/sci/ - Science & Math

cosX-sinX=0.5
(cos-sin)X=0.5
X = 0.5/(cos-sin)

Square both sides
Finish it from there with your identities

>>952383
cant be done as you need a value to put infront of sin and cos

use <span class="math">\cos^2{x}+\sin^2{x}=1 [/spoiler]

>>952398
why would you do that? and also im looking for the value of X

Square both sides
use (cos^2)x + (sin^2)x = 1

i_lost_the_game.jpg

squaring 0.5 gets 0.25 not 1... so it wont work

I'm reporting thread left right and center today. It's good to be the king.

Ok from trig. rules it follows that cos(x)-sin(x)=tan(x)
So we get:
tan(x) = 0.5
x = ~0.46

>>952424
wtf

>>952408
i'm sick of your shit kid
as soon as you read this delete this thread
<span class="math">\cos x-\sin x =\frac{1}{2} [/spoiler]
<span class="math">\cos^2 x+\sin^2 x -2\sin x \cos x=\frac{1}{4} [/spoiler]
<span class="math">1 -(1-\sin(2x))=\frac{1}{4} [/spoiler]
<span class="math"> \sin 2x =\frac{1}{4} [/spoiler]
<span class="math"> x= \frac{\arcsin(.25)}{2} [/spoiler]
<span class="math"> x=0.126340128 [/spoiler]

now gtfo /sci/ and never come back
and to the rest of you don't fucking bump hw threads

ah shit its actually sinX-cosX=0.5

>>952452
this isnt a fuckin HW thread this question came up on an exam i took and the answer was 0.63 the fact that you fail asses cant get it right just shows how smart ya'll are

>>952460
it's the same thing

>>952468
next time ask wolframalpha then
i'm not a fucking calculator

>>952452
AND when you put the answer you got you actually get 1 not 0.5 so you know for a fact you got the wrong answer

>>952470
not really its actually different, whats 7-2 and 2-7? 5 and -5 so different questions means different answers

>don't fucking bump hw threads
I agree.

>>952488
(7-5)^2=(5-7)^2

>>952481
well fuck aint this the science and math? thought i would see how you guys would approach this type of question as i just used f(X)=sin(x)-cos(x) on my calculator and made it do it from 1-100 in steps of 1

>>952488
|7-2| = |2-7|

>>952468
>ya'll

<span class="math"> \cos x - \sin x = {1\over 2}
\sqrt{2} * ({1\over {\sqrt{2}}\cos x - {1\over {\sqrt{2}}\sin x = {1\over 2}
({1\over {\sqrt{2}}\cos x - {1\over {\sqrt{2}}\sin x = {1\over 2\sqrt{2}}
\sin ({\pi\over4}-x)= {1\over 2}
[\math]
there you go[/spoiler]

<span class="math"> \cos x - \sin x = {1\over 2}
\sqrt{2} * ({1\over {\sqrt{2}}\cos x - {1\over {\sqrt{2}}\sin x = {1\over 2}
({1\over {\sqrt{2}}\cos x - {1\over {\sqrt{2}}\sin x = {1\over 2\sqrt{2}}
\sin ({\pi\over4}-x)= {1\over 2}
[/spoiler]
there you go

[TEX] \cos x - \sin x = {1\over 2}
\sqrt{2} * ({1\over {\sqrt{2}}\cos x - {1\over {\sqrt{2}}\sin x = {1\over 2}
({1\over {\sqrt{2}}\cos x - {1\over {\sqrt{2}}\sin x = {1\over 2\sqrt{2}}
\sin ({\pi\over4}-x)= {1\over 2}
[\TEX]
there you go

[tex] \cos x - \sin x = {1\over 2}
\sqrt{2} * ({1\over {\sqrt{2}}\cos x - {1\over {\sqrt{2}}\sin x = {1\over 2}
({1\over {\sqrt{2}}\cos x - {1\over {\sqrt{2}}\sin x = {1\over 2\sqrt{2}}
\sin ({\pi\over4}-x)= {1\over 2}
[/tex]
there you go

<span class="math"> \cos x - \sin x = {1\over 2}
\sqrt{2} * ({1\over {\sqrt{2}}\cos x - {1\over {\sqrt{2}}\sin x = {1\over 2}
({1\over {\sqrt{2}}\cos x - {1\over {\sqrt{2}}\sin x = {1\over 2\sqrt{2}}
\sin ({\pi\over4}-x)= {1\over 2}
<span class="math">
there you go[/spoiler][/spoiler]

>>952592
[m ath] [/math]

<span class="math">
\cos x - \sin x = {1\over 2}
\sqrt{2} * ({1\over {\sqrt{2}}\cos x - {1\over {\sqrt{2}}\sin x = {1\over 2}
({1\over {\sqrt{2}}\cos x - {1\over {\sqrt{2}}\sin x = {1\over 2\sqrt{2}}
\sin ({\pi\over4}-x)= {1\over 2}
[/spoiler]

>>952383
this is my favorite response on /sci/ ever

>>952452

hey bro, you're the closest one to a math literate in this thread so i'll go easy on you...

2sinxcosx = sin2x =/= 1-sin2x. if you make that correction and continue what you did you should get the right answer

>>952616
so it is
i fucked up copying from a website