[ 3 / biz / cgl / ck / diy / fa / ic / jp / lit / sci / vr / vt ] [ index / top / reports ] [ become a patron ] [ status ]
2023-11: Warosu is now out of extended maintenance.

/sci/ - Science & Math


View post   

File: 45 KB, 626x600, high iq.jpg [View same] [iqdb] [saucenao] [google]
11240052 No.11240052 [Reply] [Original]

>> No.11240057

>>11240052
4 of the objects looks like dicks
the answer is 5

>> No.11240126

>>11240052
The title threw me off and I spent a while looking for patterns of horizontal, diagonal, etc inversion, position by number of sides, and else. Then I realized it’s just a kindergarten question where you match the shapes into the proper holes

>> No.11240130

>>11240052
is it 5 ?

>> No.11240133

>>11240052
probably 5. makes the most sense based off the pattern.
all the shapes have to reoccur. but the circles only attach once, semis twice, triangles three, and squares four.
4 defies that.
thus it should be 5.

>> No.11240143

>>11240133
Oh yeah I forgot to mention that this was fucking trivial and childish. So I assume your actual question had nothing to do with the answer, and more with something that is absolutely retarded?

>> No.11240144

>>11240052
Answer is obvious. Circles are connected to other objects by one edge, and objects with two or more vertices are connected to other objects by an edge at each vertex. The pattern would be even better if a teardrop shape were used instead of a circle.
Here we have a triangle, two semicircles, and a circle. The triangle must be connected by three edges, each semicircle by two, and the circle by one. The only visible choice that satisfies these conditions is 5.

>> No.11240170

>>11240057
t. high iq poster that can discern the irony of this post

>> No.11240172

>>11240052
I didn't even realize it was a test and just saw a bunch of merchants

>> No.11240173

>>11240052
#3 is a happy merchant, rotated 90 degrees ccw

>> No.11240179

>>11240143
Yes, hence the ironic intent of this post

>> No.11240180

it needs to contain the shapes in the above picture, while adhering to the rule that it has a number of lines attached to it equal to the number of sides its shape has. So figure 5
Harder please troll

>> No.11240187

>>11240057
all of this

>> No.11240192

>>11240179
Yeah I know, that's why I called it retarded.
An entire thread dedicated to being a faggot. Great.
I love /sci/, hope to see more.

>> No.11240198

>>11240052
Actually low IQ question

>> No.11240201

>>11240180
Oh yeah number of sides makes sense too.

I thought you just had to connect every corner, except for the circles, which always have 1 connection. Though I also arrived at 5

>> No.11240207

>>11240052
Number 3 please

>> No.11240212

>>11240198
that

>> No.11240213

>>11240057
>>11240143
>>11240144
>>11240170
>>11240172
>>11240173
>>11240198
Holy based.

>> No.11240320

The fact that OP believes that this is a "high iq question" makes me think that he's just a low iq retard

>> No.11240338

there's an abstract merchant in there along with the cock and balls

>> No.11240382

>>11240052
5

This was too easy. I wish solving this meant something. It doesn't.

Two things to notice when solving.

1. The shapes, obviously
2. The number of connector lines coming from the shape.

>> No.11240388

>>11240057
Ya, the bikini girl is the straight answer and the correct one.

>> No.11240390

>>11240382
>The number of connector lines coming from the shape.
But that's wrong.

>> No.11240412

>>11240320
Actually true

>> No.11240421
File: 119 KB, 583x482, 1548810236506.png [View same] [iqdb] [saucenao] [google]
11240421

>another IQ thread

>> No.11240432

>>11240421
High IQ post.

>> No.11240536

>>11240052
The answer is 5. There are 2 semi-circles, 1 triangle and 1 circle and the lines that connect them run along sides for the semi-circles/triangles and forms an orthogonal angle with the face of the circle.

>> No.11240541

>>11240052
Is this loss?