Brainlet test

[Anonymous No.11012797]

Describe the area of the red square in terms of a single variable. (The area is not considered a variable)

[Anonymous No.11012804]

>>11012797
L^2

[Anonymous No.11012811]

>>11012797
X^2
(x being the length of the red square)

[Anonymous No.11012812]

Is this a quarter circle? Is that described by (x-1)^2 + (y-1)^2 =1?
Not enough information given.

[Anonymous No.11012818]

>>11012804
>>11012811
It seems I've been BTFO. Okay, describe the area of the red square in proportion to the whole thing. Yes, its a quarter circle, are you blind?

[Anonymous No.11012819]

[eqn]A=\frac{R^2(\sqrt{2}-1)^2}{2}[/eqn]
Where R is the radius of curvature

[Anonymous No.11012821]

(R*(sqrt(2)-1))^2 / 2

[Anonymous No.11012823]

[eqn]A=\frac{R^2(\sqrt{2}-1)^2}{2}[\eqn]
Where R is radius of curvature

[Anonymous No.11012825]

fucking latex

[Anonymous No.11012827]

>>11012812
Shut up retard

[Anonymous No.11012828]

>>11012818
a unit circle?

[Anonymous No.11012829]

>>11012828
shouldn't matter. All a unit circle is is a circle with radius 1

[Anonymous No.11012834]

(R*(sqrt(2)-1)/sqrt(2))^2
R is the radius of the circle.

[Anonymous No.11012835]

>>11012828
No

[Anonymous No.11012837]

Entire image has dimension R (radius of circle)
Image diagonal is sqrt(2R^2)=sqrt(2)R
Area diagonal is sqrt(2)R-R=(sqrt(2)-1)R
Area dimension is (sqrt(2)-1)R/sqrt(2)
Area is (sqrt(2)-1)^2R^2/2.

[Anonymous No.11012862]

((r(sqrt(2)-1))/sqrt(2))^2 = Area of the red circle.

[Anonymous No.11012908]

Can some frens give me links to fun geometry problems like this?

[Anonymous No.11013568]

r^2*(3-2sqrt(2))/2, where r is the area of the circle.

[Anonymous No.11013748]

>>11012797
>>11012908
What’s the point of this? When would this ever be practically used?

[Anonymous No.11013753]

It's a square, dumbasses

[Anonymous No.11013785]

the red square which is the space in between the circle and the two tangent lines has the length of the radius minus the hypotenuse of the 45 degree right triangle.

[Anonymous No.11013789]

>>11013785
here is a sketch to explain the answer

[Anonymous No.11013803]

>>11012823
Posting pictures of zoophile sodomy won't change that nowhere it was implied that the curve is a perfect circle.

[Anonymous No.11014929]

>>11013803
>sodomy
How would you know~? Perv

[Anonymous No.11015323]

>>11014929
This slightly turned me on

[Anonymous No.11015504]

>>11012797
A, where the variable A repesents the area of the red square

[Anonymous No.11015538]

Got the same as everybody else here, except >>11013568 I guess.

[Anonymous No.11015552]

>>11012797
sneed

[Anonymous No.11015593]

>>11015552
Not a meme. Never gonna be a meme.

[Anonymous No.11015704]

>>11015552
What does it mean?

[Anonymous No.11015714]

>>11015323
What? Me knowing what a perv u are?

[Anonymous No.11016314]

>>11015552
Chuck

[Anonymous No.11017045]

>>11012797

[Anonymous No.11017076]

>>11012797
((r*sqrt(2)-r)/sqrt(2))^2

[Anonymous No.11017182]

>>11012811
unironically the best answer

[Anonymous No.11017333]

>>11012797
Consider a curve y = f(x). We are interested in knowing how big the square under the curve is, presupposing that the square is contained on its left by x = a and both sides must be equal in size. The diagonal of the square has to touch the curve, it shall not cut it.
Eq 1 -> y = x-a, Eq 2 -> y = f(x)
Obviously x-a = f(x).
Suppose now a = -1 and f(x) = (1-x^2)^0.5.
We get from Eq1 and Eq 2 -> x+1 = (1-x^2)^0.5 or -(1-x^2)^0.5+x+1 = 0. Now, I don't care about solving it but it's obvious that it contains two roots because doubling it results in a polynome of the form ax^2+bx^1.5+cx+dx^0.5+e = 0, which must have 4 different roots as becomes clear by substituting x = y^2. The roots of the equation -(1-x^2)^0.5+x+1 are in fact -1+(sqrt(2)-1)*cos(45°) and 1-(sqrt(2)-1)*cos(45°).
The point of this whole post is showing how any such problem can be reduced to polynomic equations whose roots and solutions are hardly non-trivial.

[Anonymous No.11017334]

>>11017333
meant to say hardly trivial.

[Anonymous No.11017338]

x*f(x)

[Anonymous No.11017388]

>>11014929
send the full image to me

[sad intj identityless No.11017500]

>>11013748
imagine being a sensor