produce usable answers.
nope

it works, and f'(x) is defined with limits

>> No.11508930

>>11508917
talking to you is like talking to a block of conjac. dear fuck your brain is nothing but jelly and you never add anything useful to these threads.

>> No.11508931
File: 13 KB, 439x352, p1.png [View same] [iqdb] [saucenao] [google]
11508931

>>11508780
I assume that the two horizontal lines are supposed to be number lines. then Z and W aren't supposed to be drawn on the lines, because they don't represent any number. they actually represent so-called "ideal points", which are basically points on the horizon.

pic related is what you see if you draw a finite portion of your picture on a canvas and you tilt the canvas a little.

>> No.11508933

>>11508892
>calculus is explicitly finite. Any math that "deals" with "infinity" yet produces an answer in real time is always, explicitly using finite operations to do so.
Yes, that's exactly my point.

>>which ultimately derives a definition of infinity which means any test of n as an element within an infinite set, is indeed a finite number, and always will be, continually.
You keep repeating this without explaining how it's relevant.

>"proving" infinity "exists" is almost as difficult as proving something that no longer exists ever existed at all.
There is no need to prove anything in math "exists," but if it makes you feel better, infinite decimals and infinite limits are used all over physics.

>Can you "prove" the WTC twin towers exist?
Do you understand the difference between math and empiricism? Theorems vs. Facts?

>This is all in relation to assuming 0.999… explicitly contains infinite 9's, as if you know it as truth, as if you'd seen it yourself, as if you'd measured it and contained it conveniently in 8 text characters
LOL, now you seem to think symbols have meaning beyond their definition, as if they need to be discovered in a Platonic realm. Choose a position already.

>There are not "infinite" 9's there.
Why not? You haven't actually given an argument, just wasted a bunch of electronic space. None of it is math.

>> No.11508935

>>11508906
>nope
Nope.

>> No.11508944
File: 22 KB, 419x540, p2.png [View same] [iqdb] [saucenao] [google]
11508944

>>11508780
>>11508931
pic related is what happens if you draw the whole picture with correct scale and then tilt the canvas. we can see that the points Z and W actually coincide, BZ and BW coincide, and therefore slope of BZ is 0. which proves 0.999... = 1.

>> No.11508949

>>11508935
k, have fun by yourself

>> No.11508954

>>11508931
the graphic merely aligns with zeno's paradoxes of Achilles and the tortoise, which itself boils down to [math]\sum_{n=1}^{\infty} \frac{1}{2^n}[/math], which is also similarly applied to zeno's Arrow paradox, defining [math]\frac{1}{\infty}[/math] cannot be possible, for infinite sequential addition of the result would never produce 1.

there always exists a smallest finite part, regardless of how arbitrary it may be.

>> No.11508957

>>11508930
>like talking to a block of conjac
you should know

>> No.11508958

>>11508888
It's funny how truths that have been clear since the third grade can still be legitimately called into question. Math is funny that way.

>> No.11508964

>>11508954
No need to define 1/inf, it never occurs in the sum.

>for infinite sequential addition of the result would never produce 1.
What do you mean by never? Are you saying each addition step takes some amount of time? It doesn't, and you can solve it instantly using calculus.

>there always exists a smallest finite part, regardless of how arbitrary it may be.
Incorrect.

>> No.11508969

>>11508906
What else would it reasonably mean?

>> No.11508972

>>11508916
Give them a break, they're generally people who have yet to be exposed to modern mathematical formalism, but feel that 0.999... potentially stands for some quantity that, *could* be infinitesimally distinct from 1, and feel that statements against this are blind attacks against this possibility. In a sense, they are right to point out that most of the proofs typically offered against this are things that implicitly assume that they are using a specific set of numbers, but without actually defining it, and showing that, for instance, the Archimedean property holds.

Given that the Dedekind construction of the reals is relatively recent, compared to Newton's intuitive use of infinitesimals, there in a sense, actual justification to the person who claims that 0.999... = 1 is debatable, in the absence of prior agreement of the conventions being used. It's one thing to explicitly claim that this is false with regard to the reals, using standard notation, but another to merely point out that the notation could be defining some sequence of numbers which converge to something which could be distinct from 1 in some hypothetical set of numbers where this might be possible, which is something that isn't generally going to be 'proven' in these kinds of debates.

>> No.11508974

>>11508954
>here always exists a smallest finite part,
let's pretend finite is infinite

>> No.11508989 [DELETED] 

>>11508969
reasonably, it's a dumb ass way of writing a meaningless digit
anything after the "...", aka ellipsis indicates the previous digit repeats forever
so if you have to tack something on the right side of ..., it's either meaningless or literally infinitely small - the value of n is n*10^-inf=0

>> No.11508993

>>11508944
This is fucking with my mind. Tilting an infinite ruler like this, the laws of perspecive means that you can see the entire ruler. I can see intinity? Whoa, dude.

>> No.11508995

>>11508933
construct two sets:
A: the set of all integers
B: the set containing the result of [math]\sum_{n=1}^{\infty} \frac{9}{10^n}[/math]
>[math]A: [ \underbrace{0 , 1 , 2 , 3 , 4 , \dots}_{size = \infty} ] [/math]
>[math]B: [ \underbrace{0 . 9 , 9 , 9 , 9 , \dots}_{size = \infty} ] [/math]
let n'th element in A have a directly comparable element in B such that [math]sum_{n=1}^{\infty} \frac{9}{10^n}[/math] maps to [math]n[/math] in A and B.
let [math]n[/math] be any number
https://www.wolframalpha.com/input/?i=is+infinity+a+number%3F

Now that this is laid out, what information can be gleamed from this?
the most of which has occurred is two arbitrarily undefined evergrowing sets of numbers have been created and some kind of cheat was used to "definitely" contain them between and opening and closing bracket, defying the definition of infinity being "unbounded".
the useful bits however, are
> "n is any number"
> "[math]\infty[/math] is not a number"
which predicates that any usage of our sets to retrieve a calculable value from B must be an n'th equivalent term of the n'th element from A.
and since n = a number
and infinity = not a number
the usage strictly applies finitely.
for any n, in A or B applying to [math]\sum_{n=1}^{\infty} \frac{9}{10^n}[/math], there is a non-zero smallest part [math]\frac{1}{10^n}[/math] which exists.

>> No.11508997

>>11508969
reasonably, it's a dumb ass way of writing a meaningless digit
anything after the "...", aka ellipsis indicates the previous digit repeats forever
so if you have to tack something on the right side of ..., it's either meaningless or literally infinitely small - the value of n in that position is n*10^-inf=0

>> No.11508999

>>11508989
I think the intepretation of finitely many digits is much more reasonable.

>> No.11509000

>>11508999
>>11508949

>> No.11509005

>>11508997
>>11508949
>>11509000
>t. second year math major

>> No.11509008
File: 38 KB, 553x241, xHbYo[1].png [View same] [iqdb] [saucenao] [google]
11509008

>>11508993
parabola is an ellipse with one focal point being an ideal point. why? if you draw a parabola on an infinite canvas and tilt it, you'll see an ellipse. how cool is that?

>> No.11509012

>>11508995
>defying the definition of infinity being "unbounded".
Only if you don't know what unbounded means.

> "n is any number"
> "∞ is not a number"
>which predicates that any usage of our sets to retrieve a calculable value from B must be an n'th equivalent term of the n'th element from A.
Doesn't follow.

>for any n, in A or B applying to ∑∞n=1910n, there is a non-zero smallest part 110n which exists.
Mmhmm but we are not interested in some n but the entire sum.

>> No.11509014

>>11509008
Tha is cool

>> No.11509018

>>11508995
You could have just said "any partial sum is not 1" instead of wasting all that time writing out an irrelevancy. Brainlet.

>> No.11509019
File: 418 KB, 479x720, tips fedora.png [View same] [iqdb] [saucenao] [google]
11509019

>>11509012
apparently you don't know what boundaries are.

>> No.11509020

>>11509005
it's comfy here
https://www.wolframalpha.com/input/?i=%289.9...7%29-10

>> No.11509031

>>11509019
What is the largest natural number?

>> No.11509032

>>11509020
truly topthink of the toppest thinkers.
https://www.wolframalpha.com/input/?i=sum%5B9%2F10%5En%2C+%7Bn%2C1%2C10%5E140%7D%5D+-+1

>> No.11509035

>>11509031
Didn't know we were playing Jeopardy but yes, that's 200 points for "retarded questions"

>> No.11509037

>>11509031
(undefined)

>> No.11509038

>>11509032
>syntax error
kek, am I supposed to applaud?

>> No.11509041

>>11509037
So how you can we talk about the natural numbers as a thing? It's boundless, so we can't talk about them.

How many real numbers are there between 0 and 1?

>> No.11509045

>>11509041
>How many real numbers are there between 0 and 1?
aleph-1

>> No.11509049

>>11509020
It's allright. Next year you'll begin developing a deeper understanding of concept, so you won't have to get so hung up on notation.

>> No.11509053

>>11509041
>It's boundless, so we can't talk about them.
I don't see how that follows.

>> No.11509064

>>11509041
as many as you're willing to calculate.
sky's the limit.
you can come up with unlimited possibilities between 0.5 and 1.0 just using [math]lim_{k \rightarrow \infty} \sum_{n=1}^{\infty} \frac{k}{(k+1)^n}[/math], and yet it wouldn't even be all the possibilities between 0.5-1.0

think about that.
there are more real numbers between 0.5->1.0 than the already infinite possibilities between 0.5 -> 1.0 which [math]lim_{k \rightarrow \infty} \sum_{n=1}^{\infty} \frac{k}{(k+1)^n}[/math] has the capacity to account for.

infinity > infinity.

>> No.11509067

>>11509045
Impossible, it has to be finite since they ate bounded by 0 and 1. Apparently you don't know what boundaries are.

>> No.11509068
File: 660 KB, 1432x4127, math.jpg [View same] [iqdb] [saucenao] [google]
11509068

>>11508414
yes

>> No.11509069
File: 155 KB, 1300x957, external-content.duckduckgo-7.jpg [View same] [iqdb] [saucenao] [google]
11509069

>>11508944
>we can see that the points Z and W actually coincide, BZ and BW coincide, and therefore slope of BZ is 0. which proves 0.999... = 1.

You just assumed that 1=0 in order to get the conclusion you wanted! You know that railroad tracks don't ACTUALLY converge in the distance, right?

>> No.11509070

>>11509053
Then why are you saying it?

>> No.11509074

>>11509064
No that must be wrong, since they are bounded by 0 and 1 and as you said this violates the definition of unbounded.

>> No.11509077

>>11509074
"as many as you're willing to calculate" is implicitly a finite amount.
just wordplay.

>> No.11509079

>>11509070
I'm... not?

>> No.11509084

>>11509031
My ass

>> No.11509094

I wonder if OP ever understood the proofs in this thread.

>> No.11509119

>>11509020
>>11509032
https://www.wolframalpha.com/input/?i=penis+on+an+English+keyboard

wolfram is truly a bountiful wealth of knowledge

>> No.11509138

>>11509077
Finite, but unbounded. Thanks for proving my point.

>> No.11509140

>>11509067
kek, oh anon
https://youtu.be/i7c2qz7sO0I?t=4m20s

>> No.11509151

>>11509049
a mathematician not strict on notation is not a mathematician

>> No.11509157

>>11509151
Spoken like a true second year math major.

>> No.11509163

>>11509068
>confusing x and f(x)
yet again, not surprised

>> No.11509168

>>11509069
>You know that railroad tracks don't ACTUALLY converge in the distance, right?
how is that relevant ? who said anything about convergence ?

>> No.11509171

>>11509157
>graduating is an alien concept to you
have a great life anon

>> No.11509175

>>11508057
Checks out.

>> No.11509196

>>11507816
error in rounding...
1/3=0.333333333333
2/3=0.666666666667
-------------------------------
3/3=1

To be clear. "..." is not real
1/3 is not a rational real number
/sci/ is gay

>> No.11509234

>>11509196
retard

>> No.11509251

>>11509234
What I mean is: three dots in a row are abstract, whereas real numbers are real, and 1/3 is neither.

>> No.11509252

>>11509196
Thats the deal though. Lots of rounding occurs in computable math. There is some "soft" idea that after x amount decimal digits, it's okay to just cut it at x+1 and use the x+1'th digit to potentially round the x'th.
it can solve some logical errors, such as
>1 ÷ 3 = "0.3333333" (Answer)
>(Answer) × 3 = "1.0"
because it will round the last digit,
but at the same time it creates logical problems elsewhere where rounding isn't what's desired.

What is the mathematical law or rule that you're supposed to ignore digits longer than 10 decimals while using the 11th digit to round and carry to the 10th?

>> No.11509254

>>11509252
But, but, TI80 is my friend.

>> No.11509265
File: 29 KB, 398x369, ANUDDA SHOAH.png [View same] [iqdb] [saucenao] [google]
11509265

>>11509252

>> No.11509269

>>11509251
This still doesn't make sense.
Real numbers are real numbers.
1/3 is a real number. The symbol "1/3" is a representation of that number in a fractional form. The symbol "0.333..." is another representation of the same number, in an infinite decimal expansion form.

>> No.11509293

>>11509269
1/3 is a real number but the infinite decimal expansion isn't actually equal to it. just "close enough" depending on how you look at it. more literally, 1/3 is greater than the decimal expansion.

and depending on how you look at that inequality, 1/3 and "0.3333..." are actually different numbers.

>> No.11509299

>>11509293
infinite decimal expansion is actually equal to it.
finite decimal expansion isn't actually equal to it.

>> No.11509305

>>11509265
fuck off back to >>>/pol/

>> No.11509310

>>11509299
infinite is finite.

another way of looking at it is >>11508995 which shows infinite is just a direction of continued finite effort.

there is no direct equality without an end to the decimal expansion, and infinite decimals doesn't produce an end, so it doesn't produce direct equality.

>> No.11509314

>>11509293
You need to be 18 to browse this website

>> No.11509315

>>11509310
lol wat

>> No.11509319

>>11509293
What you're saying is only true for finite decimal expansions of arbitrary lengths. The whole point about the infinite decimal expansion is that it coincides with the limit of the finite decimal expansions.

>> No.11509321

>>11509319
okay bigdick, what's the limit of the finite decimal expansions?
the biggest real number?

whats the biggest real number?
oh right, there isn't one.

get fucked.

>> No.11509324

>>11509321
>okay bigdick, what's the limit of the finite decimal expansions?
It's the least real number that is not smaller than any of the finite decimal expansions.

>> No.11509330

>>11509319
>>11509321
>>11509324
lmao u guys

>> No.11509332

0.999... = 1
but ONLY if you round on the last digit of 0.999...

>> No.11509349

>>11509321
The limit of the finite decimal expansions in question:
0.3
0.33
0.333
0.3333
0.33333
0.333333 and so on...
is 1/3.

>> No.11509359

>>11509310
>infinite is finite
wew lad

>> No.11509369

For anyone who claims 0.999...=/=1
Define FORMALLY what you mean by:
- 0.999...
- 1
The mathematicians here who claim 0.999...=1 use the standard implicit definition
- 0.999... is the real number represented by the Cauchy sequence (0, 0.9, 0.99, 0.999, ...)
- 0.9999... = 1 asserts that the Cauchy sequences for 1, namely (1,1,1,...) is equivalent to the Cauchy sequence of (0.9, 0.99, 0.999, ..)

>> No.11509370

>>11509310
>there is no direct equality without an end to the decimal expansion
This is simply not true.

>> No.11509385

>>11509349
[math]\sum_{n=1}^{k} \frac{3}{10^n}[/math]

k = the limit.

limit is a qualia of the direction component within the equation, not within the result.

but if you want to say 1/3 is the limit of the decimal expansion "0.3333...", then... well, that doesn't really mean much other than what you're saying. Doesn't mean they're equal. it's sure enough to say that "0.333..." is trying it's darndest to reach it's limit of 1/3, but the fact of the matter is it never will, because that's what infinity evokes. never-ending.

>> No.11509389

>>11509370
prove it

>> No.11509402

>>11509389
>>11508140

>> No.11509408

>>11508389
substraction, faggot

>> No.11509412

>>11507816
it's not 0.999 is 0.999 and 1 is 1 you damn cunt

>> No.11509437

>>11508833
>what you're saying is not a reasonable math function without first addressing how you're creating your 0.999.... reference.
>what the fuck infinity means and what the fuck "..." dot repetition means, of which neither are explained well or used correctly.
Decimal expansion tells you where you find a number on the number line if you keep dividing line segments into smaller and smaller parts. Nothing else. So denote [math]x = 0.999.\dots[/math] and let's get into it.

The number before the decimal point being zero literally means that [math]x \in [0,1][/math].
The first digit being 9 literally means that if you divide [math][0,1][/math] into ten equal parts, then [math]x[/math] is somewhere in the tenth part. In other words [math]x \in [\tfrac{9}{10},\tfrac{10}{10}][/math]
The second digit being 9 literally means that if you divide the smaller segment [math][\tfrac{9}{10},\tfrac{10}{10}][/math] into ten equal parts, then [math]x[/math] is somewhere in the tenth part. In other words [math]x \in[\tfrac{99}{100},\tfrac{100}{100}][/math]
The third digit being 9 literally means that if you divide the smaller segment [math][\tfrac{99}{100},\tfrac{100}{100}][/math] into ten equal parts, then [math]x[/math] is somewhere in the tenth part. In other words [math]x \in[\tfrac{999}{1000},\tfrac{1000}{1000}][/math]
The fourth digit being 9 literally means that if you divide the smaller segment [math][\tfrac{999}{1000},\tfrac{1000}{1000}][/math] into ten equal parts, then [math]x[/math] is somewhere in the tenth part. In other words [math]x \in[\tfrac{9999}{10000},\tfrac{10000}{10000}][/math]
...
The n-th digit being 9 literally means that if you divide the smaller segment [math][ \sum_{k=1}^{n-1} \tfrac{9}{10^k},1 ][/math] into ten equal parts, then [math]x[/math] is somewhere in the tenth part. In other words [math]x \in [ \sum_{k=1}^{n} \tfrac{9}{10^{k}},1 ] [/math]
...

>> No.11509439

>>11509408
By your logic

10x=10000
-x=1

9x=999
x=111

>> No.11509445

>>11508833
>>11509437
>what you're saying is not a reasonable math function without first addressing how you're creating your 0.999.... reference.
>what the fuck infinity means and what the fuck "..." dot repetition means, of which neither are explained well or used correctly.
The dots in [math]x = 0.999\dots[/math] are not "hiding anything." All they're saying is that the n-th digit of this decimal expansion is 9.

Obviously we will never find [math]x[/math] if we attempt to actually follow these instructions, because there is no last step. We will always end up only with a very small interval which contains [math]x[/math]. There will always be one more step to perform.

HOWEVER. That doesn't mean we can't find [math]x[/math] by other means. [math]x[/math] is simply a point on the number line which satisfies [math]x \in [ \sum_{k=1}^{n} \tfrac{9}{10^{k}},1 ] [/math] for all [math]n \in \mathbb{N}[/math]. That is:
[eqn]\sum_{k=1}^{n} \tfrac{9}{10^{k}} \leq x \leq 1 \quad \text{for all }n \in \mathbb{N}[/eqn]
All we need are these two facts:
Firstly, there exists AT LEAST one number with this property and that's [math]1[/math].
Secondly, there cannot be two distinct numbers with this property.

These two together give [math]x=1[/math].

[math]0.999\dots[/math] was just a very stupid and very inefficient set of instructions on how to find one on the number line.

>> No.11509452

>>11509385
>k = the limit.
wat? You're not making sense.

>if you want to say 1/3 is the limit of the decimal expansion "0.3333..."
That strictly speaking not what I'm saying.
What i'm saying is 0.333... is the limit of (0.3, 0.33, 0.333, ...). I'm also saying 1/3 is the limit of the same sequence (0.3, 0.33, 0.333, ...).

>the matter is it never will, because that's what infinity evokes. never-ending.
The never-ending thing about the infinite decimal expansion is the number of decimals, not the amount of time it would take to write out all the decimals one after the other.
The infinite decimal expansion is not a process. It is a symbolic representation of a real number.

>> No.11509455

>>11508411
>you think infinitellty small numbers exist. They dont

by your logic, an infinite amount of dots wouldnt form a line

>> No.11509462

>>11509437
ooooooohhh shitlatexman is back
what happened, did they kick you out of the psychic ward to use it for corona-patients?

>> No.11509465

>>11509452
you're just making shit up and its easy to see.

>> No.11509478

Thats why you use base 6, the base where the least % of all single digit divisions are repeating decimals

>> No.11509501

>>11509465
I'm trying to discuss the concept of infinite decimal expansion and symbolic number representation, without obfuscating the matter with formalism. Other anons are more suited to and have already shown the formal explanations. I'm more interested in the ideas behind the formalism.

>> No.11509509

>>11508503
>I can just keep adding stuff on the smaller side of a "greater than" symbol and the symbol will stay true

2 > 1
2 > 1.5
2 > 2
woooooooooow, mathfags btfo

>> No.11509523

>>11509455
Please explain your thinking here. I don't follow.

>> No.11509534
File: 9 KB, 250x153, Population_of_Armenia_since_1949.svg.png [View same] [iqdb] [saucenao] [google]
11509534

>>11509265
>population growth rates are constant
>population growth rates are unaffected by genocide
I guess the Armenian genocide is fake too.

>> No.11509554

>>11509501
never-ending means the same thing regardless if time is a factor or not. the decimal "0.333..." is never-ending.

Relative to trying to translate 1/3 to decimal via division, the never-ending nature is an emergent property of being unable to settle on a final digit (which is otherwise present in decimal forms of fractions that do evenly divide, such as 1/2, 1/4, 1/5, 1/8, 1/10, etc)
Relative to [math]\sum_{n=1}^{\infty} \frac{3}{10^n}[/math], the never-ending nature is an emergent property of using "[math]\infty[/math]" as an element of the function towards solving the equation.
In the Sum, we get the answer we are telling it to give us cleanly, and we expect it to never-end because that's a supplied element from the get-go. so [math]\sum_{n=1}^{\infty} \frac{3}{10^n} = 0.333\dots [/math], and this is also the same exact number retrieved from attempting to translate 1/3 into decimal.

[math]\frac{1}{3} > (\sum_{n=1}^{\infty} \frac{3}{10^n} = 0.333\dots )[/math]

>> No.11509582

>>11509554
imagine losing in math to a 8-year-old

>> No.11509649

>>11509452
Infinity is not a number though. It isn't used to describe a "set-in-stone" amount the same way you'd say there are 10 apples, 7,000,000,000 people, or 365 days in a year.
10; 7,000,000,000; 365; these are all numbers used to describe amounts.
Infinity isn't a number though, so it can't be used the same way.
Infinity isn't "set-in-stone" like 10 is.
10 apples, 10 people, 10 days; regardless of what is being counted, if there are 10 countable elements, then you'll have 10, distinct from 9 or 11.

refer to >>11508995 where the size of the set A is noted. Infinite size here is not some extension of the numberline, but rather it encompasses the numberline. "1", "2", or "10" are all elements within infinity, and not merely in the sense that "1, 2, and 10 are all elements of 13" as if they're implicitly being added together. The never ending possibilities of increasingly large integers greater than 0 are what define infinity.
To say "0.999..." has "infinity 9's" is to say it simultaneously has all consecutive finite counted elements listed within the "infinite" set. But given there is no indication of how all these elements are being simultaneously invoked, be they adding/multiplying/factorializing/etc, (aka 1+2+3+... / 1×2×3×... / etc), then theres no honest sensible approach, and given trying to define "all" elements of something that never-ends, it's even less intelligible. "All" elements of a set with 10 elements is 10. "All" elements of a set with unlimited elements is... not a knowable number.

>> No.11509657

>>11509534
the armenian genocide happened in WW1. your graph starts after WW2.

>> No.11509663

>>11509554
There is nothing in what you said that implies your conclusion that
[math]
\frac{1}{3} > \sum_{n=1}^{\inf}\frac{3}{10^n}
[/math]
which is false.

Also fun fact: Did you know that the infinite decimal exansion 0.000... is equal to to finite decimal expansion 0.0 which is equal to the integral form 0?

>> No.11509664

>>11509582
you must be 18+ to post here.

>> No.11509683

>>11509663
Repeating decimal 0's are an emergent property of final solution.
1/2 = 0.50000000...
1/4 = 0.25000000...
1/8 = 0.12500000...
1/10 = 0.1000000...
Repeating decimal zero's are defacto a sign of final equality because the steps of long division to reach that point technically end.
1/8 = 0.125 is the technical final step, and anything further is just solving [math]0-0 = 0 -0 = 0 -0 ...[/math] pointlessly.

>> No.11509685

>>11509649
>Infinity is not a number though.
I never said it was.

>"All" elements of a set with unlimited elements is... not a knowable number.
I never said anything like this either.

But that does not mean we can't refer all elements in a set.

>> No.11509693

>>11509663
1/3 > 0.3; true
1/3 > 0.33; true
1/3 > 0.333; true
if this continues, it will always remain the same true case.
...
1/3 > 0.333...; true

>> No.11509708

>>11509693
Wrong, review the order limit theorem. You can only conclude that 1/3 >= 0.33333....

>> No.11509709

>>11509693
>if this continues, it will always remain the same true case.
this is simply not true. it's a common beginner mistake, that doesn't make it acceptable.
[math]a_n < K[/math] for all [math]n[/math] only implies [math]\lim_{n\to\infty}a_n \leq K[/math]
[math]x < K[/math] for all [math]x \in A[/math] only implies [math]\sup A \leq K[/math]

>> No.11509710

>>11509693
>>11509509

>> No.11509711

>>11509683
>steps of long division to reach that point technically end
No they don't. They technichally do not end. It is precisely because they technically do not end that I'm able to continue adding zeroes at the end. There simply come a point where it's convenient to stop, because continuing repeating self similar steps just doesn't yield any additional information.

But this whole talk about step of an algorithm is a red herring, because as I said earlier, a decimal expansion (finite or infinite) is not a process. It is a symbol that refers to a real number.

>> No.11509712

>>11509657
Way to miss the point. The graph must be fake since population growth rates are constant, right?

>> No.11509727

>>11509693
>if this continues, it will always remain the same true case.
Not true. Only true for finite decimal expansion 0.3, 0.33, 0.333 etc. Like I'm sure I said in an earlier post.

I don't think you understand how limits work.

>> No.11509733

>>11509685
>I never said it was
>>11509452
>>The never-ending thing about the infinite decimal expansion is the [math]\text{number of decimals}[/math]
>>The infinite decimal expansion... is a symbolic [math]\text{representation of a real number}[/math].
>i never said it was
sounded to me like you were using infinity as a number.

>> No.11509744

>>11509664
classic projection

>> No.11509753

>>11509727
0.3 has how many 3's?
0.33 has how many 3's?
0.333 has how many 3's?
loose answer: a finite amount.

0.333... has how many 3's?
>infinity is not a number
loose answer: an arbitrary finite amount.

I don't think you understand what infinity means. It's analogous with continuous; never-ending.

If you had infinite time to increment from 0 by +1 every second, which case is true?
>a: after an infinite amount of time has passed, you'll have counted through all the integers
Or
>b: you will count finite numbers forever and never stop

>> No.11509756

>>11509733
Ok, fine. I did use the word 'number' in reference to an infinite sequence. Would you have felt more comfortable if I had said
"cardinality of the set of decimal places"?

The point i was trying to make is that anon apparently thinks about infinity as steps of an algorithm that takes time to carry out and must be carried out sequentially.

>> No.11509764

>>11507839
presupposes 0.999...*10=9.999... to begin with

>> No.11509768

>>11509756
everything is carried out sequentially. merely existing to have this retarded argument required a sequence of events. the real question is at which point you're going to figure it out.

>> No.11509771

>>11509753
>an arbitrary finite amount
Wrong again. Arbitrarily large finite =/= infinite. Finite induction does not prove the infinite case.
As an example, you can prove inductively that an arbitrary finite intersection of open sets remains open, but it's easy to construct an infinite intersection that isn't open

>> No.11509790

>>11509753
Again, the infinite decimal expansion is not a process that must be carried out.

In the same sense that the infinite set of natural numbers is not a timed process that must be carried out.
I can refer to, and think about, the entire infinite set in a finite constant amount of time without having to process each individual element sequentially.

Similarly a sequence does not need to 'arrive' at a limit by way of processing each element successively in order for us to know that the limit exists and what it is.

>> No.11509797
File: 83 KB, 384x313, eQ20E.jpg [View same] [iqdb] [saucenao] [google]
11509797

>>11509771
Arbitrarily finite is the measure that can be applied to infinite. It's not that they're not the same and yet permiss the same function. Its that arbitrary finite is the ruler and infinite is the stick. Arbitrary finite is what you can measure and infinite is the thinf you're measuring.
They're not the same cause they're not the same function.

refer back to
>>b: you will count finite numbers forever and never stop
if during this process, someone else asked you what number you were on, you would tell them what number you're on and it would be an arbitrary finite number.
To take a measurement is essential to solving something.
If instead you didn't say which number you were on cause you're intent on "reaching infinity", then whatever value's you're enumerating through will never be useful for anything and your non-response is no better or worse than shrugging or replying with "???".

>how many 3's do we need to calculate on 0.333...?
>"???"
>aight thanks bud

>> No.11509800

>>11509764
True. It is a reasonable supposition though.

>> No.11509801

>>11509797
>They're not the same cause they're not the same function.
>function
you keep using this word and I don't think you know what it means

>> No.11509803

>>11509768
>everything is carried out sequentially
Not in mathematics.

>> No.11509810
File: 267 KB, 534x588, 1551554622542.png [View same] [iqdb] [saucenao] [google]
11509810

>>11509790
>>11509771
>>11509801
>>11509803
>mouthbreathers

>> No.11509811

>>11507933
>>11507960
There world is constrained by a base_n number system, in which case 1/3 always is represented by some irrational repeating number.
>>11508411
>you know that 1/3=0.333...
is equivalent to
>you know that 1=0.999...
Also, pathetic need of the additional assumption that I wouldn't catch this language.
>>11509800
It isn't reasonable to use that supposition in a proof of the same thing. It's circular reasoning to presuppose 0.999...=1, in order to then prove that 0.999...=1

>> No.11509818

>>11509797
You don't measure the infinite with the arbitrary. Instead, you use the arbitrary to show that the infinite can't be measured, and hence show that the infinite must be treated distinctly from the finite. To "measure" or reason about the infinite, you have to use analysis to build a toolkit from the ground up, instead of relying on the tools of the finite that no longer logically apply.

>> No.11509827

>>11509771
0.333... has how many 3's?
>infinity is not a number
what is your answer?
you disagree that it isn't an arbitrary finite amount, but at the same time "infinite" is not a number, and is therefore not applicable to being a number amount. You also disagree the decimal expansion "0.333..." must continue or expand from something. So how do you answer?
0.333... has how many 3's?

>> No.11509833

>>11509827
Your question does not have a defined answer, since the naturals and reals only consist of finite elements. If you'd permit the use of the extended reals, I could give you an answer, but it cannot be a natural or real number, which is what you're looking for.

>> No.11509836

>>11509833
>>11509818
Or another logically consistent answer could be, "the set of threes has the same cardinality as the naturals."

>> No.11509847

>>11509827
your dogma is that "infinity is not a number" and that a question starting with "how many ..." must have a number for an answer. if you insist on this, then your question doesn't have an answer. it's like pointing to a chair and asking "what animal is this?"

>> No.11509861

>>11509833
I think i understand your logic.
Consider inter-mantissa.
>[math] 0.0 < 0.1 < 0.\bar{1} < 0.2 < 0.\bar{2} < 0.3 < 0.\bar{3} < 0.4 < 0.\bar{4} < 0.5 < 0.\bar{5} < 0.6 < 0.\bar{6} < 0.7 < 0.\bar{7} < 0.8 < 0.\bar{8} < 0.9 < 1.0[/math]
you would have that a value [math]\frac{1}{3}[/math] cleanly and decisively equals [math]0.\bar{3}[/math] much the same way that [math]\frac{1}{2} = 0.5[/math]. Put another way, as 0.5 has arbitrary 0's after it denoting full equality and final solution, you would have [math]0.\bar{3}[/math] also be seen in a similar manner. That after this "symbol 3" value, there also exists some imaginary metric of arbitrary 0's denoting final solution and full equality to [math]\frac{1}{3}[/math].

I'm like 90% sure this is what you're trying to convey.

>> No.11509884

>>11509861
The metric I'm using is "a=b iff abs(a-b) < r for all real r>0"

>> No.11509887

>>11509811
>It isn't reasonable to use that supposition in a proof of the same thing. It's circular reasoning to presuppose 0.999...=1, in order to then prove that 0.999...=1
You're right in that the supposition 10*0.999... = 9.99... needs to be proven formally or the rest doesn't count as a proof.
But the first time I encountered this 'proof' I arrived at the above supposition based on my knowledge about how multiplication with decimal numbers worked that had been taught, and some reasonable assumptions about how that might extend to multiplication by 10 with infinite decimals.
I did not need to presopose 0.999...=1 to arrive at the conclusion that 10*0.999... = 9.99...
Instead, based on my guess that 10*0.999... = 9.99... I arrived at the conclusion that 0.999...=1, wich blew my mind at the time. It might be thought of as a sort of "high level" proof that takes for granted som seemingly obvious assumptions, but hinges on those assumptions in fact being correct. You know, like most of education and knowledge. Or if not a proof then a strong indicator.

But yeah, the most stringent proof of 10*0.999... = 9.99... that I know is the proof by limits, which is essentially the same as proving 0.999...=1 directly.

>> No.11509888

>>11509811
In base 3, 1/3 = 0.1

>> No.11509924

>>11509847
I would consider it more like taking a photo. If i said "hey, turn around and take a photo!" And you immediately turned around and took a photo (for the sake of convenience, its a polaroid and prints instantly), will you actually know what's going to show up on the photo before you see the photo? You were facing the opposite direction the moment before the photo was taken, so you had no idea what was going on behind you. What things were moving, where things were moving towards, it's literally quite a mystery to you until the photo prints and shows you a vertical slice of what was occurring. But once you have your photo, your snapshot, your measure of a moment, you can definitely tell what things were moving and where they were moving towards when comparing the photo to things as they unfold.

What i'm saying is, a photo is a finite measurable freeze-frame of the expansion of time since before last thursday. Much the same as 1/3 = ??? becomes 1/3 = 0.333... once you make the measurement.

If you solve it via long division (0.333...) well those repeating 3's tend toward a finite end because you'll either get bored of writing 3's or decide a certain amount of decimal digits is enough.
If you solve it via magical numbers ([math]0.\bar{3}[/math]) gets rendered instantly (like [math]\frac{1}{2} = 0.5[/math] is instant), but now you have to explain where magical numbers come from and why they need to exist.

>> No.11509927 [DELETED] 

>>11509924
>cont.
I'll have you know that these inter-mantissa magical numbers, provided the accomodation in >>11509861 where
>after this "symbol n" value, there also exists some imaginary metric of arbitrary 0's denoting final solution and full equality inherently implies a couple things, such as there is an end to the 3's (they're not "infinite") so 0's can come after, and if 0's come after, would require [math]\sum_{n=1}^{\infty} \frac{3}{10^n}[/math] produce those 0's at [math]n=\infty[/math] for [math] \frac{3}{10^{\infty}} = 0[/math] which requires infinity be a sequentially reachable number incrementing from a real number, which means it's also a finite end to the numbers, and then suddenly literally everything you believe in is so fucking mind-fuckingly retarded that it required this entire thread to explain to you why what you vehemently defend as true is instead actually just fucking fanfiction.

>> No.11509930

I'll have you know that these inter-mantissa magical numbers, provided the accomodation in >>11509861 where
>after this "symbol n" value, there also exists some imaginary metric of arbitrary 0's denoting final solution and full equality
inherently implies a couple things, such as there is an end to the 3's (they're not "infinite") so 0's can come after, and if 0's come after, would require [math]\sum_{n=1}^{\infty} \frac{3}{10^n}[/math] produce those 0's at [math]n=\infty[/math] for [math] \frac{3}{10^{\infty}} = 0[/math] which requires infinity be a sequentially reachable number incrementing from a real number, which means it's also a finite end to the numbers, and then suddenly literally everything you believe in is so fucking mind-fuckingly retarded that it required this entire thread to explain to you why what you vehemently defend as true is instead fucking fanfiction.

>> No.11509957

>>11509924
>If you solve it via long division (0.333...)
But you can never do that. Solving it via long division you will never arrive att 0.333... because that would require infinite positive-time steps, i.e. infinite time. What you can do is realise that you're repeating self-similar steps, so you can conlude what the limit number looks like. You can therefore shortcircuit the process and arrive at an infinite decimal number expansion in a finite time. And that's where the magic number comes from.

>> No.11509972

>>11509957
>lets pretend infinite is finite

>> No.11509979

>>11509827
>0.333... has how many 3's?
aleph-0

>> No.11509998

>>11509972
How do you even have problem with this? If you keep recursively performing self similiar steps that result in a three, you know you're not suddenly going to get a four at some decimal place.

>> No.11510020

>>11509452
>>the matter is it never will, because that's what infinity evokes. never-ending.
>The never-ending thing about the infinite decimal expansion is the number of decimals, not the amount of time it would take to write out all the decimals one after the other.

i think there was a momentary split of coherence here. You seemed to think "never" was a function of time, but it's just as easily conveyed via a single-notion comparison of "is" or "is not"
if "1 is never 2", it means the same as
"1 is not 2"

so if "0.333..." is 'trying it's darndest to reach 1/3', the emergent property of there being unending 3's means it never actually reaches 1/3.
>0.333... is never 1/3
>0.333... is not 1/3

>> No.11510036

>>11508259
9.99999... = 10
99.9999... = 100
and so on

>> No.11510051

>>11509998
the question isn't whether or not the 3's continue, that much is very obvious. the 3's continue. there indeed wont be a 4.

the question is what does "infinite" mean?
>arrive at an infinite decimal number expansion in a finite time
i feel the wording of this assumes "infinity" is reachable.

it's one thing to say the 3's continue.
it's another thing to say the 3's continue decisively further than unimaginably long, which is what "infinitely" means to me. Saying it with such defacto certainty makes it seem like an infinity has already been achieved in whole during the course of human history and has been bounded, contained, and conveniently packaged in a nice little concept that can be as easily or discretely understood as the integer "1" without ambiguity, and because it has such a similar packaging it must therefore be allowed to be used similarly as discrete integers.

>> No.11510070

>>11508806
wtf is this? lol schizo

>> No.11510125

>>11510020
>"0.333..." is 'trying it's darndest to reach 1/3',
This wording would suggest a process. But 0.333... is not a process. It is a number.

> the emergent property of there being unending 3's
Ok, but all the 3's are all there without the need to proces each of them.

>means it never actually reaches 1/3.
It doesn't "reach", because again, it is not a process. It doesn't follow from this that "0.333... is not 1/3".

In fact it turns out that 0.333... is 1/3. How?
By recognizing that 0.333... is the limit of the infinite sequence of numbers 0.3, 0.33, 0.333, ...
The number 0.333... is not in this sequence, nor does the sequence ever reach 0.333... None the less, 0.333... is the limit of the sequence.
It can also be shown through analysis, that 1/3 is also the limit of the sequence. Therefor we
conclude that 1/3 = 0.333...

>> No.11510170

>>11510125
So you cannot pin a number amount on the amount of 3's in "0.333...", arrive at some arbitrary conclusion that "0.333..." is a simple-as decimal number which plainly just exists as discernibly as any integer might, and that this decimal number "0.333..." explicitly equals the fraction 1/3, just because you're confusing limit with equality?

1/3 is the limit of what "0.333..." is... well, not TRYING to reach because you don't hive with that vocabulary... so..
1/3 is the limit of what "0.333..." ... is?
Is that what you're saying?
(0.333...)'s limit is (0.333...)
...
???

>> No.11510185

>>11510051
>makes it seem like an infinity has already been achieved
Well, yes. We could say that infinity has been achieved.
When we write 0.333..., that is a finite notational convention to refer to a zero followed by a decimal point and them infinitely many threes. We have a finite way of writing something infinite. We do not need to process or reach each 3. Simply by definition of the notation, we know that all the 3's are there, each in their right place. As such, one you say that we have "achieved infinity". But then again, i wouldn't say "achieved" because as I keep saying, we are not dealing with a process.

>> No.11510187

>>11510170
what 0.333 IS NOT:
a process
a measurement

what 0.333... IS:
a number, i.e. a definite point on the number line

>> No.11510206

>>11510170
Let S be the infinite sequence (0.3, 0.33, 0.333, ...)

The limit of S is 1/3
The limit of S is 0.333...
1/3 is 0.333...

>> No.11510216

>>11510125
I think your issue is that you're still clinging to the idea that 1/3 = 0.333... even though a simple proof was provided via division steps.
>1/3 > 0.3
>1/3 > 0.33
>1/3 > 0.333
>assume any continuation of this process results in the ever-continuing process of:
>1/3 > 0.333...
it holds true for any and all continuities of 0.333...'s expansion, and that is what both "infinity" and the "..." notation accomodate or imply.
Continuation.

Alternatively, using your notation:
> 1/3 > [0.3]
> 1/3 > [0.3, 0.33]
> 1/3 > [0.3, 0.33, 0.333]
> ...
> 1/3 > [0.3, 0.33, 0.333, ...]

>> No.11510248

>>11510206
>The limit of S is 1/3
>The limit of S is 0.333...
Each of these statements inherently invalidates the other. Only one can be true. Technically the second one isn't true at all cause you appear to be assuming 0.333... has n-discernible difference over a real number n amount of 3's appearing incrementally in each element if the set defining the sequence.
In essence, what you're saying is [0.3(n+1 amount of 3's) is the limit of 0.3(n amount of 3's), which
>1. is stupid
and
>2. defies your assumption of (0.333...)'s discrete behaviour, which it can't very well be discrete if it's constantly changing. The integer 1 never changes into another number, nor does it's size change.

>> No.11510261

>>11510216
This was false the two previous times you posted it, and it keeps being false.

>it holds true for any and all continuities of 0.333...'s expansion
No it doesn't. It only holds true for any and all FINITE "continuities of 0.333...'s expansion"

>> No.11510285

>>11510248
>Only one can be true
Which would make them both the same statement. Which means the 1/3 is 0.333...

>[0.3(n+1 amount of 3's)] is the limit of 0.3(n amount of 3's)
No, that's not how limits work.
[0.3(n amount of 3's)] is the limit of 0.3(n amount of 3's)

(this is sort of a weird notation for limits and sequences you've invented here, but i'm trying to work with it)

>> No.11510288

>>11510170
the definition of 1/3 is:
divide [0,1] into three parts of the same length. this number is the left end point of the second part.

the definition if 0.333... is:
this number lies in [0,1]
this number lies in [3/10,4/10]
this number lies in [33/100,34/100]
this number lies in [333/1000,334/1000]
this number lies in [3333/10000,3334/10000]
...

this is literally the definition of decimal expansion

>> No.11510300

>>11510261
ALL EXPANSIONS OF 0.333... ARE FINITE
ANY
ALL
EVERY
WHY?
BECAUSE INFINITY IS DEFINED BY THE FINITE >>11508995

" A L L " values within the INFINITE set are FINITE, and sequencing THROUGH " A L L " values of the infinite set is what DEFINES infinity.
However "ALL" elements of an un-numbered length set returns NO KNOWABLE NUMBER to represent the AMOUNT OF ELEMENTS in the set. Infinity represents it, but infinity is an adjective, an adverb, not a noun, and definitely not a NUMBER.

this does not mean "continue using '...' notation and just fuck around"
It means STOP FUCKING USING "..." NOTATION CAUSE IT DOESN'T MEAN ANYTHING.

IF YOU DON'T TEST HOW MANY 3'S THERE ARE, THERE ARE JUST AS LIKELY TO BE ONLY 1.
0.3

IF YOU TEST HOW MANY 3'S THERE ARE, YOU MAKE AN OBSERVATION TO AN ARBITRARY FINITE DEGREE BOUND WITHIN THE SET OF INTEGERS, WHICH IS AN ARBITRARY FINITE NUMBER.
A NUMBER WHICH WILL NOT BE PREDESTINED FOR YOU, BUT A NUMBER WHICH YOU MUST PROVIDE, FOR IT MUST BE A REAL NUMBER AMOUNT OF 3'S BECAUSE INFINITY IS NOT A NUMBER AMOUNT AND FAILING TO TEST ASSUMES ONLY ONE 3.
0.3
don't use [math]0.333\dots[/math]
use [math]0.333\dots_{x=n}[/math] to determine the degree of your REQUIRED DECIMAL ACCURACY LIMIT.

>> No.11510306

>>11510248
a sequence can have at most 1 limit
if you know that the limit of this sequence is some real number A
and if you know that the limit of this sequence is some real number B
the only logical conclusion is that A = B

this is how math actually works how weird is that

>> No.11510309

I need 33 decimals of accuracy on 1/3
>[math]\frac{1}{3} > 0.333..._{x=33}[/math]

simple as.

>> No.11510321

>>11510300
>ALL EXPANSIONS OF 0.333... ARE FINITE
The expansion of 0.333... is infinite

0.3 finite
0.33 finite
0.33333333333333333333333 finite
0.333... infinite

See how that works?

>> No.11510326

>>11510300
>It means STOP FUCKING USING "..." NOTATION CAUSE IT DOESN'T MEAN ANYTHING.
"..." in 0.333... means that the n-th digit is 3 for all n

>> No.11510327

>>11510300
>FOR IT MUST BE A REAL NUMBER AMOUNT OF 3'S
No it doesn't. It's an INFINITE DECIMAL EXPANSION. By the very definition of INFINITE DECIMAL EXPANSION it can not have a real number amount of 3's. That's what INFINITE DECIMAL EXPANSION means.

>> No.11510335

>>11510321
sequencing through the set of all integers is an infinite process.

0.333... does not contain "infinite 3's"
0.333... contains an arbitrary finite amount of 3's that you're willing to work with and compute upon.
0.3 + 0.3 = 0.6
0.33 + 0.33 = 0.66
0.333 + 0.333 = 0.666
0.3333 + 0.3333 = 0.6666
>if "0.333..." truly contains infinite 3's
>then:
0.333... □ □ □
well shit i'm trying to add another "0.333..." after it but I can't even make it to the addition sign because i have to spend the rest of fucking forever writing out more 3's so i can actually accurately do real fucking math on actual digits and not just made-up math on retarded assumptions of ignorance!

>> No.11510368

>>11510335
I'm not even sure you're the same anon I began this discussion with.

>0.333... does not contain "infinite 3's"
Yes it does. It does by definition of the notation.

>well shit i'm trying to add another "0.333..." after it
well shit i'm trying to add another "0.333..." after it but I can't even make it to the addition sign
You just write 0.333... + 0.333... That's the whole point of the ... elipsis notation: to not having to spend the rest of fucking forever writing 3's.

Decimal expansion is just a notation for refering to a number. It doesn't change the number's place on the number line. The number still follows all the usual arithemtic laws.

>> No.11510373

>>11510335
>>11510368
As it turns out:
0.333... + 0.333... = 0.666...

>> No.11510393

[math]\frac{1}{3} > 0.333... \\ \\ 3(\frac{1}{3}) > 3(0.333...) \\ \\ \frac{3}{3} > 0.999...[/math]
>1/3 > 0.333...
>...
>1/3 > 0.3333
>1/3 > 0.333
>1/3 > 0.33
>1/3 > 0.3
T R U E
ALL CHECKS OUT!

[math]\frac{1}{3} = 0.333... \\ \\ 3(\frac{1}{3}) = 3(0.333...) \\ \\ \frac{3}{3} = 0.999...[/math]
>1/3 = 0.333...
>...
>1/3 = 0.3333
>1/3 = 0.333
>1/3 = 0.33
>1/3 = 0.3
F A L S E
ITS ALL WRONG

>> No.11510398

>>11510393
This is nonsense.

>> No.11510407

>>11508439
Prove it wrong, faggot. Find a number strictly inbetween 1 and .999...
The reals are dense, therefore there should be an INFINITE number of numbers for you to use. Pick one and show me, or shut your retarded ass up.

>> No.11510409

>>11510398
"..." means "continued"
shocker, i know.

>> No.11510410

>>11508439
>You're really proud of this image and constantly repost
Imagine being stupid enough to believe that /sci/ is one person. You don't, but others might have to.

>> No.11510412

>>11508444
Autism =/= wrong. The image is, potentially, proof of that.

>> No.11510420

>>11508466
Retard, he said it RESULTS in contradictions. He did NOT say that it IS a contradiction. Learn to read, faggot.

>> No.11510424

>>11510410
Surely no one else but the retarded author would care enough to name an image that is also full of easily disproveable retard tests which only the author could believe in.

>> No.11510426

>>11508448
You are fully within your rights to make an image with objectively wrong information. I would strongly suggest you not do that, but you can.

>> No.11510431

>>11509455
>Real numbers are literally the same as geometric constructs.
Fucking kill me.

>> No.11510437

>>11509811
>1/3 always is represented by some irrational repeating number.
What definition of "irrational" are you using? I ask because you're clearly not using a definition that people who actually understand math use.

>> No.11510448

>>11510393
What does 1/3 equal in decimal notation according to your retard logic?

>> No.11510454

>>11510409
Usually 'continued' in this context means continued infinitely.

If you refuse to accept that and keep insisting that is means continoued with a finite amount of 3s, then we need another notation that you can accept for the concept on infinite decimal expansion, so we can at least discuss the same topic.

>> No.11510464

>>11510424
Then fucking disprove it if it's so easy.

>> No.11510472

>>11510437
Irrational is inequal.
Pi is equal to a decimal number that has not been fully discovered, such that the decimal evaluation of pi must therefore be strictly less than the "number" [math]\pi[/math]
3 < pi
3.14 < pi
3.141 < pi
3.1415 < pi
this continues forever for all discoverable decimal digits of evaluating pi

property of irrationality.
0.3 < 1/3
0.33 < 1/3
0.333 < 1/3
0.3333 < 1/3
This continues forever for all discoverable decimal digits of evaluating 1/3

>> No.11510479

>>11510448
It wouldn't have one, according to anon, I think.

>> No.11510484

>>11510472
>Pi is equal to a decimal number that has not been fully discovered
how many digits does this decimal number have ?

>> No.11510487

>>11510472
Stop making up and misusing mathematical terminology.

>> No.11510499

>>11510472
Why are you lying by implying that you know what you're talking about?

>> No.11510500

>>11510487
Eat shit nigger retard, irrationality has other elements but unending expanding decimal is literally one of the defining features.

>> No.11510509

>>11510500
>Irrational is inequal.
That's the misusing part, you idiot.

>> No.11510511

>>11510472
I have no illusions of changing you mind, but you should know that your definiton does not agree with the usual definiton of irrational number, that most everyone else uses.

An irrational number is on that can not be written as a fraction p/q, where p and q are integers.

Pi, the ratio between a the area of a circle and the square of the radius of the same circle, is irrational.

3.1415 can be written 31415/10000 and so is rational.

0.3 = 3/10 is rational
0.33 = 33/100 is rational

1/3 is rational

>> No.11510515

>>11510472
and since the pattern continues, by your logic
3 < pi
3.14 < pi
3.141 < pi
3.1415 < pi
..
pi < pi

>> No.11510527

>>11510509
Defining where the decimal place at which the irrational expanding decimal suddenly equals the value of it's limit is your burden to prove, if you feel that way.
Pi > 3
Pi > 3.1
Pi > 3.14
How many decimal digits are needed to equate pi?
Reminder: infinity is not a number amount, because it isn't even a number

:p

You telling me you never thought about this shit even once in your fucking life?

>> No.11510534

>>11510515
Nigga even all 50 trillion known decimal digits of pi still aren't there. You gonna pretend to know more than the ones that have been discovered?
You got a 10% chance of guessing the immediately next digit correctly, go for it fag.

>> No.11510551

>>11510534
completely irrelevant. explain how is

0.3 < 1/3
0.33 < 1/3
0.333 < 1/3
..
0.333... < 1/3

different from

3 < pi
3.14 < pi
3.141 < pi
3.1415 < pi
..
pi < pi

>> No.11510560

>>11510527
Don't change the subject, subhuman. We are talking about your objectively WRONG definition of irrational. We need to clear up you not knowing BASIC mathematical terminology before we can get to anything proof related.

>> No.11510562

>>11510551
All the digits of 0.333... are known?

>> No.11510566

>>11510551
That would require explaining to you how much of a retard you are for thinking infinity is something which exists or is applicable to knowing "infinite" digits of pi.

You can read the rest of the thread for that, i've already shown it dozens of times.

>> No.11510571

>>11510562
Yes. It doesn't matter what n is, the nth decimal will be 3. So yes they are all known, even if we haven't "discovered" them yet.

>> No.11510579

>>11510566
Infinity does exist mathematically. Stop being a mathematical version of a creationist.

>> No.11510584

>>11510571
n'th decimal = real number decimal, just make sure to remember that part too.

>> No.11510585

>>11510566
>That would require explaining to you how much of a retard you are for thinking infinity is something which exists or is applicable to knowing "infinite" digits of pi.
I don't need to invoke infinity at all to define 0.333... or a decimal expansion of pi.
>You can read the rest of the thread for that, i've already shown it dozens of times.
you haven't shown nothing, all your claims are getting disproved over and over

>> No.11510590

>>11510579
Ironic when you treat infinity as infalliable as a creationist treats the bible, you utter cumstain retarded hypocrite of a failed experiment.

>> No.11510600

>>11510571
This is completely retarded, FYI.

>> No.11510605

>"infinity exist!"
>prove it
>"no proof needed, its unfalsifiable XD"

>"god exist!"
>prove it
>"no proof needed, its unfalsifiable XD"

[math]I R O N Y[/math]

>> No.11510610

>>11510590
Infinity does exist because, just LITERALLY EVERYTHING ELSE IN MODERN MATH, we defined it using an axiomatic system.

>> No.11510615

>>11510600
Enlighten me, what is the nth digit if not 3?

>> No.11510617

>>11510610
axiom of infinity is LITERALLY a joke you penis head.

>> No.11510618

>>11510585
>I don't need to invoke infinity at all to define 0.333... or a decimal expansion of pi.
Technically you do. Any finite decimal expansion will not be pi.

>> No.11510630

>>11510617
1) Stop misusing literally.
2) Prove it. Prove it's a "joke". Find an actual contradiction instead of whining about how it "doesn't exist".

>> No.11510633

>>11510615
The retarded bit your definition of irrational, that you think this question is relevant.

>> No.11510634

>>11510605
Your dishonest comparison is not appreciated. Infinity exists because we defined it, and it doesn't lead to contradictions.

>> No.11510642

>>11510618
technically all I need is the universal quantifier
I don't need to actually carry out an infinite process

>> No.11510650

>>11510633
>The retarded bit your definition of irrational, that you think this question is relevant.
"what is the n-th digit" is actually the only relevant question regarding decimal expansions lmao

>> No.11510654

>>11510633
Don't dodge the question. What is it?

>> No.11510663

>>11510630
axiom of infinity allows for 1 infinity to exist, and that infinity is describing the size of the set of all natural numbers.
I constructed this set in >>11508995 and sourced a /sci/ trusted go-to to insure infinity is not a number, which makes it's application to the size of the set of "all" numbers functionally identical to the word "unlimited".

The greater issue exists with the assumption of whether or not "unlimited real numbers" do in fact exist.
If humanity was destroyes by a meteor, who'd be around to continue counting?
Whatever largest real number that had been instantiated at that point would therefore in fact be the last number, and the amount of number usage would no longer increase.

If you don't like the philosophical angle, whatever. It's not even required.

>> No.11510664

>>11510642
You still can't consider infinite decimal expansions without invoking infiniti. The concept infinity is inherent in the concept infinite decimal expansion.

>>11510650
No. The decimal expansion of pi has been show to be infinite without anyone knowing the n:th digit for every n.

>> No.11510670

>>11510663
>axiom of infinity allows for 1 infinity to exist,
Well, that's a shitty axiom since the infinity of the reals is known to be greater than the infinity of the naturals.

>> No.11510674

>>11510634
>god created us and we created infinity(god)
>chicken created the egg which then hatched into the chicken which laid it
>not a contradiction
infinity's definitions and usages are so laughably contradicting that it seems like an inescapable law of the universe that it can't actually exist.
You are so, so wrong.

>> No.11510680

>>11510663
And from that axiom we proved that there exists more infinities than just the one explicitly defined.

>> No.11510683

>>11510674
>infinity's definitions and usages are so laughably contradicting
give one example

>> No.11510689

>>11508995
>contain them between and opening and closing bracket, defying the definition of infinity being "unbounded".
You are retarded.

>> No.11510695

>>11510674
>infinity's definitions and usages are so laughably contradicting
also do you consider quantifying over natural numbers as usage of infinity? because that's all you need to define, say, decimal expansions and limits

>> No.11510706

>>11510674
FUCKING PROVE IT! If it's so easy and laughable, then it should be easy for a "genius" like you to find one. Do it. Do it now. Don't change the subject, just do it now.

>> No.11510710

>>11510634
https://www.wolframalpha.com/input/?i=infinity
>Infinity is an unbounded quantity greater than every real (and every whole) number.
https://www.wolframalpha.com/input/?i=quantity
>a Quantity is how much there is or how many there are of something that you can quantify
https://www.wolframalpha.com/input/?i=quantify
>to Quantify is to express as a number or measure or quantity
https://www.wolframalpha.com/input/?i=is+infinity+a+number%3F
>∞ is not a number
https://www.wolframalpha.com/input/?i=Does+1%2F%28not+a+number%29+%3D+1%2Finfinity%3F

circular, contradicting, utterly retarded.
thanks infinity.

>> No.11510722

>>11510689
learn what boundaries are, autismo.
I mean it in more than one way.

>> No.11510727

>>11510710
>circular, contradicting, utterly retarded.
give one example

>> No.11510732

>>11510727
the whole post one example. There are 1 more in this thread.
Digest glass, [math]senpai[/math]

>> No.11510738

>>11510710
>https://www.wolframalpha.com/input/?i=Does+1%2F%28not+a+number%29+%3D+1%2Finfinity%3F
It literally says the exact opposite of what you claim it says, lying retard.

>> No.11510743

>>11510732
https://www.wolframalpha.com/input/?i=Does+%28not+a+number%29+%3D+infinity%3F
Lying retard. It literally says that "not a number" is not the same as "infinity".

>> No.11510744

>>11510722
I think you should learn what mathematics is. You don't seem to have a single clue.

>> No.11510754
File: 165 KB, 800x800, 1524043147486.jpg [View same] [iqdb] [saucenao] [google]
11510754

>>11510738
>is ∞ a number?
>>no
>is "1/(not a number) = 1/∞" true?
>>no
goddamnit you fuck

>> No.11510771

>>11510754
I hope you never try to learn javascript.

>> No.11510778

>>11510743
It says infinity is not a number

therefore infinity = (not a number)

1/(NaN) = some bullshit irreducible letter-a symbol, may as well be undefined. Doesn't do jack shit.

but 1/infinity = 0
they should have the same result, both aren't numbers.
https://www.wolframalpha.com/input/?i=%281%29+divided+by+%28potato%29

says infinity isn't a number, but treats it as number for arithmatic. says it isn't a number, but defines it as a quantity, where quantites are defined by numbers.

>> No.11510803

>>11510754
>>11510778
You are either lying or so stupid that I can't comprehend it. The link does NOT say "Is infinity a number". What the fuck is happening? It says "is infinity equivalent to "not a number"" and it answers "false". It literally says the exact opposite of what you say it does, but you are so stupid that you can't understand how double negatives work. Knowing how to work with double negatives is below Jr. High algebra level math. How the fuck did you not understand this? I'm completely shook.

>> No.11510812

>>11510803
>but you are so stupid that you can't understand how double negatives work.
Maybe they're Polish?

>> No.11510857

>>11510803
there are multiple links in that post, coombrain anon.

>> No.11511153

>>11510664
https://mathworld.wolfram.com/PiDigits.html
formula (3)
A recursive formula, conjectured to give the nth hexadecimal digit of pi-3

>> No.11511196

>>11511153
[math]
\boxed{ \text {nth hexadecimal of} ~ \pi -3} \\
x_0=0\\
x_n= \text{frac} \left ( 16x_{n-1}+\frac{120n^2-89n+16}{512n^4-1024n^3+712n^2-206n-21} \right )
\\
d_n=\left \lfloor 16 x_n\right \rfloor
[/math]