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/sci/ - Science & Math


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File: 921 KB, 3000x2275, particlephysics.gif [View same] [iqdb] [saucenao] [google]
7212873 No.7212873 [Reply] [Original]

Can someone explain to me why the speeds of sound and light are constants? (within a controlled environment of course)

Why is it that if i'm moving backwards at 100 mph, then project a light forwards, it isnt moving in that direction at the speed of light minus 100mph?

Also is there a time it takes to accelerate to that speed?

What is a good book to read to explain all this sort of stuff? Also interested in learning about matter, antimatter, all aspects of particle physics

>> No.7212877
File: 18 KB, 297x255, 1429358671163.png [View same] [iqdb] [saucenao] [google]
7212877

Speed of sound is not constant like the speed of light.

>Why is it that if i'm moving backwards at 100 mph, then project a light forwards, it isnt moving in that direction at the speed of light minus 100mph?
Because the speed of light is constant no matter what.

>Also is there a time it takes to accelerate to that speed?
Nope.

>What is a good book to read to explain all this sort of stuff? Also interested in learning about matter, antimatter, all aspects of particle physics?
Last volume of Halliday physics must have some Special Relativity in it.

>> No.7212881

>>7212877
>because the speed of light is constant no matter what.
But what is that speed relative too in the vacuum of space where there is no reference point? if i'm moving in one direction at the speed of light, and then project light in the other direction, then in order to move at the speed of light in that direction wouldnt the particles need to be leaving me at twice the speed of light?

sorry if i sound retarded.

>> No.7212883

>Why is it that if i'm moving backwards at 100 mph, then project a light forwards, it isnt moving in that direction at the speed of light minus 100mph?

<span class="math">\displaystyle u = \frac{v + v'}{1+\frac{vv'}{c^2}}[/spoiler]
Now pick v = -100mph and v' = c.
<span class="math">\displaystyle u = \frac{-100 + c}{1+\frac{-100c}{c^2}}[/spoiler]

<span class="math">\displaystyle u = \frac{(-100 + c)c}{c - 100} = c [/spoiler]

>> No.7212885

>>7212877
>that image
Base A = best base.

>> No.7212891

>>7212881
You should just get the equations and do the math. I consider this a work of Lorentz-Poincaret, so you can go for them instead of Einstein of Shekelsberg

>>7212885
I guess that image shows how retarded the whole planet is. We should say base I I I I I I I I I I

>> No.7212907
File: 206 KB, 768x1024, 1429657561889.jpg [View same] [iqdb] [saucenao] [google]
7212907

>>7212883
>>7212891
K.
Cheers

>> No.7212925
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7212925

>>7212883
>using a formula to demonstrate the postulate which was used to derive the formula

>> No.7212928

>>7212925
it's normal to teach most of physics tautologically until far into graduate school, sad but true

>> No.7212951

>>7212928
Not if you're not american...

>> No.7212961

>>7212928
this is why no-one should be surprised when their bachelor in physics doesn't get them job offers