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10982184 No.10982184 [Reply] [Original] [archived.moe]

Okay so this is bugging me
1 ÷ 3 = .333- (one third)
.333- × 3 = .999

3/3rds is less than one according to our math?

>> No.10982191

.999(infinite 9) = 1

>> No.10982219

Lmao, you should work on your bait quality

>> No.10982222

Metric bullcrap

>> No.10982227

Here you go senpai:
\sum_{k=1}^{\infty} 9(1/10)^k = \frac{0.9}{1-0.1}
\sum_{k=1}^{\infty} 9(1/10)^k = \frac{0.9}{0.9}
\sum_{k=1}^{\infty} 9(1/10)^k = 1
0.9+0.09+0.009+... = 1
\therefore 0.999... = 1

>> No.10982393

".99999..." and "1" are two notational representations of the same number under the standard construction of the reals

>> No.10982430

So you believe that If a number has nothing between it and another number then it's the same number? Seems like special pleading.

>> No.10982453 [DELETED] 

No. .999... is not one. If it were, line AZ and BZ would have the same slope, (paralel) yet somehow converge at Z.

>> No.10982455
File: 6 KB, 618x175, SlopeProof 999.png [View same] [iqdb] [saucenao] [google] [report]

No. .999... is not one. If it were, line AZ and BZ would have the same slope, (paralel) yet somehow converge at Z.

>> No.10982466 [DELETED] 

I reject your hypothesis

>> No.10982481

He's just telling it like it is.

>> No.10982486
File: 2 KB, 203x191, hypotenuse length.png [View same] [iqdb] [saucenao] [google] [report]

geometric proofs are notoriously weak when dealing with infinity:

distance =/= length

hypotenuse length, [math] n \rightarrow \infty [/math]

a+b or [math] \sqrt{a^{2}+b^{2}} [/math] ?

>> No.10982618
File: 48 KB, 350x494, Pi = 4 proof.png [View same] [iqdb] [saucenao] [google] [report]


That is kind of the same as this. They are good examples of why you can't assume that a process taken to infinity equals it's limit. A staircase with infinitely many steps of infinitely small size is not a line. A polygon with infinitely many right angles is not a circle. A number with infinitely many trailing nines is not the next digit up.

>> No.10982658

is this a wildburger thing? never saw someone try so hard at being wrong

>> No.10982695


Insults = I can't find anything wrong with your logic.

>> No.10982697

no i'm not trying to use an insult, "wildburger" is a reference to N J Wildberger, not an amerifat thing

>> No.10982725

As the decimal place approaches infinity the difference between .999999999 and 1 becomes so infinitesimally small that .9999999 = 1

>> No.10982754

.999... = 1

>> No.10982769

>They are good examples of why you can't assume that a process taken to infinity equals it's limit.
It is, you don't understand what a limit is.

>> No.10983056

>It is, you don't understand what a limit is.
> Doesn't bother to try to explain anything.

These discussions turn into religion really quickly. If a number with infinite digits is a valid construct, then why isn't a staircase with infinite steps?

>> No.10983123

>turn into religion really quickly. If
google it, wikipedia it - no-one here is your mommy

>> No.10983136

That's literally true, calling it "special pleading" doesn't mean anything.

>> No.10983141

You're just saying that if x-y=0 then x=y, which is trivially true.

>> No.10983142


So if there is nothing between A and B, then A and B are the same letter?

>> No.10983149

in R they are

>> No.10983161


>I'm right, you're wrong. Google it, because I'm too lazy to defend myself.

>> No.10983218

1/3 = 1/3
1/3 X 3 = 3/3 = 1
Decimals are fractions to the tenth power.
Everything I just typed is made up scribbles. This is why maths cant prove anything and is a great example. Could give a shit less about your "model" unless it provides more insights into a persuasive argument for a theory. But if the persuasive argument is squigglie math proofs fuck right off.

>> No.10983239

>then why isn't a staircase with infinite steps?
It does not converge to a line. All you have to do is look at the definition a limit.

>> No.10983246

> but muh .9's X infinity = 1

This is also retarded. 1 X infinity = Infinity
.9 X infinity means it can continue to be divided infinitely. Its a shitty system and maths is fucken gay

>> No.10983325

ur not worth it

>> No.10983329


>> No.10983338

This dude has been checking this thread for over an hour just to say, "google it" and "you're not worth it"


>> No.10983628

>what is a discrete space

>> No.10983630

Nah you're just dumb

>> No.10985149

I don't "believe" anything about the statement I made. It's a definite, provable fact about the standard construction of the reals and how that relates to our symbolic language for notating elements of the reals.

>> No.10985176

1/3 isn't equal to 0.333, 0.333 with the repeater symbol is an approximation of one third.
This is because you are in a reality where infinity is not defined, it's outside the dimension we inhabit.
So for example I can type 0.333..., or 0.333333333..., or with a million 3s, but I can't type infinite threes, so we use the symbol 1/3, or an approximation 0.333,
3 X 1/3 =1. 3 X 0.3333.. does not equal 1.

>> No.10985190

>infinity is not defined
wew lad
An unbounded quantity that is greater than every real number.

>> No.10985191

1/3 = 3/10 + 1/30
= 0.3 + 1/30
= 0.33 + 1/300
= 0.333 + 1/3000
= 0.3... + 1/inf
= 0.3... + 0
= 0.3...

>> No.10985202

I don't mean it lacks a definition in the English language, I mean that you can't actually write an infinite number, you can only approximate, if you know what I mean,
This is confusing because we are taking approximations, running them through an equation, getting an answer that is intuitively incorrect.
It's just mixing up real world and vectored maths.

>> No.10985210

>if you know what I mean,
not even a clue

>> No.10986319

tell me when you reach that last digit

>> No.10986335

1/∞ ≠ 0

infinity is not a number, is a concept

>> No.10986453

how is this invalid?

>> No.10986459

1/3 is not .333 that is just an approximation, you can't represent 1/3 as a decimal but .333 repeating forever is the closest value because .334 is too big and .333 is slightly too small so when they show a repeating bar it is because .333 is not actually one-third but it is the closest you can get with decimal in base 10.

>> No.10986462

because the infinite block has infinitely many deviations from the circular form.

>> No.10986463


>> No.10986484

read a book

>> No.10986489

>hurr infinite exists exist, just accept it
very enlightening

>> No.10986495

sure bud

>> No.10986502

>exists exist
the best kind of exist

>> No.10986506

>appeal to authority with no reasoning

>> No.10986516

shitposter vs W|A, easy choice

>> No.10986524

>I believe it but I can’t tell you why

>> No.10986529

shitposter vs W|A, easy choice

>> No.10986532
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>> No.10986549

.333 infinite times would have no value because infinity is not a number so an infinite number of 3s is also not a number

>> No.10986554

>infinity is not a number
so what

>> No.10986564

so .333 (infinite) cannot be a number either.

>> No.10986567

>infinity is totally not a number you guys!
>”but what is it?”
>a quantity...

>> No.10986572

yes, but the limit of the sequence .3, .33, .333, .3333,... surely can be defined as a number and that number is equivalent to 1/3

>> No.10986586

in other words, 0.333... is limited by 1/3, and will never actually equal 1/3

>> No.10986592

So .333... does not equal 1/3 and thus is not equivalent ?

>> No.10986595

how exactly?

>> No.10986598

0.333... is a meaningless expression. You’re assuming that something infinite exists. 0.333... should not be viewed as a number but it shows that as you repeat the process, 0.333... approaches 1/3. There’s no justification for treating it as a number though. Even if you did, it still can’t equal 1/3, because there is always a remainder.
0.33 is just as unequal as 0.333...
There is always a gap between them

>> No.10986622

.3333.... IS grade school shorthand for "the limit of the sequence .3, .33, .333, .3333, ...". idk what the expression would mean otherwise. so, yes, .333.... is equivalent to 1/3

>> No.10986633

this is not a good way to think about decimal representations. if you are going to think about decimals-as-real-numbers, you should think about all real numbers as equivalence classes of sequences.

the sequence implicitly represented by .3333.... is no less different from 1/3 as .999.... is in the equivalence class representing 1, or 1.99... is in the equivalence class representing 2.

>> No.10986652

Anon it’s simple.

10S =9.999...
-S =0.999...
9S= 9

>> No.10986662

>0.999... is a number
>you can multiply and add it
Yeah I’m gonna need a justification for your extension of arithmetical operations to infinite sums

>> No.10986681


literally done in any calc 1 class. changing the above argument from functions to sequences is trivial.

>> No.10986686

>10S = 9.999...
Where is the ending 0?

>> No.10986689

Finally someone who isn’t an idiot on this sub. Technically all numbers in decimal notation are infinitely long;
4 is really 4.0000...
You can also take the algebra a step further:
Since 1=0.999...
-0.999= -1
Therefore all infinitesimals are equal to 0, since:
0.000...1*X = 0*X
except at x= infinity

>> No.10986705

Are you fucking stupid.
It’s non terminating

>> No.10986727

Then how do you justify multiplying it? Where is the rule that says we can multiply an infinite sum? I certainly cannot prove such a thing empirically or even intuitively. You’re pulling these rules out of nowhere. That’s not how mathematics works

>> No.10986747

Anon, every mathematician in the world disagrees with you.
Why do we allow people who haven't even done Calc to make math threads.

>> No.10986752

And yet you yourself cannot give a justification. You’re blindly believing “every mathematician in the world” and it’s embarrassing. If you judged mathematics by majority and authority, then at one point, you would have detested infinity and infinitesimals

>> No.10986758

>You’re pulling these rules out of nowhere. That’s not how mathematics works
Except that's exactly how mathematics works. It's the study of games we play on abstract structures.

>> No.10986769

Yes anon, you, who clearly have no mathematical training whatsoever, are in the right here. A breakthrough thinker, no one has ever questioned this before and you are going to change the field of mathematics with this.

>> No.10986787

Do you also reject multiplying pi by 2?

>> No.10986790

oh ok

>> No.10987133

>Where is the rule that says we can
Where is the rule that says we can't

>> No.10988357


>> No.10988381

Yes, that's literally how you prove uniqueness

>> No.10988448

1/3 is not strictly equal to 0.333...
instead, it cannot be strictly equal in decimal notation. We're taught that anything can be rendered in decimal, but for some things it's not really accurate and is simply more of a cheat.

unfortunately the cheat also works towards convincing some people that 0.999... = 1, even though this is not essentially the case. This has to do with seemingly-infinite repetition. In the case of rendering 1/3 as 0.333... using the cheat, it makes enough sense that this specific rendering of 0.333... approximating 1/3 specifically, times 3, would produce 0.999..., and that 1/3 *3 = 1.
however, this does not hold true for something like
[math]\sum_{n}^{\infty}\frac{1}{2^n}[/math] which intends to strictly produce a 0.999... result. This calculus however "uses" "infinity", which rationally isn't actual infinity but is instead seemingly infinite.

to quickly define the difference between infinite and seemingly-infinite, both are technically shortened from their results and there is an unimaginable degree of accuracy should one continue with calculation, so "seemingly-infinite" is more like a realnumber (infinity-1). There is no countable proof for either infinity or seemingly-infinite, so in the same regard there is no strong evidence an (infinity-1) cannot exist as a real number too long to intelligently do any math with, which would give it the same relevant property as straight-up "infinity" does. In all, anything that is described as infinite is more likely than not simply seemingly-infinite.

>> No.10988458

This seemingly-infinite term is necessary for describing the 0.999... number produced by the above sum algorithm, because it is strictly provable to not be the same 0.999... number rendered from 0.333...*3 where we got the 0.333... from 1/3 specifically. Any partial sum step of [math]n[/math] within the sum will produce a string of 9's followed by a string of various digits. The infinity-hopefuls contest that those trailing digits would simply vanish under the condition that actual infinity had been reached from numerating [math]n\rightarrow\infty[/math], but since there is no way to actually do this, this vanishing cheat isn't real either. The true result of this sum is a seemingly-infinite string of 9's, followed by a seemingly-infinite string of various digits, which is different from the 0.333...*3 = 0.999... number which is solely just a seemingly-infinite string of 9's.

a lot of mental cheating occurs when rendering repeating numbers in higher maths, and for this example we end up shortening what seems to be infinitely repeating patterns down to just 3 digits followed by an ellipses rendered as [math]0.999...[/math]

>> No.10988513

1 = \dfrac{3}{3} = 3 \cdot \dfrac{1}{3} = 3 \cdot 0.\bar{3} = 0.\bar{9}

>> No.10988535
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>> No.10988601

[math] \displaystyle
\boxed{0 < p < 1} \\
p^n-1 = (p-1)(p^{n-1}+p^{n-2}+ \dots +p+1) \\
\dfrac{p^n-1}{p-1} = \sum \limits_{j=0}^{n-1}p^j \\
\lim_{n \to \infty} \dfrac{p^n-1}{p-1} = \lim_{n \to \infty} \sum \limits_{j=0}^{n-1}p^j \\
\dfrac{0-1}{p-1} = \sum \limits_{j=0}^{\infty}p^j \implies \dfrac{1}{1-p} = \sum \limits_{j=0}^{\infty}p^j

>> No.10988705

A simple explanation is that infinity does not exist so you'll never have an actual circle.

>> No.10988714

Perfect troll explanation.

>> No.10988737
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Thanks for quoting everyone in the thread. That was very helpful and not annoying at all.

>> No.10988748

i hope there was a point to this post

>> No.10990466

there is

>> No.10990727

This is just a quirk of notation. 0.999... = 1. This is because what we mean by 0.999... is just the limit of 0.9 + 0.09 + 0.009 +...; and this limit is 1. This is trivial to see if you actually think of the definition of a limit for a series: The limit of a series a_i is c if for every epsilon > 0, there exists an N > 0, such that for all natural n >= N, the distance between a_n and c is smaller than epsilon. Or in short: The limit of a series is c if the series gets within any arbitrary distance of c eventually, which is obviously true for 0.999... and 1.

The reason it seems so illogical is that there seems to be some kind of room between 0.999... and 1; for any amount of nines there's still space between it and 1, so if you add nines forever, it will just get closer and never really there right? But there is no such thing as 'adding nines' as if it is some kind of temporal process. Thinking about it in these terms is already based on a misinterpretation of what 0.999... means.

>> No.10990738

>p^n = 0
prove it

>> No.10990777

Are you stupid?
0.999...=\=1 threads have been going strong for years...

>> No.10990785

>You’re pulling these rules out of nowhere. That’s not how mathematics works
It LITERALLY is as any book on the foundations on mathematics will tell you.

>> No.10990823


>> No.10990847


Wonder what the theological\metaphysical implication of the perfectly equal division of the one by the three not adding back to the one perfectly over an infinite series is. It's almost as if IsRaEl is somehow more than the sum of its parts somehow... Likely this is more due to the imprecise nature of finite math, but still an interesting thought.

>> No.10990850


>> No.10990855

x = 0.999...
10x = 9.999...

10x - x = 9.999... - 0.999...
9x = 9
x = 1

0.999... = 1

>> No.10990862

1/9 = 0.111...
8/9 = 0.888...
9/9 = 0.999...

>> No.10991492
File: 402 KB, 211x199, what the fuck.gif [View same] [iqdb] [saucenao] [google] [report]

oh please continue, don't pay any attention to the fact that there are other people in the room.

>> No.10991504

>10x = 9.999...
Where is the ending 0?
>n = inf
Still haven’t proven that n^inf is possible, let alone equal to 0

>> No.10991539
File: 112 KB, 953x613, 0.999 = 1.jpg [View same] [iqdb] [saucenao] [google] [report]

>> No.10991680

Why not live a carefree life in base 3?

>> No.10992148

The thought just occured to me, Why would someone accept that 1/3 = 0.333... but not accept that 0.999... = 1.0 ?

>> No.10992151

Because 1/3 isn’t equal to 0.333...

>> No.10992172

>Why not live a carefree life in base 3?
I heard there's niggers in it

>> No.10992195

Perhaps I sould be more specific. In the first post of this thread, Anon said he was "bugged" by the apparent paradox he posted. In that post, he accepted that 1/3=0.333... but did not acceept that 0.999...=1. That seems like cognitive dissonance, and something that should be pointed out, whether you believe in infintiy or not.

>> No.10992207

With 0.999... we don’t see the “1” out front, so we might think they’re unequal. With 0.333... there doesn’t have to be a 1 there. We just assume it’s equal to 1/3. However, if we look at the fraction representations:
3/10, 33/100, 333/1000/ 3333/10000 etc.
we see how there’s always a remainder of 1. No matter how long the fraction is, there will always be a remainder. And just saying “go to infinity” doesn’t really justify how the remainder goes away.

>> No.10992214


This is clearly not equal to 1/3

>> No.10992217



>> No.10992249 [DELETED] 
File: 988 KB, 599x600, 3D pepe.png [View same] [iqdb] [saucenao] [google] [report]

[math]\frac{1}{3} > \sum_{n=1}^{\infty}\frac{1}{3^n}[/math]

>> No.10992253 [DELETED] 
File: 7 KB, 250x241, 1406248015414s.jpg [View same] [iqdb] [saucenao] [google] [report]

[eqn]\frac{1}{3} > \sum_{n=1}^{\infty} \frac{1}{3^n}[/eqn]

>> No.10992586

\boxed{0 < p < 1} \\
1 = p + (1-p) ~~~~~~ \overset{1}{ \overbrace{[=====p=====|==(1-p)==]}} \\
\text{divide p using x} ~~~~~~ \overset{1}{ \overbrace{ \underset{p}{[ \underbrace{=====x=====|==(p-x)==}]} ~~ + ~~ (1-p)}} \\
\text{solve x and (p-x), when length ratios must be the same} \\
\dfrac{x}{p-x}= \dfrac{p}{1-p} \Rightarrow x- xp = p^2 - xp \Rightarrow \underline{x=p^2} \Rightarrow \underline{(p-x)=p(1-p)} \\
\overset{1}{ \overbrace{ \underset{p}{[ \underbrace{=====p^2=====|==p(1-p)==}]} ~~ + ~~ (1-p)}} \\
\overset{1}{ \overbrace{ \underset{p^2}{[ \underbrace{=====p^3=====|==p^2(1-p)==}]} ~~+ p(1-p)+(1-p)}} \\
\overset{1}{ \overbrace{ \underset{p^3}{[ \underbrace{=====p^4=====|==p^3(1-p)==}]} ~~+ p^2(1-p)+p(1-p)+(1-p)}} \\
(1-p)+p(1-p)+p^2(1-p)+p^3(1-p)+ \cdots =1 ~~~~ \left | ~ \times \frac{1}{1-p} \right . \\
1+p+p^2+p^3+ \cdots = \dfrac{1}{1-p}

>> No.10992594


>> No.10992604

You can’t justify the disappearance of the p^n term. Bullshit bullshit bullshit

>> No.10992616 [DELETED] 


>> No.10992623


>> No.10992632

In the second to last line, the last term should be p^n, but instead there is (...). The last term gets smaller, but you haven’t proven that it becomes 0. The sum becomes arbitrarily close to 1, but it never equals 1.

>> No.10992664


>> No.10992671

Wait a minute with that brown example,
Like for real time out.

If you had 1 litre of water, so 1000 grams of water, and you pour it into 3 containers, you don't have 333.333... grams in each container, you have a precise weight in each container.
This analogy is rediculous, it's the same as saying 9=10,
You can't round up physical values.
If you buy a gram of coke, and the dealer taps it onto the scale until it's 0.9999999 grams, that isn't 1 gram.

This whole debate rages because of a misunderstanding between vectored maths and real world maths,
These symbols you are looking at are approximations done by humans in order to measure our world better, you cannot have an infinitely repeating number measured in the real world anymore than you can give a value in kilometres for how far away infinity is.

>> No.10992672

Any non-zero number p multiplied by itself will not be equal to zero. So no matter what n value, p^n will never equal zero. It’s pure bullshit and you eat it up

>> No.10992682

Theme of the thread:

>> No.10992693

what if i told you
>1/3 is NOT .333 ad infinitum

>> No.10992712


>> No.10992752


>> No.10992760

and with that, you concede a lack of understanding. This discussion can go no further as you fail to defend your methods and have no chance of providing any reasons whatsoever for your sleight of hand trucks you call mathematics.

>> No.10992764

the bus stop masturbator has spoken

>> No.10992876

just convert your bases to something other than decimal. "0.333..." in decimal can be represented as 0.4 in duodecimal, which fits into 12 three times quite nicely.

>> No.10992880

*which fits into 1(base 12), my bad

>> No.10993904


>> No.10994024

some numbers shouldn't be rendered in decimal and should just be left as fractions, simple enough.

[math]1 \div 3 = \frac{1}{3} [/math]

>> No.10994045
File: 33 KB, 801x626, computer smarts.png [View same] [iqdb] [saucenao] [google] [report]


>> No.10994098


>> No.10994107

let's pretend finite is infinite

>> No.10994112

1/3 = 0.1_3

>> No.10994119

>mass quoting
use an approximation next time

>> No.10994120

this should be undefined given inf/inf is undefined.

>> No.10994162

sure bud

>> No.10994177

glad you two agree now

>> No.10994199
File: 36 KB, 797x638, computer smarts.png [View same] [iqdb] [saucenao] [google] [report]

idk if you're being stupid or not but wolfram thinks 0.1 followed by 56 more 1's is the literal 1/9. wolfram is incredibly retarded.

>> No.10994393

ok bubba

>> No.10994560
File: 30 KB, 842x527, WOLFRAM NO.png [View same] [iqdb] [saucenao] [google] [report]


>> No.10994581

The limit of 9 times 1/10^n+1 as n approaches infinity is 1.

>> No.10994589

You're taking a limit. 0.333... is an accident of notation.

>> No.10994595


infinity isn't a number btw.

>> No.10994598

You need Jesus and to learn what a limit is.

>> No.10994600


>> No.10994604
File: 218 KB, 500x340, 1564681657669.png [View same] [iqdb] [saucenao] [google] [report]

limit is only a viable concept when using it with a number and not a retarded object like infinity, which by very definition is limitLESS.

>the limit is unlimited
please use your thinker.

>> No.10994605

Staircases don't have an infinite number of infinitely small steps in a finite distance. Any staircase that did would be a ramp.

>> No.10994608

1/3 is 1/3. Once and forever, periodic nums are bullshit use fractional otherwise we'll get noticable unwanted effects on varius calculations.

>> No.10994614

Writing infinity as a number is shorthand for taking a limit, just like 0.999...

Really not sure why anyone who doesn't at least understand the concept of a limit is on this board. You know this is a math and science board right?

>> No.10994625

It's basically true in real life. Macroscopic objects aren't made of infinitesimal parts. There are no perfect circles, just arbitrarily approximate ones up to a point.

>> No.10994651

heres some hot new math i just came up with

[math]\frac{1}{3} = 0.\overline{333}:A[/math]

what does ":A" mean? It's a hexidecimal numeric identifier, used to determine how the number should be read.
>:A= this number is repeating without significant deviation. Direction: Hold 1 more digit than is displayed, and round. [math]0.333:A \rightarrow 0.333[3][/math] 0.333[3] = 0.333; 0.333[3]*2 = 0.666[6] = 0.667; 0.333[3]*3 = 0.999[9] = 1.0
>:B = this number is seemingly repeating but contains significant deviation [eqn]\sum_{n=1}^{\infty} \frac{1}{2^n} = 0.\overline{999}:B [/eqn].
>:C =
>:D =
>:E =
>:F =

>>[math]0.\overline{999}:A \neq 0.\overline{999}:B[/math]
FEEL free to fill these in.

>> No.10994699

The entire concept of limits is that some infinities are limited. Like a curve on a plane, which, regardless of length, is made of infinite points. If you can't understand this, you will never be able to do any math or science.

>> No.10994729

nothing is made of infinite anything and you're a daydreaming mong living in fantasy land.

>> No.10994735

I fucking hate decimals

>> No.10994751

Maybe the true math was the infinite friends we made along the integral.

>> No.10994941

Math can only approximate physical reality and vice versa, you absolutely retard. The point is that you can approximate at any arbitrary scale. This is shit someone with an IQ of 90 should be able to understand.

>> No.10995499

\displaystyle \sum_{n=1}^{\infty}\frac{9}{10^n} = \frac{9}{10} + \frac{9}{100} +\frac{9}{1000} + ...
= b = \frac{1}{10}(9 + \frac{9}{10} + \frac{9}{100} +...)
= \frac{1}{10}(9+b) = b \\
\frac{1}{10}(9+b) = b \\
\frac{9}{10} = \frac{9}{10}b \\
1 = b

>> No.10995528

it only takes 62 digits to accommodate the scale of the UNIVERSE in meters with planck length accuracy. How's that for arbitrary you dumb nigger.

>> No.10995655

>62 digits
peanuts compared to the amount of ways you can arrange 6.022x10^23 molecules

>> No.10995774

meme number.

>> No.10995858

less than 20g of water

>> No.10997184


>> No.10997380

>b = 1/10b

>> No.10997680

>i have no argument

>> No.10997701

>9/10 + 9/100 + 9/1000... = b
>b = 1/10(9 + 9/10 + 9/1000...)
>b = 1/10(b)
>b = 0

>> No.10997703


>> No.10998493
File: 122 KB, 900x900, prophet.jpg [View same] [iqdb] [saucenao] [google] [report]


>> No.10999140

based basebro

>> No.10999142

.333 repeating is exactly 1/3 you dumb nigger

>> No.10999160

>Where is the rule that says we can multiply an infinite sum?
If you want to multiply an infinite sum by a single number, it's easy, you just multiply every summand by that number. It's called the distributive law.

>> No.10999193


>> No.10999388

>>b = 1/10(b)
hurr durr
it's b = 1/10(9+b)

>> No.10999904

No, it is not. It is conceptual approximation.

>> No.10999915

.333...=1/3 is an approximation retard!

>> No.10999918

Wrong. .999... is not a real. It is a hyperreal. And it is sure as hell not equal to 1.

>> No.10999920

So let me guess, a parabola touches its asymptotes?

>> No.11000310

The absolute state of /sci/

>> No.11001098


>> No.11001107
File: 28 KB, 488x463, retardClap.png [View same] [iqdb] [saucenao] [google] [report]


>> No.11001932

Thanks for this shit post. Kinda new to this board, this post made it very clear that everyone here is retarded. This place is an incredibly inefficient way to learn or discuss anything

>> No.11001950

This is the answer.
1 div by 3 =! .333
1 div 3 = 1/3, a ratio.
Nothing breaks
Limits and aproctchomations are not needed

>> No.11003165
File: 161 KB, 432x432, 1569267671600.png [View same] [iqdb] [saucenao] [google] [report]

>This place is an incredibly inefficient way to learn or discuss anything
That's here. That's home. That's us.

>> No.11004962


>> No.11006945

bump lmao

>> No.11007941

True for the most part, there are a couple smart people that post here though.

>> No.11009451
File: 4 KB, 150x150, 1621709_10203787937878020_248716194_n.jpg [View same] [iqdb] [saucenao] [google] [report]

resurrected from page 10

>> No.11009488

Bridging fractions and decimals was never meant to happen. Dont do this. They arent compatible

>> No.11009497

Depends what you're trying to learn. Two days ago I learned how to defend my property using a neural net and through botany.

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