/sci/ - Science & Math

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Anonymous Thu Mar 28 00:56:19 2019 No.10503140 [Reply] [Original]

a circle is x^2 + y^2 < r^2
a hyperbola is a x^2 - y^2 < r^2
can you do an imaginary circle x^i2 + y^i2 < r^i2

>>	Anonymous Thu Mar 28 00:58:34 2019 No.10503144 >>10503140 Try it and get back to me

>>	Anonymous Thu Mar 28 01:02:36 2019 No.10503151 >>10503140 You can’t have a “<“ between complex numbers you fucking faggot

>>	Anonymous Thu Mar 28 01:09:31 2019 No.10503163 >>10503151 i<2i

>>	Anonymous Thu Mar 28 01:44:26 2019 No.10503212 >>10503163 You can't do that.

Anonymous Thu Mar 28 02:25:16 2019 No.10503265

>>10503163
C is not a fully ordered set. You can consider induced order on its subspaces like R or Rez=0, or a lexicographical order, but it's insufficient to just write an inequality sign.

I'd advise you to read about projective spaces and elliptic curves in RC2.

>>	Anonymous Thu Mar 28 02:38:31 2019 No.10503289 >>10503265 The fuck is fully ordered? You mean totally ordered?

>>	Anonymous Thu Mar 28 02:43:11 2019 No.10503293 >>10503265 Your an retard, C has perfectly valid orderings as a set, the problem is C is not an ordered field. It's different

>>	Anonymous Thu Mar 28 02:43:23 2019 No.10503294 >>10503140 abs(z) < r

>>	Anonymous Thu Mar 28 11:03:45 2019 No.10503981 >>10503293 >C has perfectly valid orderings as a set such as...?

>>	Anonymous Thu Mar 28 11:07:32 2019 No.10503988 >>10503140 That curve looks kinda hot. She single?

>>	Anonymous Thu Mar 28 11:11:50 2019 No.10503999 File: 35 KB, 500x667, 1465389673721.jpg [View same] [iqdb] [saucenao] [google] >>10503988 waifus are always single.

>>	Anonymous Thu Mar 28 11:16:53 2019 No.10504010 >>10503981 Every set has a well ordering, brainlet

>>	Anonymous Thu Mar 28 12:10:42 2019 No.10504131 >>10504010 >non-answer color me surprised

>>	Anonymous Thu Mar 28 12:25:07 2019 No.10504167 >>10503981 Lexicographic ordering is a total ordering on C.

>>	Anonymous Thu Mar 28 12:37:05 2019 No.10504185 >>10503981 He is just saying that you can total order C as long as you don't constrain the order to be compatible with the ring structure.

>>	Anonymous Thu Mar 28 12:40:39 2019 No.10504187 >>10503988 Don't think so, I see a penis incoming from the origin

>>	Anonymous Thu Mar 28 12:49:35 2019 No.10504203 >>10504010 Nope, the complex numbers do NOT have a natural ordering. If you disagree, tell me, with proof, how 0 and i should be ordered in relation to each other.

>>	Anonymous Thu Mar 28 12:56:24 2019 No.10504215 >>10504203 Shut the fuck up you dumb nigger

>>	Anonymous Thu Mar 28 13:07:04 2019 No.10504235 >>10504203 I don't know what a natural ordering is, I was only talking about well ordering and total ordering

>>	Anonymous Thu Mar 28 13:17:10 2019 No.10504258 >>10504010 Based Axiom of Choice anon

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