/sci/ - Science & Math

[Anonymous No.11502031]

>eat a quark
>no taste
they lied

[Anonymous No.11502064]

>>11502031
strange

[Anonymous No.11502099]

[math]
\Psi = \text{e} ^{ \text{i}(kx- \omega t)}~~~(= \cos(kx- \omega t)+ \text{i} \sin(kx- \omega t)~) \\
\dfrac{ \text{d} \Psi }{ \text{d} x}= \text{i}k \, \text{e} ^{ \text{i}(kx- \omega t)}= \text{i}k \Psi \\
\dfrac{ \text{d}^2 \Psi}{ \text{d}x^2}= \text{i}k \, \text{i}k \Psi= -k^2 \Psi \\
k= \dfrac{p}{ \hbar}~~~~~ \left ( [k]=~ \frac{kg \cdot \frac{m}{s}}{J \cdot s}= \frac{kg \cdot m}{Nm \cdot s^2}= \frac{kg }{kg \cdot \frac{m}{s^2} \cdot s^2}= \frac{1}{m}~ \right ) \\
\dfrac{ \text{d}^2 \Psi}{ \text{d}x^2}= -\dfrac{p^2}{ \hbar^2} \Psi \\
- \hbar^2 \, \dfrac{ \text{d}^2 \Psi}{ \text{d}x^2}= p^2 \, \Psi \\
E= E_k+E_p= \frac{p^2}{2m}+E_p \\
E \Psi= \frac{p^2}{2m} \Psi+E_p \Psi=\frac{p^2 \Psi}{2m}+E_p \Psi=\dfrac{- \hbar^2}{2m} \, \dfrac{ \text{d}^2 \Psi}{ \text{d}x^2}+E_p \Psi \\
[/math]

[Anonymous No.11502171]

>>11502099
/thread
fuckin owned

[Anonymous No.11502185]

>>11502031
you needed more charm

[Anonymous No.11502211]

>>11502099
>not using \partial
Unreadable

[Anonymous No.11502268]

>>11502031
Get better quark, then, or better yet, make it yourself.