/sci/ - Science & Math

[Anonymous No.11453435]

>it ain’t B

[Anonymous No.11453445]

[Anonymous No.11453478]

>>11453445
What the fuck is the answer? The longest distance that I see from A is 2 + sqrt2, which is B.

[Anonymous No.11454220]

how the fuck is that thing supposed to be a cube when one side is 2

[Anonymous No.11454279]

Lolling hard irl

[Anonymous No.11454415]

>>11454220
It ain’t B

[Anonymous No.11454430]

>>11453478
hint: just b yourself

[Anonymous No.11454925]

>>11453445
B. the hint is a trick.

[Anonymous No.11455061]

>>11453445
Holy shit I just computationally verified it's actually not b! You're not trolling. Gonna spend some time trying to find the maximum point analytically.

[Anonymous No.11455091]

Alright I figured it out. The maximum distance is [math]\sqrt{\frac{85}{9}}[/math]
Is that correct OP?

[Anonymous No.11455097]

>>11455091

[Anonymous No.11455119]

>>11455091
worked solution?

[Anonymous No.11455122]

>>11455097
correction

[Anonymous No.11455461]

>>11454925
It ain’t B

[Anonymous No.11455492]

>>11455122

(1+4+1)^0.5 = 2.449

(1+4+2/3)^0.5 = 2.380

It is B you dumb fucks.

[Anonymous No.11455494]

>>11455492
It ain’t B

[Anonymous No.11455557]

>>11455494
x^2+y^2+z^2=a
(x-b)^2+y^2+x^2=a+b^2-2bx

if x>b, then x=b+c where c is positive
b^2-2*(b^2+bc) = -b^2-2bc

thus (b^2-2bx) is negative
therefore (x-b)^2+y^2+x^2=a-d where d is positive

thus (x-b)^2+y^2+x^2 < a
thus ((x-b)^2+y^2+x^2)^0.5 < a^0.5

therefore ANY subtraction from the largest extent of a cuboid will reduce the distance

therefore A->B is the biggest distance

[Anonymous No.11455567]

>>11455557
Sorry bro it ain’t B

[Anonymous No.11455732]

>>11453435
its C