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/sci/ - Science & Math

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11280343 No.11280343 [Reply] [Original]

Why wouldn't this work?

>> No.11280350

angle > curve

>> No.11280353

Because pi is not 4

>> No.11280361
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11280361

>if a circle was a square, pi would be 4
wow

>> No.11280372

>>11280343
4! = 23.999...

>> No.11280386

>>11280361
I think the largest pi would be a triangle.
The smallest pi is a line (circle).
The question is, what would pi be if a circle were a triangle?

>> No.11280401

>>11280353
If you draw a square around the circle and proceed to do the demonstrated steps it will be 4.
>>11280372
Which only further proves the point that 3.14 is not the true number.

>> No.11280407

>>11280343
convergence doesn't imply convergence of derivatives

>> No.11280413

>>11280350
>infinite angles making up a curve
A fractal circle

>> No.11280461

>>11280413
>infinite angles
aka smooth

>> No.11280474

>>11280372
4! = 23.999...
23.999... = 24.000...
24.000... = 3.14!

4 = 1 = 3.14

>> No.11280489

>>11280461
That can't be right. Pi can't be infinity!

>> No.11280492

>>11280407
this is the actual reason

>> No.11280494

>>11280407
based /thread

>> No.11281244

Pi is 4 in the taxicab metric

>> No.11281246
File: 1.96 MB, 1440x2984, troll.png [View same] [iqdb] [saucenao] [google]
11281246

>>11281244
this.

>> No.11281251

>>11280343
The excess area does not shrink. It only gets divided differently each step.

>> No.11282193

>>11281251
holy hell you're retarded don't reproduce

>> No.11282204
File: 78 KB, 798x490, 1554826928442.png [View same] [iqdb] [saucenao] [google]
11282204

>>11280343
>>11280361
is this the power of the human intellect?

>> No.11284330

>>11281246
>incel wall of text
cope

>> No.11284351

>>11280407
/thread

>> No.11284433 [DELETED] 

>>11280343
This is just pointwise convergence.
The limit obtained this way does not end up representing the smooth geometric shape that e.g. over (0,1) has the parametrization [math] y(x) = \sqrt{ 1-x^2 } [/math].

>> No.11284436 [DELETED] 

Or, when I already speak of parametrizations, I should rather say

[math] \langle t , \sqrt{1-t^2} \rangle [/math]

>> No.11284438 [DELETED] 

>>11280343 (OP)
This is just pointwise convergence.

The limit obtained this way does not end up representing the smooth geometric shape that e.g. over (0,1) has the parametrization

[math] t\mapsto \langle t, \sqrt{1-t^2} \rangle [/math]

>> No.11284440

>>11280343
This is just pointwise convergence.

The limit obtained this way does not end up representing the smooth geometric shape that e.g. over (0,1) has the parametrization

[math] t \mapsto \langle t, \sqrt{1-t^2} \rangle [/math]

with slop

[math] t \mapsto \langle 1, -\frac{t}{\sqrt{1-t^2}} \rangle [/math]

>> No.11284598
File: 12 KB, 687x388, NANI.png [View same] [iqdb] [saucenao] [google]
11284598

>> No.11284600

>>11284598
Perfectly summarizes everything about OP and this
/thread

>> No.11284603

>>11284600
but that's just a restatement of the original pic

>> No.11284608

>>11284603
So you believe that the red line and black line have equal lengths because one converges on the other?

>> No.11284633

>>11284440
>This is just pointwise convergence.
that's not necessarily true. it can be parametrized such that the convergence is uniform, but it still doesn't imply convergence of arc length.

>> No.11284656

>>11280343

pi is defined as C/d. this just shows that your series of path lengths (which is constant) does not converge to pi.