/sci/ - Science & Math

[Anonymous No.10374391]

90% of people will get this wrong.

[Anonymous No.10374407]

17

[Anonymous No.10374414]

>>10374407

explain your answers otherwise the post is worthless

[Anonymous No.10374419]

26

[Anonymous No.10374421]

>>10374414
>t. high school teacher

[Anonymous No.10374422]

14

[Anonymous No.10374428]

>>10374419
Every black dot on the caterpillar is 1 and every flower is 2.
The clock is 6 or 5 depending on the hour.

[Anonymous No.10374433]

>>10374391
54

[Anonymous No.10374439]

>>10374391
Fuck this shit, I always miss some details

[Anonymous No.10374444]

>>10374391
14

[Anonymous No.10374447]

>>10374419
this

[Anonymous No.10374450]

>>10374391
54

[Anonymous No.10374463]

>>10374391
45

[Anonymous No.10374477]

>>10374391
27
the snake has one segment more than the others but lost it's head thingy, so it's still a 7. the rose is doubled: 4. the tachometer is on 5 instead on 6 thus it gets a 5.

7+4*5=27

[Anonymous No.10374492]

>>10374477
Each segment is 1 and the thing on his head is a flower (which is 2).
So it should be 6+4*5=26

[Anonymous No.10374511]

>>10374492
i thought about that but the low res + low iq got me.

[Anonymous No.10374515]

>>10374391
[math] \displaystyle
\left \{ \begin{matrix}
(x+y)+(x+y)+(x+y) &= 21 & \Leftrightarrow (x+y)=7 \\
z+z+(x+y) &= 19 & \Leftrightarrow z=6 \\
y+z+(x+y) &= 15 & \Leftrightarrow y=2 \Rightarrow x=5
\end{matrix} \right.
\\
x+2y \cdot z = 5+4 \cdot 6 = 29
[/math]

[Anonymous No.10374528]

[math] \displaystyle
\left \{ \begin{matrix}
(x+y)+(x+y)+(x+y) &= 21 & \Leftrightarrow (x+y)=7 \\
z+z+(x+y) &= 19 & \Leftrightarrow z=6 \\
y+z+(x+y) &= 15 & \Leftrightarrow y=2 \Rightarrow x=5
\end{matrix} \right.
\\
(x+1)+2y \cdot (z-1) = 6+4 \cdot 5 = 26
[/math]

[Anonymous No.10374553]

Are those really meant to be two flowers on top of each other, or just one flower that is shaped differently? There is also no 100% way to be sure to know that the value of the clock is 6, or if just the clock itself represents the value 6; meaning the watch hands in the last equation being 5 would not change the value of the clock. It is likely that the person who made this had the watch hand value in mind but there is no way to know for sure because the first time we see a different value is the one we're supposed to solve.
tl;dr there is no definitive answer

[Anonymous No.10374593]

7+7+7 = 21
6+6+7 = 19
2+6+7 = 15

7+2*6
Order of operations
7+(2*6)
7+(12) = 19
Am I honestly the best at simple math on /sci/? I haven't been in formal education for 2 decades.

[Anonymous No.10374598]

>>10374593
Anon...
I...
Try looking harder, the caterpillar on the bottom doesn't have a flower on its head, there's 2 flowers and the clock doesn't display the same hour

[Anonymous No.10374662]

The flower on the last row ruins the whole thing. The author's inability to draw (or cut and paste) reasonably well shouldn't ruin things but it does. Redraw the flower illustration on the last line.

[Anonymous No.10374664]

>>10374598
The last caterpillar also has more segments than on the other lines.

[Anonymous No.10374688]

>>10374598
Then it’s unsolvable, since you can’t assume that flower on top of flower = 2 flower, no more than you can assume w = 2v.

[Anonymous No.10374858]

>>10374391
>look its one of those pics where some symbol is subtly stacked at the end
>haha got you

[Anonymous No.10374871]

>>10374422
>>10374444
this

(5+2)+(5+2)+(5+2)=21
6+6+(5+2)=19
2+6+(5+2)=15
5+(2+2)+5=14

[Anonymous No.10374876]

>>10374688
v^2

[Anonymous No.10374877]

>>10374871
oh wait i missed that the last caterpillar has six segments

i change my answer to 15

[Anonymous No.10374881]

>>10374688
it is solvable if you go with the simplest solution, i.e. each segment corresponds to 1

[Anonymous No.10374890]

7+7+7=21
6+6+7=19
2+6+7=15
7+1-2+(2*2)*5=26

[Anonymous No.10374897]

>>10374877
fuck i'm a retard. also missed the multiplication symbol

26 it is (until next time)

[Anonymous No.10374951]

>>10374463
/thread.
The other answers are the result of trickery. The little flower on the head is dishonest and intentionally designed to mess someone up. It's like the math teachers who would have rather simple calculus and algebra problems with extremely pedantic arithmetic in hopes of a student making a mistake or running out of time to complete.

[Anonymous No.10374955]

>>10374433
Meant to quote this one.

[Anonymous No.10374956]

>>10374951

[Anonymous No.10374968]

>>10374391
7+7+7=21
6+6+7=19
2+6+7=15
5+4×5=25

[Anonymous No.10374990]

7

[Anonymous No.10375010]

>>10374391

It's a bullshit question
3A=21, A=7
2B+A=19, B=6
C+B+A=15, C=2
D+E+F=?, Not enough information given. Wow OP is so smart.

[Anonymous No.10375079]

>>10374956
Hello http://reddit.com!

[Anonymous No.10375105]

>>10375079
you sure sound cock-sure

[Anonymous No.10375198]

25

[Anonymous No.10375271]

>>10374391

Each dot on the bug represents +1. The flower represents +2. The clock is based off the hour.

6 + (2 * 5) = 16

[Anonymous No.10375279]

>>10375271

Although it'd be 26 if there is a flower "hidden" behind the other flower. Shitty picture quality makes it unnecessarily misleading.

[Anonymous No.10375330]

16. Three times the faggot equals 21. One fagget is also 7. The cock is of course 6 each cuz 2 cocks + ond faggot equels 19 and time is also 6. A clock less but + an flower equals 15, also is flower 2. The bottom faggot has one limb more and no flower so he's 7+1-2=6. 6 + Flower × cock at 5 (6-1=5) = 16

[Anonymous No.10375336]

>>10374890
>2*2
Its 2+2 u feget

[Anonymous No.10375340]

>>10374477
>The snake

[Anonymous No.10375351]

>>10375010
Maybe if your not smart enogh and you're brain doesn't work. R*tard.

[Anonymous No.10375359]

>>10375105
Must mean I'm an expert.

[Anonymous No.10375364]

>>10374391
50

[Anonymous No.10375459]

>>10375351
What's the answer then lol

[Anonymous No.10375506]

>>10374414
>show your work

[Anonymous No.10375622]

>>10374477
>the snake

[Anonymous No.10375643]

>>10374391
19
>>10374414
3(caterpillar) = 21
(caterpillar) = 7

2(clock)+7 = 19
(clock) = 6

(flower)+6+7 = 15
(flower) = 2

7+2*6 = 19

This is really underhanded btw, the main reason most people probably get this wrong has nothing to do with them being dumb. They just miss the multiplication symbol at the end.

[Anonymous No.10376168]

>>10374391

A butterfly.

[Anonymous No.10376173]

15. Caterpillar at bottom didn't have a flower. Clock is at 5 not 6. Two flowers also (2 each).

[Anonymous No.10376326]

>>10375359
not without a correct answer, honey

[Anonymous No.10376330]

>>10375459
>>10374528

[Anonymous No.10376350]

>>10374391
19

[Anonymous No.10376405]

>>10375643

[Anonymous No.10376424]

>>10374391
25

[Anonymous No.10376426]

>>10376424
fuck this shit, extra segment, answer is 26

[Anonymous No.10376815]

>>10374956
Dunning and Kruger suffered from the D-K effect.

[Anonymous No.10377763]

>>10374391
caterpillar = 7
clock@6 = 6
flower = 2

bottom:
(caterpillar-flower) + (double flower x clock@5)
= 5 + 4x5 = 25

[Anonymous No.10377769]

>>10377763
oops, caterpillar has extra leg, so 26

[Anonymous No.10377774]

>>10374391
108

[Anonymous No.10377786]

19

[Anonymous No.10377820]

28

[Anonymous No.10377839]

26 caterpillar is missing flower on bottom but has extra tail so = 6 2 flowers = 4 clock = 5 so total is 26 ez

[Anonymous No.10377941]

>>10374477
>the snake

[Anonymous No.10377960]

>>10374391
The bottom caterpillar is longer. How do you figure out it's value?

[Anonymous No.10377987]

Every caterpillar has at least 7 limbs not shown therefore we cannot see if they have any watches on and the problem is unsolveable. Q.E.D.

[Anonymous No.10378046]

>>10377820
Looking closer at the detail I am coming to 26 not 28.

[Anonymous No.10378105]

>>10374391
The 3 caterpillars at the top are identical, they each have 5 dots and 1 flower.
3 Identical caterpillars summed up equals 21.
21/3=7
The caterpillars each equal 7.
Another caterpillar, identical to the previous ones, plus two identical clocks equals 19.
19-7=12
12/2=6
The clocks each equal 6.
Since each clock's hour hand is at 6, we can infer that the value of clock is equal to the number pointed at by its hour hand.
1 Flower plus another identical clock plus another identical caterpillar equals 15.
15-7=8
8-6=2
Therefore, a flower equals 2.
Since all previous caterpillars were worth 7, and had 1 flower, and 5 dots, we can infer that a caterpillar without a flower would be equal to the number of dots on its body.
Therefore, a caterpillar with 6 dots would be equal to 6.
2 flowers stacked one on top of the other would be equal to 4.
A clock with the hour hand pointed to 5 would be equal to 5.
6+4+5=15
15 is the correct answer.
Your are all braindead faggots.

[Anonymous No.10378137]

>>10378105
this has to be bait.

[Anonymous No.10378141]

>>10374428
wrong, the clock is the gcd of its hands.
so gcd( 12, 6, 48 seconds) = 6
but gcd (12,5,48) = 1.
Therefore 6 + 4 x 1 = 10
QED

[Anonymous No.10378143]

>>10378141
BASED

[Anonymous No.10378152]

>>10374391
if the last three characters are represented in the first three equations, then 19 because 7+6*2 = 19

[Anonymous No.10378199]

1)3x+3y=21 meaning x+y=7
2)2z+x+y means 2z+7=19 therefore z=6
3)x+z+x+y means x+6+7=15 therefore x=2 creating 2+y=7 so y=5
4)y+x(z) means 5+2(6) which is 17

17 is the objective answer and all other ones come from objective brainlets

[Anonymous No.10378206]

>>10378199
*note:there's no where in the problem that says the time on clock is what determines what variable z is

[Anonymous No.10378220]

>>10378206
right, its determined via the gcd of its arms.

[Anonymous No.10378233]

>>10374428
>>10378141
>these people think the value of a clock varies based upon time of day

[Anonymous No.10378234]

>>10378220
We dont know though. OP's pic forgot to list which variables equal what and how many there are. Therefore the person is free to choose any answer they deem reasonable

[Anonymous No.10378291]

>>10374391
95% of people will get this wrong

[Anonymous No.10378332]

>>10378291
delta-Y is not impressive

[Anonymous No.10378472]

>>10374391
15, you're all brainlets

[Anonymous No.10378493]

>>10378472

[Anonymous No.10378516]

>>10378472
You missed the multiplication symbol, brainlet.

[Anonymous No.10378519]

>>10378291
Just use the formulas

[Anonymous No.10378556]

>>10374391
>HURRRRR BUT I HAVEN'T TOLD YOU THE RELATION BETWEEN HOUR SHOWN AND CLOCK VALUE

[Anonymous No.10378673]

>>10374433
wrong

[Anonymous No.10378689]

>>10378233
> values are fixed throughout time
pleb

[Anonymous No.10378691]

>>10378234
OP ommited it because the in the given context its obvious that we are concerned with the gcd.

[Anonymous No.10378781]

>>10378691
This

[Anonymous No.10379135]

>>10374391
19 with BIDMAS
54 with left-to-right
Fuck your intentionally ambiguous bullshit. I hope /sci/ stops responding to these threads.

[Anonymous No.10379218]

>>10378472
I think you missed something pal.

[Anonymous No.10379271]

>>10374391
7+7+7=21
6+6+7=19
2+6+7=15

7+2*6=19
You do multiplication first tard-o's

[Anonymous No.10379274]

>>10378689
If they were calendars you'd have a point.

[Anonymous No.10379611]

>>10378691
>its obvious
OP needs to format his questions properly. List givens, which variables I'm using, what they equal context of the problem and what I am solving for

This is a 18+ science/math board. Not elementary school

[Anonymous No.10379699]

7 + 8 x 5 = 47
(two flowers)

[Anonymous No.10380378]

>>10374391
either 19
because 7+2*6
or its
5+4*5=25
the worm without a flower is a worm worth 7-2=5
the flower appears to be double in the last one. 2+2=4 And all the other clocks point at six and have a value of six but the last clock points to 5 and my guess is its worth 5.

am i smart now?

[Anonymous No.10380402]

caterpillar = 7
clock = 6
flower = 3
redpilled, autists

[Anonymous No.10380403]

>>10374391
16, now I will read the thread.

>>10374414
>explain your answers otherwise the post is worthless
Top to bottom:
1. Each segment with the black dot is 1 and the flower on the head 2; (5+2)*3
2. 6 o'clock + 6 + 7
3. 2 flower + 6 o'clock + 7
4. 6 segments +( 2 flower * 5 o'clock )
Its a good idea to explain btw, hopefully I'm not a brainlet about this.

[Anonymous No.10380430]

>>10380403 (continued)
Or its 26 because that may possibly be two flowers on the bottom row. Its hard to tell with such a shit quality picture which OP should receive a temporary ban for trolling with it.

[Anonymous No.10380442]

>>10374391
https://youtu.be/k9hDi-085lU

[Anonymous No.10380447]

Image search reveals op is a redditfag.