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/sci/ - Science & Math


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File: 19 KB, 427x382, 24067948_2194179857274464_3536452397110443347_n.png [View same] [iqdb] [saucenao] [google]
9335650 No.9335650 [Reply] [Original]

Thoughts?

>> No.9335658

You should be using absolute values for the equation. That just isn't usually specified because it only matters if you're using imaginary unit lengths for the sides

>> No.9335660

so this is the power of complex numbers...

>> No.9335670

>>9335650
>>9335658

It should be [math]a ^ \dagger a + b ^ \dagger b = c ^ \dagger c[/math]

>> No.9335788

>>9335650
this image is false

clearly the length is real, not imaginary

>> No.9335795

>>9335788
Of course, the square root of -1 isn't real in our number system, so we just use i as a substitute for a real number.

So, in theory, this image is true.

>> No.9335801

>>9335650
i=1
o=√2

>> No.9335803

>>9335795
wrong

>> No.9335809

>>9335801

i = √-1
i^2 = -1
1 + -1 = 0

>> No.9335819

>>9335803
Explain.

>> No.9335829

>>9335809
the length of i is 1.

>> No.9335845

>>9335829

You are literally retarded.

>> No.9335858
File: 53 KB, 403x448, 1509935607777.png [View same] [iqdb] [saucenao] [google]
9335858

>>9335845
i is assumed used as a variable, not an imaginary number, in the example triangle
Of sides 1, 0(zero), i. in this example, the triangle depiction is actually an illusion, and the result is a line with length 1 having the same distance as a line with length i, so i=1

If the triangle sides were instead 1, o(variable), i ; the solution is not 1.

>> No.9335875

>>9335845
But that is literally what the retarded picture says

>> No.9335880
File: 125 KB, 500x358, 1510270439396.png [View same] [iqdb] [saucenao] [google]
9335880

>>9335875
0 and O, my nigger.

>> No.9336203

i2 = 12 + 02
-1 = 1

FALSE!!

>> No.9336211
File: 18 KB, 546x477, special-right-triangles.png [View same] [iqdb] [saucenao] [google]
9336211

>>9335650

>> No.9336216

>>9336203
Deplorable...

>> No.9336566

how do you have a length of zero?

>> No.9336580

>>9335650
you're not using a proper metric. if you want to use imaginary numbers, you need to come up with a new definition of distance that satisfies the definition of a metric.

>> No.9337013

>>9335650
good thread

>> No.9337411

>>9336203
kek

>> No.9337419
File: 172 KB, 1202x216, 1488403366976.png [View same] [iqdb] [saucenao] [google]
9337419

Can we not?