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/sci/ - Science & Math


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7209499 No.7209499 [Reply] [Original]

|-2+3| = ?

>> No.7209502

1
/thread

>> No.7209503

1

>> No.7209506

5 of course

>> No.7209511

>>7209502
>>7209503
These. Absolute value is supposed to be treated like a parenthesis in order of operations.

>> No.7209514

>>7209511
It's still 5, retard.

|-2+3| = |-5| = 5

>> No.7209516

>>7209514
Saged masturb8tr. No one can be this stupid. Not even on /sci/

>> No.7209518

>>7209514
-2+3=-5

>> No.7209521
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7209521

>>7209514

>> No.7209524
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7209524

>>7209514
lol

>> No.7209525

op here
another question
sin^2α = sinα^2 ?

>> No.7209526

It's an absolute function so the | | thingies makes all numbers inside positive. So the -2 becomes a positive 2 meaning 2+3= 5

/thread

>> No.7209529

>>7209499
3-2=5!

why use such a basic concept to b8

>> No.7209533

>>7209526
pls stahp it's not funneeeh

>> No.7209534

>these are the people who give you advice on mathematics

>> No.7209536
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7209536

>>7209526
Stop be such an faggot. These spergs won't react like you think they will. Still using sage in my cooking.

>> No.7209537

>>7209533
>>7209536
You replies exactly how I thought you would, thank you.

>> No.7209540

>>7209537
No anger means no satisfaction. Especially after revealing yourself. Bah, Felicia.

>> No.7209541

>>7209529
5! = 1x2x3x4x5 = 120
fgt

>> No.7209545

>>7209536
>an faggot
kek'd

>> No.7209549

>>7209525
What about it?

>> No.7209553

>>7209549
it's question

>> No.7209561

>>7209540
You mad bro?

>> No.7209577

>>7209553
You're asking if they're equal? They're two ways of writing the same thing. I've seen both used in textbooks.

>> No.7209587

>>7209514
|-5| is undefined, absolute values have to be positive

>> No.7209597

>>7209577
don't you see "?" in my post?

>> No.7209900

This is the biggest troll thread ever.

To clarify |-2+3|=sqrt[ (-2)^2+3^2] = sqrt(13)~3.6

>> No.7209914

>>7209499
1-2+31=30
step it up guys

>> No.7210024

>>7209577
No they are not. sin^2(x) = (sin(x))^2 but sin^2(x) =! sin(x)^2

If you wanted to solve such that sin^2(x) - sin(x)^2 = 0 then that's a different question that I'd have no idea how to solve. Maybe Taylor Series would do it but I don't know. I've never ever had to solve something like that before.

>> No.7210040

>>7210024
solve for x such that*

>> No.7210049

>>7210024
sin(x)^2 absolutely equals (sin(x))^2 get your fucking functional notation right. sin(x^2) is what you are thinking. Jesus fuck what middle school do you attend?

>> No.7210060

>>7210024
So (f(x))^2 != f(x)^2?

>> No.7210065
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7210065

>>7210060
f(x)^2 != f(x^2)

>> No.7210079

>>7210065
Yeah that's the point, who I replied to just said what I was questioning.

>> No.7210089

>>7209502
>>7209503
retards
>>7209514
/thread
christ i'm in middle school and i know this shit, you fuckers are stupid

>> No.7210099 [DELETED] 

>>7210060
>>7210049
It's you're prerogative if you want to omit the extra brackets but it really should be written as f(x)^2 should really be written as (f(x))^2 or else it could be confused as f(x^2). Calculators as well as most people will know what you mean if f(x)^2 = (x^3 + 3x)^2 then f(x) = (x^3 + 3x) but for the trigonometric functions complicate things. sinx^2 could easily be sin(x^2) or sin(x)^2. That's why it's a good idea to put the extra brackets to differentiate between the two.

>> No.7210107 [DELETED] 

>>7210060
>>7210049
It's you're prerogative if you want to omit the extra brackets but f(x)^2 should really be written as (f(x))^2 or else it could be confused as f(x^2). Calculators as well as most people will know what you mean if f(x)^2 = (x^3 + 3x)^2 then f(x) = (x^3 + 3x) but the trigonometric functions complicate things. sinx^2 could easily be sin(x^2) or sin(x)^2. That's why it's a good idea to put the extra brackets to differentiate between the two to distinguish between sin(x^2) and (sinx)^2. sin(x)^2 is just too ambiguous.

>> No.7210110

>>7210060
>>7210049
It's your prerogative if you want to omit the extra brackets but f(x)^2 should really be written as (f(x))^2 or else it could be confused as f(x^2). Calculators as well as most people will know what you mean if f(x)^2 = (x^3 + 3x)^2 then f(x) = (x^3 + 3x) but the trigonometric functions complicate things. sinx^2 could easily be sin(x^2) or sin(x)^2. That's why it's a good idea to put the extra brackets to differentiate between the two to distinguish between sin(x^2) and (sinx)^2. sin(x)^2 is just too ambiguous.

>> No.7210114

>>7209587
lol

>> No.7210119

>>7210107
that's not how it works you aren't supposed to reply with the right answer in a troll thread

>> No.7210121

Seeing that the expression is Riemann integrable you can do backwards analytic continuation across complex integer values to approximate its value as it approaches infinity from the positive side, yielding |-2+3| = Si(x)

>> No.7210463

>>7210110
Yes sinx^2 is ambiguous

Sin(x)^2 isn't

>> No.7210464

>>7210121
>backwords analytic continuation
So just limiting the domain?