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/sci/ - Science & Math


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7621064 No.7621064[DELETED]  [Reply] [Original]

New stupid questions general thread here.


Old thread here:
>>7612327

>> No.7621066
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7621066

I'm in my first Organic chemistry lab this semester and I've been looking over the msds safety data and I have a question

Is there a tangible and/or meaningful difference between a liquid compound being
"Flammable"
"Highly flammable"
"Combustible"
Having "Flammable liquid and vapor"?

>> No.7621079

>>7621066
take this with a grain of salt as I'm not entirely sure:

>"Flammable"
An open flame will cause it to ignite
>"Highly flammable"
An open flame will cause it to ignite, and it will ignite very easily
>"Combustible"
Enough heat can cause it to catch fire.
>Having "Flammable liquid and vapor"?
The liquid and the vapour can be ignited by an open flame. (think gasoline)

>> No.7621087

>>7621066
>>7621079 here

try this:
http://www.differencebetween.com/difference-between-flammable-and-vs-combustible/
http://www.differencebetween.com/difference-between-flammable-and-highly-flammable/

>> No.7621107

Is there any similarity in the principles of electron clouds of atoms and photon spheres of black holes?
Can a black hole have other orbiting surfaces around it, like a neutrino sphere?

>> No.7621121

if you were to put a giant copper wire around the earth and put a magnet on orbit around said wire , would that generate "infinite" electricity until the magnet fall back on earth ?

>> No.7621134

>>7621121
No

>> No.7621137

What is the proof that 1+1=2?

Google had nothing.

>> No.7621150

>>7621121
The generation of electricity would reduce the kinetic energy of the magnet, causing it to fall faster, so it could not stay in orbit. No perpetual motion machines for you fggt.

>> No.7621164

Reposting
Is biotechnology and biomedical engineering stuff like nanomachines to improve your body?

>> No.7621179

Reposting
Is biotechnology and biomedical engineering stuff like nanomachines to improve your body?

>> No.7621254
File: 6 KB, 327x233, 1445996893582.png [View same] [iqdb] [saucenao] [google]
7621254

I have a simple circuit where
[math] \mathbf{V} = 200\measuredangle{-180^\circ} [/math]
L = 2H
[math] \mathbf{I} = 100\measuredangle{90^\circ} [/math]

I need to find the voltage across the current source, but the current source itself is throwing me off. What are the step I need to take?

>> No.7621276

>>7621137
https://en.m.wikipedia.org/wiki/Peano_axioms

>> No.7621327
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7621327

A quantum mechanical particle in a magnetic field.

If the Coulomb gauge gives that the divergence of A is 0, where does the 2 in the denominator go? Multiple sources say that this is the right answer, but I just can't wrap my head around how it works.

Source of the pic: http://www.tcm.phy.cam.ac.uk/~bds10/aqp/lec5_compressed.pdf

>> No.7621355

>>7621164
No. It's physics mixed with chemestry, programming and electrical engineering. You won't build nanobots.
You will programm stuff.

>> No.7621360

>>7621327

You have to use the product rule. Perhaps it will make more sense if you think of applying the operator to a wave function:

[math]-\frac{q}{2m}(\vec{p} \cdot \vec{A} + \vec{A} \cdot \vec{p}) \, \psi = \frac{q i \hbar}{2m}\Big(\nabla \cdot (\vec{A} \psi) + \vec{A} \cdot \nabla \psi) \Big) [/math]

[math] = \frac{q i \hbar}{2m}\Big((\nabla \cdot \vec{A}) \psi + 2 \vec{A} \cdot \nabla \psi) \Big) [/math]

[math] = \frac{q i \hbar}{2m}\Big(0 \, \psi + 2 \vec{A} \cdot \nabla \psi) \Big) [/math]


[math] = \frac{q i \hbar}{m}(\vec{A} \cdot \nabla) \psi [/math]

>> No.7621365

>>7621254
Suppose both sources separately, then use superposition of sources.

>> No.7621368

>>7621360

Ah, right. Using operators which do not always operate on something does confuse me sometimes. Thanks!

>> No.7621393

>>7621355
Disappointing...
Thanks anyway!

>> No.7621396

>>7621137
http://quod.lib.umich.edu/cgi/t/text/pageviewer-idx?c=umhistmath&cc=umhistmath&idno=aat3201.0001.001&frm=frameset&view=image&seq=401

>> No.7621426

>>7621368
They will always operate on something, so you can always use that technique. It is probably worth getting used to manipulating operators directly though.

>> No.7621466

>>7621107
Can someone please answer this?

>> No.7621469

Is this a stupid question?

>> No.7621523

>>7621469

Yes, because if it were not a stupid question it wouldn't belong here, thus making it quite a stupid question indeed. Its being a stupid question therefore makes it worthy to receive an answer here, which I have just provided.

>> No.7621551

Are the shapes of atomic orbitals the actual shape of the electron cloud? Can the electron cloud be spherical?

>> No.7621612
File: 325 KB, 1280x800, Spherical_Harmonics.png [View same] [iqdb] [saucenao] [google]
7621612

>>7621551

No, the shapes illustrated in books are idealizations that convey some spatial characteristics of the electron cloud density given by [math]|\psi|^2[/math] or are polar plots of the spherical harmonics like pic related. See here for some other visualizations:

https://en.wikipedia.org/wiki/Atomic_orbital
https://en.wikipedia.org/wiki/Spherical_harmonics

In s-states the electron cloud isn't spherical, just spherically symmetric.

>> No.7621614

>>7621064
Is there any real chance of us finding a way to extend our life expectancy past 150 years in our lifetime?

>> No.7621620

If I've shown that not B => not A, is that equivalent to showing that A => B? If so, I can then assume that the latter statement is true, right?

>> No.7621629
File: 90 KB, 604x840, Aubrey_de_Grey.jpg [View same] [iqdb] [saucenao] [google]
7621629

>>7621614

This man thinks so, and he looks twice that age right now!

https://en.wikipedia.org/wiki/Aubrey_de_Grey
https://www.youtube.com/watch?v=T0lvxTm2iLg

>> No.7621639

>>7621620

Yes, that is the contrapositive, which is a logically equivalent statement.

https://en.wikipedia.org/wiki/Contraposition

>> No.7621640

>>7621639
Thanks mate

>> No.7621646

>>7621137
Because of the way addition is defined, 1 + 1 is the same thing as saying the number directly after, or the successor of, 1. 2 is defined as the successor of 1, hence 1 + 1 = 2. My proof implicitly uses the Peano axioms, so read up on those if you're interested.


tl;dr - that's just the way it's defined.

>> No.7621659

Are there any engineers with a B.S degree in engineering that are willing to be interviewed?
I would need your name, university, employment, job title/description, and some answers to basic questions.

If not here, does anyone know a good site/ forum to interview an Engineer?