/sci/ - Science & Math

>>10408026
If the sequence ends, it isn't equal to 1.

>>10408026
0.999 ... 999 ≠ 1
0.999 ... = 1

>>10408026
0.999 ... 999 = 0.9... = 1
0.999 ... 998 = 0.9... = 1

>>10408056
>0.999 ... 999 = 0.9...
>0.999 ... 998 = 0.9...
But that's wrong you fucking idiot.

>>10408060
0.1 = 10^-1
0.01 = 10^-2
0.001 = 10^-3
:
0.0...1 = 10^-inf =0

anything after '...' is zero

>>10408067
>anything after '...' is zero
Then why is there a 1 after the ...?

>>10408071
why not?

>>10408076
Because if you know how the sequence ends, it's not infinite.

>>10408092
we don't know, so what?
1*10^-inf=0
2*10^-inf=0
3*10^-inf=0
4*10^-inf=0
5*10^-inf=0
6*10^-inf=0
7*10^-inf=0
8*10^-inf=0
9*10^-inf=0
0*10^-inf=0

>>10408182
>when you absolutely, positively have to convince every motherfucker in the room

Hey, I only now got that reference after watching the film
Feels good

>>10408182

To understand what's happening to the numbers after the decimal when you multiply the number by 10, suppose it was 0.99 instead.

x=0.99
10x=9.9 <--- That's 9.90, not 9.99

Even though both 9.999... and 0.999... stretch to infinity, the numbers after the decimal in 9.999... are still smaller because there are different orders of infinity.

The irrational numbers between integers are a higher order of infinity than the integers themselves, for example.

>>10408989
>Even though both 9.999... and 0.999... stretch to infinity, the numbers after the decimal in 9.999... are still smaller because there are different orders of infinity.
But that is wrong.

>>10409040

Nice explanation.

>>10408182
None of those are proofs retard.

>>10409395
I explained it earlier >>10408092

>>10408989
>suppose it was 0.99
"let's pretend infinite is finite"

retard

>>10409408
They're all correct retard.