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/sci/ - Science & Math

File: 43 KB, 500x281, heh.jpg [View same] [iqdb] [saucenao] [google]

Anonymous Tue Dec 25 08:21:07 2018 No.10241736 [Reply] [Original]

Prove that 2π>6 without using a single word or mathematical symbol.

If you can't, you're officially a brainlet

>>	Anonymous Tue Dec 25 08:24:33 2018 No.10241741 File: 10 KB, 500x500, circle.png [View same] [iqdb] [saucenao] [google] >>10241736

>>	Anonymous Tue Dec 25 08:26:20 2018 No.10241744 >>10241741 yes and? this proves nothing so far

>>	Anonymous Tue Dec 25 08:26:31 2018 No.10241746 File: 3 KB, 226x217, 2pi vs 6.png [View same] [iqdb] [saucenao] [google]

>>	Anonymous Tue Dec 25 08:29:50 2018 No.10241749 >>10241746 can someone explain this to me? brainlet here

>>	Anonymous Tue Dec 25 08:30:34 2018 No.10241751 >>10241744 Brainlet

>>	Anonymous Tue Dec 25 08:46:56 2018 No.10241764 >>10241749 2pi is the circumference a circle and the hexagon has 6 sides

>>	Anonymous Tue Dec 25 08:48:24 2018 No.10241766 >>10241746 OP BTFO

Anonymous Tue Dec 25 08:49:29 2018 No.10241768

>>10241749
if you spread out both figures into a straight line, the perimeter of the hexagon will be smaller than the circle's. since he circle is based on the hexagon, the perimeter of the circle is 2piR, the perimeter of the hexagon is 6R. the radius cancels out, so 2pi is greater than 6

>>	Anonymous Tue Dec 25 08:54:46 2018 No.10241777 File: 7 KB, 244x243, 2pi vs 8.png [View same] [iqdb] [saucenao] [google] >>10241746

>>	Anonymous Tue Dec 25 08:57:52 2018 No.10241783 >>10241777 You can't fit a regular octagon with a sidelength of 1 into a unit circle.

>>	Anonymous Tue Dec 25 09:00:00 2018 No.10241790 >>10241783 My point was that the hexagon picture doesn't prove that you can fit a regular hexagon with a sidelength of 1 into a unit circle

>>	Anonymous Tue Dec 25 09:02:47 2018 No.10241797 File: 94 KB, 850x531, __patchouli_knowledge_and_remilia_scarlet_touhou_drawn_by_terimayo__sample-ad96284c916a2e5c6b26afd100f16342.jpg [View same] [iqdb] [saucenao] [google] >>10241790 Yeah, but if you put all the circles the image becomes a huge mess.

>>	Anonymous Tue Dec 25 10:26:53 2018 No.10241872 >>10241746 REKT

>>	Anonymous Tue Dec 25 10:34:39 2018 No.10241880 File: 193 KB, 870x260, 6.gif [View same] [iqdb] [saucenao] [google] >>10241736

>>	Anonymous Tue Dec 25 10:35:54 2018 No.10241881 >>10241880 ding ding ding

>>	Anonymous Tue Dec 25 10:43:58 2018 No.10241890 >>10241736 Please kill yourself

>>	Anonymous Tue Dec 25 10:52:34 2018 No.10241899 >>10241880 way too complicated, see the one with the hexagon >>10241890 brainlet

>>	Anonymous Tue Dec 25 10:54:00 2018 No.10241900 >>10241880 >>10241881 How is that a proof? It just asserts that 2pi > 6. There's no way to make sure that the animation is correct

>>	Anonymous Tue Dec 25 10:56:30 2018 No.10241906 >>10241900 >There's no way to make sure that the animation is correct What does this even mean. Either you accept this sort of graphical "proof", or there is no proof of this sort at all.

>>	Anonymous Tue Dec 25 10:57:19 2018 No.10241908 >>10241906 It means that gif doesn't prove shit

>>	Anonymous Tue Dec 25 10:59:34 2018 No.10241912 File: 164 KB, 1500x1000, IMG_20181010_162504.jpg [View same] [iqdb] [saucenao] [google] >>10241881

>>	Anonymous Tue Dec 25 11:00:47 2018 No.10241914 File: 38 KB, 960x640, 1505195660127.jpg [View same] [iqdb] [saucenao] [google] >>10241908 Nothing really proves anything.

>>	Anonymous Tue Dec 25 11:01:45 2018 No.10241915 >>10241906 >>10241908 To add, I think graphical proofs are possible, but that gif just asserts that the circle has >6 circumference. Adding a rolling animation doesn't make it a proof

>>	Anonymous Tue Dec 25 11:05:49 2018 No.10241919 File: 22 KB, 187x255, Pi.jpg [View same] [iqdb] [saucenao] [google]

>>	Anonymous Tue Dec 25 12:04:18 2018 No.10242000 >>10241915 You gotta assume some geometric definition of pi to allow for a graphical proof. So what's the one you'll grant here?

>>	Anonymous Tue Dec 25 12:56:13 2018 No.10242094 File: 1.66 MB, 3264x1836, 20181225_155638.jpg [View same] [iqdb] [saucenao] [google] >>10241797 >get home >no one has done it yet

>>	Anonymous Tue Dec 25 12:57:39 2018 No.10242096 >>10242094 anon, I... >>10241746

>>	Anonymous Tue Dec 25 12:57:55 2018 No.10242097 >>10241746 HOLY FUCKING BASED

>>	Anonymous Tue Dec 25 12:58:58 2018 No.10242101 >>10242094 >he needs circles to see that the hexagonal side lengths are equal to the radius it's obvious, anon

>>	Anonymous Tue Dec 25 13:00:10 2018 No.10242107 >>10242096 >>10242101 >what is context

>>	Anonymous Tue Dec 25 13:05:42 2018 No.10242115 File: 4 KB, 87x85, a.png [View same] [iqdb] [saucenao] [google]

>>	Anonymous Tue Dec 25 13:07:29 2018 No.10242120 >>10242094 We're too busy with nontrivial problems but you're right only engineers could be smug about these elementary questions

>>	Anonymous Tue Dec 25 13:14:53 2018 No.10242132 >>10242120 >smug about elementary questions >op literally states you're a brainlet if you can't do it

>>	Anonymous Tue Dec 25 13:43:52 2018 No.10242173 >>10241768 how do you know the perimeter of the hexagon is 6R?

>>	Anonymous Tue Dec 25 13:47:43 2018 No.10242182 >>10242094 this is the only correct answer so far

>>	Anonymous Tue Dec 25 13:50:54 2018 No.10242187 File: 33 KB, 408x406, duhhhduhhh.png [View same] [iqdb] [saucenao] [google] >>10242173 How do you not know that? It's just a bunch of equilateral triangles. lmao.

>>	Anonymous Tue Dec 25 13:51:09 2018 No.10242189 >>10242096 No. Yours doesn't prove you can fit a hexagon all the sides of which are of length 1.

>>	Anonymous Tue Dec 25 13:53:25 2018 No.10242192 >>10242187 Picture doesn't show that triangles are equilateral.

>>	Anonymous Tue Dec 25 13:54:26 2018 No.10242195 >>10242189 this btfos you >>10241777

>>	Anonymous Tue Dec 25 13:57:30 2018 No.10242198 >>10241736 The proof is trivial.

>>	Anonymous Tue Dec 25 13:58:24 2018 No.10242201 File: 36 KB, 1000x864, scale-clipart-1.png [View same] [iqdb] [saucenao] [google]

>>	Anonymous Tue Dec 25 14:03:52 2018 No.10242215 File: 5 KB, 1059x612, penis.png [View same] [iqdb] [saucenao] [google]

>>	Anonymous Tue Dec 25 15:26:02 2018 No.10242365 >>10241777 Side length isn't equal to radius in that picture, retract your claims of btfo.

>>	Anonymous Tue Dec 25 15:26:24 2018 No.10242367 >>10242201 based

>>	Anonymous Tue Dec 25 15:28:53 2018 No.10242373 File: 14 KB, 364x402, 1536608802783.png [View same] [iqdb] [saucenao] [google] Engineer undergrad comin through this counts because I only used words and wolfram did the rest.

>>	Anonymous Tue Dec 25 15:37:34 2018 No.10242392 >>10242373 Based and wolframpilled

>>	Anonymous Tue Dec 25 15:39:34 2018 No.10242396 >>10242373 If Wolfram tells you 2+2=5, will you believe it?

>>	Anonymous Tue Dec 25 15:40:57 2018 No.10242400 File: 15 KB, 413x413, 1523435137776.png [View same] [iqdb] [saucenao] [google] >>10242396 No because it's wrong, and wolfram doesn't do that anyways.

>>	Anonymous Tue Dec 25 15:46:21 2018 No.10242411 >>10242182 >>10242094 doesn't prove anything, sketches aren't proof

>>	Anonymous Tue Dec 25 15:50:59 2018 No.10242422 >>10242396 No. I don't believe wolfram would tell me 2+2=5

>>	Anonymous Tue Dec 25 16:14:07 2018 No.10242501 File: 124 KB, 472x455, 1540248633492.png [View same] [iqdb] [saucenao] [google] >>10241736 for every circle 2piR = C so for 2pi to equal c you need 2pi equal c/R so you need pi=c/r/2 or 2c/r=pi or radius equals 1/2pi *rad it's impossible nonsense

>>	Anonymous Tue Dec 25 16:17:32 2018 No.10242510 >>10241736 i just figured it out godamnit 2*3.14(etc) > 6 you nigger

>>	Anonymous Tue Dec 25 16:25:25 2018 No.10242531 File: 43 KB, 355x340, ck_56ec1aa5a2696.png [View same] [iqdb] [saucenao] [google] >>10241736 >>10241746 >>10242115

Anonymous Tue Dec 25 16:31:17 2018 No.10242549 [DELETED]

>>10241749

Explaining my post :>>10242531

Each triangle has area R2/2
6 triangles have area 3R2
the circle has area πR2

In >>10242531's pic
we can notice that
πR2 > 3R2
i.e the circle is larger than the 6 triangles

dividing by R2 on both sides
π > 3

multiplying by 2 on both sides:
2π > 6

>>10242531 proves without using words.

>>	Anonymous Tue Dec 25 16:45:21 2018 No.10242596 File: 45 KB, 355x600, f.png [View same] [iqdb] [saucenao] [google] >>10242531

>>	Anonymous Tue Dec 25 16:51:33 2018 No.10242608 File: 17 KB, 355x600, g.png [View same] [iqdb] [saucenao] [google] >>10242596

>>	Anonymous Tue Dec 25 16:53:10 2018 No.10242611 >>10242608 holy kek

>>	Anonymous Tue Dec 25 17:05:19 2018 No.10242636 >>10241736 Just measure the fucking circumference, lol.

>>	Anonymous Tue Dec 25 17:34:40 2018 No.10242697 >>10241777 how does one miss the point this badly?

>>	Anonymous Tue Dec 25 17:51:42 2018 No.10242750 >>10241777 Here you proved that 2pi > x > 6, where x is the length of the perimeter of an octagon set in a circle such that the vertices lie on the circle. Which still proves 2pi > 6 I guess, just not as clearly as the hexagon.

>>	Anonymous Tue Dec 25 17:56:19 2018 No.10242767 Define “pi”

>>	Anonymous Tue Dec 25 18:01:32 2018 No.10242779 >>10242767 >econfag spotted god I hate these fucks so much they use pi as a variable sometimes

Anonymous Tue Dec 25 18:19:50 2018 No.10242820

>>10241736
Circles are like pies and so if I draw two next to each other (think balls touching), then they look like (i.e., imply) an infinity symbol, which implies a number greater than six. I've used words to convey this but the circles aren't words or symbols, they just imply all of this indirectly.

Anonymous Tue Dec 25 18:37:14 2018 No.10242855
File: 224 KB, 1000x1353, __remilia_scarlet_touhou_drawn_by_no_kan__dcc84fd870ceaa492872b296f26534ae.jpg [View same] [iqdb] [saucenao] [google]

>>10242779
>"let [math] \pi _t= \frac{P_t}{P_{t-1}} [/math], where [math] P_t [/math] indicates the price level at the period t"
>physicsfags and enginnerfags start having seizures

>>	Anonymous Tue Dec 25 18:56:53 2018 No.10242892 sin(x) < x , set x= pi/6 and you are done lmfao at all the subhuman engineers in this thread

>>	Anonymous Tue Dec 25 18:58:20 2018 No.10242896 >>10242892 Based first grade illiterate poster.

>>	Anonymous Tue Dec 25 18:59:31 2018 No.10242899 >>10242896 implying a hexagon is not a mathematical symbol LMFAO do not reply to me again you fulltime brainlet

>>	Anonymous Tue Dec 25 19:00:50 2018 No.10242901 >>10242899 Based first illiterate reddit spacing poster.

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