Will the scale tip left or right?

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Anonymous Sun Jun 23 18:47:11 2019 No.10749531 [Reply] [Original]

Will the scale tip left or right?

>>	Anonymous Sun Jun 23 18:49:55 2019 No.10749539 Right obviously

>>	Anonymous Sun Jun 23 18:50:23 2019 No.10749541 Right

>>	Anonymous Sun Jun 23 18:50:50 2019 No.10749543 Won't tip.

>>	Anonymous Sun Jun 23 18:52:39 2019 No.10749548 >>10749531 left

>>	Anonymous Sun Jun 23 18:53:14 2019 No.10749551 Literally just test it in real life.

>>	Anonymous Sun Jun 23 18:57:40 2019 No.10749570 >>10749551 Too many sources of error. And either way, you'd need to still understand why it tipped.

>>	Anonymous Sun Jun 23 19:02:08 2019 No.10749590 >>10749543 This. Left is basically pulling oneself out of a swamp by one's own hair. Right is the opposite.

>>	Anonymous Sun Jun 23 19:03:57 2019 No.10749599 >>10749539 Why?

Anonymous Sun Jun 23 19:05:57 2019 No.10749608

>>10749531
Left. The cord is sustaining the steel ball weight so doesn't count. That space displaced by it counts 0 to the net weight of the right side. As opossed to the right side, the ping pong ball weight is supported by the scale. As there is the same amount of water in either side, the scale will tip left.

>>	Anonymous Sun Jun 23 19:17:14 2019 No.10749662 >>10749608 Bouyancy is a thing you know.

>>	Anonymous Sun Jun 23 19:20:16 2019 No.10749673 >>10749531 I'm ending this thread. https://www.youtube.com/watch?v=QD3hbVG1yxM

Anonymous Sun Jun 23 19:38:25 2019 No.10749733
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>>10749531
weight one= water+pingpong weight
weight 2= water + buoyancy force of sphere

Since in the second flask the metallic sphere is not moving, we can assume it's forces are at equilibrium meanign that
Force from steel weight= buoyancy force + pull from string
That means that the buoyancy force from the steel sphere is canceled out from the weight of the steel ball and from newton's first law since every action has an equal and opposite reaction the reactionary buoyancy force on the steel ball is still acting on the flask pushing it down. This is in contrast to the first flask where the buoyancy forces are all canceled out.

Since Ping Pong balls float, assuming that booth balls have the same volume, that means that the reactionary buoyancy force on the second flask is greater than the weight on from the ping pong ball in the first flask.

Which means that the second flask should tip down.

I dunno wheter I'm right or not, please correct.

>>	Anonymous Sun Jun 23 19:42:28 2019 No.10749747 File: 60 KB, 1247x617, 1561330031951.jpg [View same] [iqdb] [saucenao] [google] >>10749531 wow the brainlet is strong with this one

>>	Anonymous Sun Jun 23 19:44:12 2019 No.10749753 >>10749673 >needing a video to understand basic physics

>>	Anonymous Sun Jun 23 19:44:31 2019 No.10749754 >>10749531 even he knows it. wich something like google existed.... https://www.youtube.com/watch?v=QD3hbVG1yxM

>>	Anonymous Sun Jun 23 19:45:09 2019 No.10749758 won't it depend on the density of the fluid? there's a cut off density after which it will start tipping to the right

>>	Anonymous Sun Jun 23 19:45:32 2019 No.10749761 >>10749754 wrong vid https://www.youtube.com/watch?v=QD3hbVG1yxM

>>	Anonymous Sun Jun 23 19:47:11 2019 No.10749769 >>10749758 no if it is the same in both sides and both spheres are the same volume. but this is implied see actually p=totalvolume-spherevolumeliquiddensity9,8m/ss >>10749747

>>	Anonymous Sun Jun 23 19:50:03 2019 No.10749782 >>10749754 >>10749754 wrong vid https://www.youtube.com/watch?v=IJ6GfBOYeLc

>>	Anonymous Sun Jun 23 19:51:52 2019 No.10749790 >>10749733 i want to rape a nonwhite

>>	Anonymous Sun Jun 23 19:58:37 2019 No.10749808 >>10749662 Is this trolling?

>>	Anonymous Sun Jun 23 20:19:56 2019 No.10749863 >>10749531 how is some cunt allowed to pose the question like that? it won't tip. Do not think it's acceptable to structure the question to preclude the answer as some fucking attempt to be cute

>>	Anonymous Sun Jun 23 20:27:39 2019 No.10749879 >>10749758 >there's a cut off density after which it will start tipping to the right Yes and the way you know that's happening is that the ping-pong ball stops floating.

>>	Anonymous Sun Jun 23 21:50:24 2019 No.10750070 >>10749808 It's proper physics.

>>	Anonymous Sun Jun 23 21:52:54 2019 No.10750078 >>10749531 there was a stackoverflow about this, i think left goes up. just google it. confusing questions often have a google answer

>>	Anonymous Sun Jun 23 22:00:00 2019 No.10750094 >>10749531 It will tip to the left. On the right, the weight isn't attacked to the scales. On the left, the extra mass of the ping pong ball will tip it over.

Anonymous Sun Jun 23 22:07:48 2019 No.10750120

>>10750094
Wrong. On the left, the force from the water providing buoyancy presses down on the scale plate, and the tension reaction force pulls up on it; they both cancel, ignoring the ping pong ball's small mass. On the right, the buoyancy-downforce means the downforce is pressing down on the scale plate.

>>	Anonymous Sun Jun 23 22:08:03 2019 No.10750121 >>10749733 You are not correct. The weight in the right flask is supported by the other stand, it won't contribute to the system. On the left, the extra weight of the ping pong ball will weigh it down.

>>	Anonymous Sun Jun 23 22:10:09 2019 No.10750129 >>10750121 >supported by the other stand The buoyancy force applies first, and then the tension in the string cancels out the rest of the weight force of the steel ball.

Anonymous Sun Jun 23 23:26:04 2019 No.10750274

>>10750121
On the left, the buoyant action-reaction pair results in no net force due to the string connection.
On the right, the buoyant action-reaction pair results in a net force up on the ball and down on the vessel, equal to the weight of displaced water, which is greater than the weight of the hollow ping pong ball.

>>	Anonymous Sun Jun 23 23:31:20 2019 No.10750282 Does the pingpong ball pull upwards on the?

>>	Anonymous Mon Jun 24 02:09:31 2019 No.10750523 >>10749808 Buoyancy still has a small but real effect on it

>>	Anonymous Mon Jun 24 02:18:39 2019 No.10750540 It tips right because the string goes limp and the water takes on the weight of the steel ball or whatever

>>	Anonymous Mon Jun 24 02:30:00 2019 No.10750561 Literally understand what a closed system is and you can solve this with ease

>>	Anonymous Mon Jun 24 02:44:48 2019 No.10750573 >>10750282 Yes and the right steel ball adds no weight

Anonymous Mon Jun 24 02:49:29 2019 No.10750585

>>10749531
Tricky question, but the key is in two things: force balancing, and the difference between internal and external forces.

For the cup on the left, picture glueing one end of a piece of string to a ping pong ball, and the other end to the base of the inside of a cup. Fill the cup with water and the ping pong ball will bob upwards due to buoyancy. Now picture cutting the string so the ball floats to the top. Although the internal forces on the ball, string and water would change, the total mass of the system, and hence its weight, will remain constant. It’s the same principle as sitting on a chair and pulling upward on it. No matter how strongly you pull, it would show the same reading on a scale before and after you started pulling due to the masses being the same.

For the cup on the right, the same principles apply. The submerged ball is suspended by an external arm, so it is part of an external system; ie. it does not exert a force of gravity on the right side due to it already being part of a separate, statically balanced system. All the ball on the right does is displace the water to the same position as in the cup on the left.

Summing forces on either side,
Left cup: (mass of cup + mass of ball + mass of string + mass of water) x g = force of left cup on system
Right cup: (mass of cup + mass of water) x g = force of right cup on the system

So, if the water + cup masses are equal on both sides, the left cup exerts a higher gravitational force on the scale than the right one does (due to the mass of the ball + string). So, the scale would tip left.

>>	Anonymous Mon Jun 24 02:51:46 2019 No.10750588 >>10750561 explain plz

Anonymous Mon Jun 24 03:03:58 2019 No.10750613

>>10750585
Wrong. The buoyancy force applies to the steel ball before the tension force from the string does. The tension force in the string is the difference of the steel ball's weight and the buoyancy force, based on the fluid density and the ball's volume.

Imagine replacing the steel ball with a ping pong ball. It would float to the top due to the buoyancy force overcoming its weight, regardless of the string. So the buoyancy force is acting on the steel ball. By Newton's third law, there is a downward force acting on the fluid mass in response to the buoyancy force, and again using the third law, there is a force acting downward on the scale and a normal force acting upward on the fluid mass, all ultimately due to the buoyancy of the steel ball. The downward force on the scale tips it right.

>>	Anonymous Mon Jun 24 03:18:51 2019 No.10750655 >>10749531 But it's clearly suspended in equilibrium.. Where the fuck did you get the idea that it will move without a change in state?

Anonymous Mon Jun 24 03:30:59 2019 No.10750678

>>10750613
Trouble is that although the ping pong ball suspended in the same manner would float to the top, the string will balance the force of the steel ball’s weight since it’s in tension.

Buoyancy is the force exerted by a fluid opposing the weight of a submerged object acting on it - in this case, the steel ball’s weight does not act on the fluid at all, since it is entirely taken up as a tensile force in the string.

>>	Anonymous Mon Jun 24 03:36:53 2019 No.10750687 >>10750655 Disregard. I suck cocks, Image states sting is used. Thus wicking effect will cause the steel side to lose water at a more rapid rate.

Anonymous Mon Jun 24 03:48:08 2019 No.10750700

>>10750678
The weight vector is not equally balanced by the tension force. The buoyancy force always acts when an object is submerged. The steel ball is submerged, so the buoyancy force is acting on it. If the steel ball were a ping pong ball, the tension force would be zero, and the same buoyancy force would be acting on it. In general, tension force is T = W - B where W is weight and B is buoyancy (magnitudes only).

Anonymous Mon Jun 24 04:59:55 2019 No.10750831

>>10750588
Well consider the righr scale, there is a beaker on top of it, it is currently stable so the net force on it is 0. Those forces are gravity P, buoyant force Fb ( equal to the weight of the water displaced by the ball) and the counter force N. So we can see that P + Fb - N=0 right? According to Newton's third law the force acted on the scale itself is equal to N. The closed system here is the beaker and the water inside.

Looking at the left scale we also have another beaker, with equal amont of water so equal gravity (P), same buoyant force acting on it (cuz same volume of displaced water), but there is some thing different. Take a look at the string connecting the ball and the beaker, it is pulling the ball down and pulling the beaker upward, so there is an additional force T exerting upward. Ofc there is the counteracting force N' exerted by the scale. So we have: P+Fn-T-N'=0

Same P, same Fb but the force on the left scale is lighter than the force on the right scale by T, hence the scales tip to the right.

>>	Anonymous Mon Jun 24 05:20:00 2019 No.10750859 >>10749543 /thread

Jinx Mon Jun 24 05:46:24 2019 No.10750893

>>10749531 Left.
The amount of liquid is same in both(assuming same volume of ping pong and metal ball). On left,there is the extra mass of ping pong ball whereas on right, the metal ball is suspended, meaning the weight is countered by external force(string).If ping pong ball is of neglible weight,then it will remain as it is.

>>	Anonymous Mon Jun 24 06:12:02 2019 No.10750924 >>10749543 Based, 200 IQ

>>	Anonymous Mon Jun 24 06:52:07 2019 No.10750983 left has more mass so it will tilt left

>>	Anonymous Mon Jun 24 07:32:07 2019 No.10751046 >not considering the gravitational pull of the steel ball /sci/ is full of brainlets.

>>	Anonymous Mon Jun 24 09:24:54 2019 No.10751280 >>10750540 >Implying a steel ball will float on water

Anonymous Mon Jun 24 09:30:36 2019 No.10751306

>>10749548
this, asuming the mass of the fluids in either GS are identical. the MASS of the ping pong ball and string is supported by the left arm of the BALANCE wheras the MASS of the steel ball and its string is supported by an outside aperature, therefore there is greater MASS on the left.

anyone that doesn't understand why I'm capitalizing the words BALANCE and MASS needs to GTFO /sci/

I swear this place should have mandatory IP trips so we can weed out the trolls and idiots and actually come to some fucking conclusions.

Anonymous Mon Jun 24 09:31:41 2019 No.10751307

>>10750678
>>10750893
>>10750983
A buoyant force is still exerted between the steel ball and the water regardless of the string holding it up. Just hold a piece of silverware and lower it partway into a cup of water, you'll feel it get noticeably lighter.

On the left, the buoyant action-reaction pair between the ping pong ball and water results in no net force between either body due to the string connection. On the right, the buoyant action reaction pair results in an upward force on the steel ball and a downward force on the vessel. This is just Newton's third law.

>>	Anonymous Mon Jun 24 09:40:36 2019 No.10751335 >>10751307 Actually silverware is too dense to notice much. Instead take a pen or some other object that just barely sinks in water, then hold it above mostly submerged.

>>	Anonymous Mon Jun 24 09:44:23 2019 No.10751344 >>10750523 It's not small. It's as much "weight" as a ball of water the same size as the steel ball. Anyway it tips right and if you say otherwise you're a goddamn brainlet.

>>	Anonymous Mon Jun 24 10:15:55 2019 No.10751453 t. brainlets https://www.youtube.com/watch?v=stRPiifxQnM

Anonymous Mon Jun 24 12:09:03 2019 No.10751767

>>10749531
Mass on left = water + ping pong ball

Mass on right = water + water displaced by steel ball

The water displaced by the steel ball is heavier than the ping pong ball since thre ping pong ball floats. This the answer is that the right side will fall.

>>	Anonymous Mon Jun 24 12:10:41 2019 No.10751771 >>10749531 Can't someone just make a youtube video about this already

>>	Anonymous Mon Jun 24 12:18:58 2019 No.10751796 >>10751771 Look 2 posts above you

>>	Anonymous Mon Jun 24 19:28:25 2019 No.10752985 This thread is proof that /sci/ is full of idiots. It tips right and anyone who said otherwise should be banned from posting.

>>	this is a shitpost and the act(...) Mon Jun 24 19:32:35 2019 No.10752995 right cuz steel is heavier than plastic DUH retarts

>>	Anonymous Mon Jun 24 19:35:45 2019 No.10753000 >>10751771 see >>10749673 >>10749754 >>10751453

Anonymous Mon Jun 24 19:40:40 2019 No.10753011

>>10751307
This means that the act of submerging the steel ball into the water could cause the scale to tip in that direction, but if the scale is held level by force until the steel ball is fully submerged and at a standstill, buoyancy will no longer apply

Anonymous Mon Jun 24 21:00:11 2019 No.10753242

>>10753011
This isn't true. If you don't have a scale on you, do this with a pen in a cup of water. It feels lighter due to buoyancy, meaning a downward force equal to the weight of water the pen displaces MUST be exerted downwards on the vessel. Check the Veritasium video that got posted if you still don't believe me.

>>	Anonymous Mon Jun 24 22:18:41 2019 No.10753388 >>10749608 This. >>10749662 It is but it does not work like you think it does.

Anonymous Tue Jun 25 04:12:11 2019 No.10754581
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>>10749531
>All of /sci/ doesn't know how to draw free body diagrams

i really need to find a new science board.
the total force on the right is the gravitational force on the glass and water + the force of buoyancy, both downwards.
The force on the left is the gravitational force on the glass, water and pingpong ball. Therefore it tips to the right

Anonymous Tue Jun 25 04:31:29 2019 No.10754631

On the right, the "weight" being felt is the buoyant force exerted by the water upon the ball. (The string isn't feeling the full weight of the ball, since there is some bouyant force)

On the left the system is stable, so we only consider the mass of the water + the mass of the air in the ball + the mass of the ball.

So if the bouyant force on an object that size outweighs the mass of a ping pong ball + the air inside, the object will tip right. And since we know this is true (because a ping pong ball floats) we know it will tip right

Anonymous Tue Jun 25 05:38:43 2019 No.10754750

>>10749531
The scale will not tip. The steel ball is pressing down on the water below it and up on the water above it. Since there is more water below it, it is being pushed up more from the bottom and will eventually be ejected by the water. The ping pong ball and string stop this from happening by inducing the same effect and also by having some weight themselves.

>>	Anonymous Tue Jun 25 14:53:08 2019 No.10755873 >>10749608 There is a hydro-static load on the steel ball, exerting tension on the string.

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